Saved Propane burns in air according to the equation C3Ha(g 502lg)3CO2) + 4H20(g) What volume of O2 in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions? Short Answer Toolbar navigation E I E B IUS EA This question will be sent to your Instructor for grading. 20 of 25 l Next > Prev nere to search

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Answer 1

Answer:

Answer: 75 liters of $O_2$ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Lat STP and contains avogadro's number $6.023* 10^(23)$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles of propane}=\frac{\text{Given volume}}{\text{Molar volume}}=(15.0L)/(22.4L)=0.67moles$

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

According to stoichiometry:

1 mole of propane combines with = 5 moles of oxygen

Thus 0.67 moles of propane combine with = $(5)/(1)* 0.67=3.35moles$

Volume of $O_2=moles* {\text {Molar Volume}}=3.35* 22.4L=75L$

Thus 75 liters of $O_2$ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

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At 25.0 ⁰C the henry's law constant for hydrogen sulfide(H2S) gas in water is 0.087 M/atm. Caculate the mass in grams of H2S gas that can be dissolved in 400.0 ml of water at 25.00 C and a H2S partial pressure of 2.42atm.

Answers

Answer: The mass of hydrogen sulfide that can be dissolved is 2.86 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the gas.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_(H_2S)=K_H* p_(liquid)$

where,

$K_H$ = Henry's constant = $0.087M/atm$

$p_(H_2S)$ = partial pressure of hydrogen sulfide gas = 2.42 atm

Putting values in above equation, we get:

$C_(H_2S)=0.087M/atm* 2.42atm\n\nC_(H_2S)=0.2105M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.2105 M

Molar mass of hydrogen sulfide = 34 g/mol

Volume of solution = 400.0 mL

Putting values in above equation, we get:

$0.2105M=\frac{\text{Mass of hydrogen sulfide}* 1000}{34g/mol* 400.0mL}\n\n\text{Mass of }H_2S=(0.2105* 34* 400)/(1000)=2.86g$

Hence, the mass of hydrogen sulfide that can be dissolved is 2.86 grams.

The periodic table displaysOA. all of the known elements that exist in the world today.
OB. only the important elements that exist in the world.
OC. only the important compounds that exist in the world.

Answers

OA. all the known elements that exist in the world today.

Why is it important to keep your apparatus dry what reaction will occur between the grignard reagent and water?

Answers

Grignard reagents react with water to create Alkanes. It is important to keep the apparatus dry because grignard reagents react with water

In the equilibrium system described by: PO43-(aq) + H2O(1) = HPO42-(aq) + OH-(aq) Brønsted-Lowry theory would designate: A) PO43- and H20 as the bases B) H20 and OH as a conjugate pair C) HPO42- and OH"" as the acids D) HPO42- and H20 as a conjugate pair E) PO43-as amphiprotic

Answers

Answer:

The correct option is: B) H₂0 and OH⁻ as a conjugate pair

Explanation:

According to Brønsted-Lowry theory, theacids are the chemical substances that form a conjugate base by donating a proton and bases are the chemical substances that form conjugate acid by accepting a proton.

In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.

Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.

The covalent compounds are soluble in:a) All acids

b) All bases

c) all solvents

d) nonpolar solvents

Answers

Answer:

d) Non-polar solvents

A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylinder after the borax solution had cooled to a certain temperature T. The student rinses the sample into a small beaker using distilled water, and then titrates the solution with a 0.500 M HCl solution. 12.00 mL of the HCl solution is needed to reach the endpoint of the titration.Calculate the value of Ksp for borax at temperature T.