What is the difference in the charges on a ballon rubbed in your hair and a glass rod rubbed

Answers

Answer 1

Answer: The balloon steals electrons from your hair, leaving the hair positively charged, and the balloon negatively charged. It causes hair to be apart from each other, because it has the same charge. Glass has a weaker hold on electrons, and silk absorbs the lost electrons.

Related Questions

What is the term used to describe the energy needed to get a reaction started
Cytology is the study of Blank______. Multiple choice question.
A shot-putter throws an 8.00 kg shot at a speed of 10.0 m/s. What is the kinetic energy of the shot?
The magnitudes of the vectors in this diagram are vx/y = 17.94 meters/second and vy/z = 3.46 meters/second. Find vx/z.
when a beam of light passes at an oblique angle into a material of lower optical density, the angle of incidence is ?

A particle with velocity v(t)=1/t−3, in m/s, moves in a straight line. Its initial displacement is known to be s(1)=1, in m. Find the position function s(t).

Answers

Answer:

s(t) = (t1 - t2)* [((1/t1 - 3) + (1/t0 - 3))/2]

Explanation:

We will assume that v(t) is in units of m/s and t (time) is in seconds.

v(t)=1/t−3

At time 0 (initial) the equation tells us the particle has a velocity of

v(t)=1/t−3

v(0)=1/(0)−3

v(0) = - 3 m/s

The particle is moving from right to left (the negative sign) at a rate of 3 m/s.

The position of the particle would be the average velocity times the time traveled.

Distance = Velocity x Time (with Velocity being the average between times t0 and t1)

We'll use s(t) for displacement for time t.

s(t) = v*t

We need the average velocity for the time period t0 to t1.

Let t0 and t1 be the initial and final times in which the measurement takes place.

At time t0 the velocity is = 1/t0 - 3

At time t1 the velocity is = 1/t1 - 3

The displacement is the average velocity between the two points, t0 and t1. This can be written as:

[(1/t1 - 3) + (1/t0 - 3)/\]/2

Displacement: s(t) = (t1 - t2)* [((1/t1 - 3) + (1/t0 - 3))/2]

Solve the problem.The Bay area of California was shaken by an earthquake on October 17, 1989. The epicenter was located at Loma Prieta. The diameter of the earthquake's horizontal waves that shocked the area measured about 120 miles. How many square miles were affected by this earthquake?

Answers

As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
area of a circle =πr*r

d=120
r=120/2r=6060*60=36003600*π=11309.734
11309.734 square miles

A compound microscope that has an eyepiece lens with a magnification of 10X and an objective lens with a magnification of 25X will have a total magnification of __________ times.

Answers

Answer:

Explanation:

total magnification = eyepiece lens x objective lens

TM = 10X x 25X

TM = 250X

Balanced forces acting on an object cause the object to accelerate. true or false

Answers

Balanced forces that is acting on an object will NOT cause the object to accelerate, instead it will cause Static Equilibrium-the object is at rest. For example, a book is on the table and there is a downward force because of the gravity but also there is an upward force from the surface that helps to balance the weight of an object which is called a support force. It happens that the net force of an object is equal to zero, means ALL OF THE FORCE CANCEL OUT! Which leads us to the conclusion that, balanced forces will cause an object to be at rest and not to accelerate.

A piece of a newly synthesized material of mass 25.0 g at 80.0◦C is placed in a calorimeter containing 100.0 g of water at 20.0◦C. If the final temperature of the system is 24.0◦C, what is the specific heat capacity of this new material? 1. 1.20 J/g ◦C 2. 7.46 J/g ◦C 3. 4.76 J/g ◦C 4. 0.30 J/g ◦C 5. 0.84 J/g ◦C

Answers

Answer:

1.Cp₁ = 1.2 J/g.⁰C

Explanation:

For new material:

m₁ = 25 g

T₁ = 80⁰C

specific heat of water = Cp₁

For water :

m₂ = 100 g

T₂ = 20⁰C

The final temperature T=24⁰C

We know that specific heat of water Cp₂ = 4.187 kJ/kg.K

The heat lost new material = Heat gain by Water

m₁ Cp₁ ( T₁ - T ) = m₂ Cp₂ (T- T₂)

25 x Cp₁ (80- 24 ) = 100 x 4.817 (24 - 20 )

Cp₁ x 56 = 4 x 4.187 x 4

$C_(p1)=(4* 4.187* 4)/(56)\ kJ/kg.K$

Cp₁ = 1.19 kJ/kg.K

Cp₁ = 1.2 J/g.⁰C

Calculate the speed of the ball, vo in m/s, just after the launch. A bowling ball of mass m = 1.5 kg is launched from a spring compressed by a distance d = 0.21 m at an angle of θ = 32° measured from the horizontal. It is observed that the ball reaches a maximum height of h = 4.4 m, measured from the initial position of the ball. Let the gravitational potential energy be zero at the initial height of the bowling ball.

Answers

Answer:

$v_0=17.3m/s$

Explanation:

In this problem we have three important moments; the instant in which the ball is released (1), the instant in which the ball starts to fly freely (2) and the instant in which has its maximum height (3). From the conservation of mechanical energy, the total energy in each moment has to be the same. In (1), it is only elastic potential energy; in (2) and (3) are both gravitational potential energy and kinetic energy. Writing this and substituting by known values, we obtain:

$E_1=E_2=E_3\n\nU_e_1=U_g_2+K_2=U_g_3+K_3\n\n(1)/(2)kd^2=mg(d\sin\theta)+(1)/(2)mv_0^2=mgh+(1)/(2)m(v_0\cos\theta)^2$

Since we only care about the velocity $v_0$ , we can keep only the second and third parts of the equation and solve:

$mgd\sin\theta+(1)/(2)mv_0^2=mgh+(1)/(2)mv_0^2\cos^2\theta\n\n(1)/(2)mv_0^2(1-\cos^2\theta)=mg(h-d\sin\theta)\n\nv_0=\sqrt{(2g(h-d\sin\theta))/(1-\cos^2\theta)}\n\nv_0=\sqrt{(2(9.8m/s^2)(4.4m-(0.21m)\sin32\°))/(1-\cos^232\°)}\n\nv_0=17.3m/s$

So, the speed of the ball just after the launch is 17.3m/s.

Other Questions

An blank Used to determine the change of an object

Pete is driving down 7th street. he drives 150 meters in 18 seconds. assuming he does not speed up or slow down what is his speed in meters per second? a. 8.3 m/s b. 0.12 m/s c. 132 m/s d. 2,700 m/s

Which types of electromagnetic wave travels through space the fastest?

A rock is dropped off a cliff and falls the first half of the distance to the ground in t1 seconds. If it falls the second half of the distance in t2 seconds, what is the value of t2/t1? (Ignore air resistance.)