Using a ruler, you measure the length of a rectangle to be 12.75 cm and the width to be 3.64 cm. Calculate the area of this rectangle (show work), reporting your answer to the correct number of significant figures.

Answers

Answer 1

Answer:

The area of rectangle with length 12.75 cm and the width 3.64 cm with 4 significant figures is 46.41 cm².

What is a quadrilateral?

quadrilateral is a plane mathematical closed figure consist of four side and four edges. There are 7 types of quadrilateral.

Trapezium, Parallelogram, Rectangle, Rhombus, Square, Kite.

Here, it is given that :

the lengthl of a rectangle is = 12.75 cm

the breadthb of a rectangle is = 3.64 cm

Now, let us calculate the area of this rectangle using area formula :

area of rectangle A = length x breadth

A = 12.75 x 3.64

A = 46.41 cm²

Therefore, the area of rectangle with length 12.75 cm and the width 3.64 cm with 4 significant figures is 46.41 cm².

check and know more about quadrilateral here :

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Answer 2

Answer:

Answer:

3200

Step-by-step explanation:

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What is 4/5 + 2/5 =?

Answers

6/5 or you could put it as 1 1/5

Please Answer the following with explanation and formula with neat typing

Answers

Answer: A

Step-by-step explanation:

You want to make them both have common denominators. What number does the denominators both go into? Thats easy, its 60.

Multiply 7/12 by 5/5 to get 35/60

Now multiply 4/15 by 4/4 to get 16/60

You need to add a negative number to 35/60 in order to get 16/60

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uppose a small cannonball weighing 16 pounds is shot vertically upward, with an initial velocity v0 = 290 ft/s. The answer to the question "How high does the cannonball go?" depends on whether we take air resistance into account. If air resistance is ignored and the positive direction is upward, then a model for the state of the cannonball is given by d2s/dt2 = −g (equation (12) of Section 1.3). Since ds/dt = v(t) the last differential equation is the same as dv/dt = −g, where we take g = 32 ft/s2. If air resistance is incorporated into the model, it stands to reason that the maximum height attained by the cannonball must be less than if air resistance is ignored. (a) Assume air resistance is proportional to instantaneous velocity. If the positive direction is upward, a model for the state of the cannonball is given by m dv dt = −mg − kv, where m is the mass of the cannonball and k > 0 is a constant of proportionality. Suppose k = 0.0025 and find the velocity v(t) of the cannonball at time t.

Answers

Answer:

Given in the explanation

Step-by-step explanation:

Given

w = 16 pounds

v₀ = 290 ft/s

g = 32 ft/s²

k = 0.0025 (Kg/s)

$m(dv)/(dt)= -mg - kv^(2)$

Solving the differential equation we obtain

$v(t)=((1)/(0.0125))*tan((-2*(t+C_(1) )/(5) )$

If v(0) = 290 ft/s, we have

$290=((1)/(0.0125))*tan((-2*(0+C_(1) )/(5) )$

⇒ C₁ = -3.254

Finally, we have

$v(t)=((1)/(0.0125))*tan((-2*(t-3.254 )/(5) )$

Which expression is the additive inverse of 25?

Answers

Answer:it’s actually very simple it’s A.

Step-by-step explanation: anything that is below one is negative that’s how I got my answer.

Answer:the answer is A

Step-by-step explanation:i did the test

What are the solutions to the equation 0=x squared- x-6

Answers

Answer:

Factor to this equation out, the easiest way is to solve for the two x values that add up to -1 but when multiplied is equal to -6. It should look like this: (x +- ?)(x +- ?).

The factored out form is then (x - 3)(x +2), because -3 + 2 = -1 and when multiplied together gives -6.

x - 3 = 0

x = 3

x + 2 = 0

x = -2

The two solutions are therefore, x = 3 and x = -2.

Find the value of x that would prove this is an isosceles trapezoid. Then find each segment length.

Answers

Answer:

Check pdf

Step-by-step explanation:

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