Write the equation of the line that it is parallel to y=2x+1 and passes though the solution of the following systems of equations :3x-2y=10
x+y=5

Answers

Answer 1
Answer:

The required equation of a line is y = 2x - 11

What is the slope of the line?

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.


Here,
The given line,
y = 2x + 1
The slope of the equation is m = 2

Now the point is  required,
3x-2y=10  - - - - - -(1)

x+y=5  
x = 5 - y - - - - -(2)
putting x in equation 1
3(5 - y) - 2y = 10
15 - 3y - 2y = 10
-5y = -5
y = 1
Now
x = 5 - y
x = 5 + 1
x = 6
Points are (6, 1)
Equation of line is given by,
y - 1 = m (x - 6 )
y - 1 = 2 (x - 6 )
y = 2x -12 + 1
y = 2x - 11

Thus, the required equation of line is y = 2x - 11

Learn more about slopes here:
brainly.com/question/3605446

#SPJ2

Answer 2
Answer:

well, keeping in mind that parallel lines have the same exact slope, hmmmmm

\bf y = \stackrel{\stackrel{m}{\downarrow }}{2}x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\n \cline{1-1} \n y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \n\n \cline{1-1} \end{array}

alrite, so we know the slope has to be 2 then hmmm let's check the point it runs through

\bf \begin{cases} 3x-2y=&10\n\n x+y=&5\n \qquad y=&5-x \end{cases} \n\n\n \stackrel{\textit{substituting \underline{y} on the 1st equation}}{3x-2(5-x)=10}\implies 3x-10+2x=10\implies 5x-10=10 \n\n\n 5x=20\implies x=\cfrac{20}{5}\implies \blacktriangleright x = 4 \blacktriangleleft \n\n\n \stackrel{\textit{since we know that}}{y = 5-x}\implies y=5-4\implies \blacktriangleright y = 1 \blacktriangleleft

so, we're really looking for the equation of a line whose slope is 2 and runs through (4,1)

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})~\hspace{10em} \stackrel{slope}{m}\implies 2 \n\n\n \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \n\n\n y-1=2x-8\implies y=2x-7


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Answers

Hello lets solve this! :)
\sf(4)/(9)m = 72\n\n\sf{Multiply~(9)/(4)~on~both~sides~to~isolate~m}\n\n(4)/(9)m * (9)/(4) = 72* (9)/(4)\n\nm = 72* (9)/(4)\n\nm = 18 * 9\n\n\boxed{\bf{m=162}}

Hope I helped! IIf you have any other questions or would like further explanation just let me know!! :)
(4/9)m=72
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m=648/4
m=162

answer. m=162

Elle can buy 2 quarts of milk for $3 or 1 gallon of milk for $3, Which Is The Better Deal.... Because Im not sure..

Answers

1 gallon is equal to 4 quarts. 

So you can either get 2 quarts for $3, or 4 quarts for 3$

1 gallon is the better deal.
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A square garden has a diagonal of 34 ft. Colton wants to put a fence around the entire garden. How much fencing will he need? Round to the nearest foot.

Answers

ok
pythagorean theorem
a and b are legs, c is hypotonuse (diagonal in this problem)
in square, legs are equal
a=b

a^2+b^2=c^2

diagonal is 34
a=b
a^2+a^2=34^2
2a^2=1156
divide both sides by 2
a^2=578
a=17√2

perimiter is 4 time 1 side for square
p=4 times 17√2
P=68√17 feet

aprox 96.1665 feet
Let s be the length of a side. 

By the Pythagorean Theorem (or knowledge of 45-45-90 triangles) we can find the length of a side from the hypotenuse. 
s² + s² = 34² 
2s² = 34² 
2s² = 1156 
s² = 578 

s = √578 
s ≈ 24.04 

There are 4 sides to the square: 
P = 4s 
P ≈ 96.16 

Answer: 
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Answers

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Answers

3kilometers
kilo=100
3kilometers=3000meters

3000 meters=how many times of the track
track=200
3000meters=how many times 200
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Answers

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