A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (2.50 m, 2.50 m) with a velocity of -5.00i hat m/s and an acceleration of -10.0j m/s2. What are the coordinates of the center of the circular path?

Answers

Answer 1

Answer:

Answer:

(2.5,0)

Explanation:

The particle can be described by the following equations:

$x=Rsin(-\omega t)+2.5\ny=Rcos(-\omega t)\n(dx)/(dt)=-\omega Rcos(-\omega t)\n(dy)/(dt)=\omega Rsin(-\omega t)\n(d^2x)/(dt^2)=-\omega^2Rsin(-\omega t)\n(d^2y)/(dt^2)=-\omega^2Rcos(-\omega t)$

For R = 2.5, ω = 2 and t = 0:

$x=2.5\ny=2.5\n\n(dx)/(dt)=-5\n (d^2y)/(dt^2)=-10$

The center of the circle would be at point (2.5,0)

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Answers

This is fairly easy. The earlier view of the solar system (geocentric) was all based on how other planets and the sun were constantly revolving the earth and we were completely stationary. The Heliocentric view has been proved to be accurate, and it is that the sun is stationary and the planets are revolving it. The similarities are that in that time, it was a continued belief that the planets were the Roman Gods, i.e. Jupiter, Neptune. Another thing is that they were correct in the Geocentric theory with the thought that the planets revolved around something.

The type of radiation that will penetrate farthest into a material isA. a beta ray.

B. a gamma ray.

C. an X-ray.

D. an alpha ray.

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Answers

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A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external pressure on the upper surface of the liquid in KPA

Answers

Answer:

3.43 kPa

Explanation:

Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:

$p=(F)/(A)$

in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):

$F=mg=(350 kg)(9.8 m/s^2)=3430 N$

And since the area on which this force is applied is $A=1 m^2$ , the pressure exerted on the upper surface of the liquid is

$p=(F)/(A)=(3430 N)/(1 m^2)=3430 Pa = 3.43 kPa$

Pressure = force / area

I assume that 350kg is the mass
Therefore,

350 x 9.8 (gravity) = 3430N

3430 / 1 = 3430Pa

3.43 KPa

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D.molecule

Answers

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a 42.3 kg girl and a 7.93 kg sled are on the surface of a frozen lake, 15.0m apart and linked by a rope, but not moving yet. then the girl pulls on the rope, exerting a 5.76 N force on the sled, pulling it toward her. how far from the girl's original position do they meet?

Answers

Answer:

they meet from the girl's original position at: 2.37 (meters)

Explanation:

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Answers

Answer:

d all of the above are correct

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