MATHEMATICS HIGH SCHOOL

The minimum of the graph of a quadratic function is located at (–1, 2). The point (2, 20) is also on the parabola. Which function represents the situation?A.f(x) = (x + 1)2 + 2
B.f(x) = (x – 1)2 + 2
C.f(x) = 2(x + 1)2 + 2
D.f(x) = 2(x – 1)2 + 2

Answers

Answer 1
Answer: Minimum wykresu funkcji kwadratowej znajduje się w ( -1, 2). Punkt ( 2 , 20) jest również od paraboli. Która funkcja reprezentuje sytuację?
Canonical form of the function
f(x) = a* (x - p)² + q

A .f(x) = (x + 1)² + 2    ⇔ p= -1 , q = 2
B. f(x) = (x – 1)² + 2    we reject
C. f(x) = 2(x + 1)² + 2  ⇔ p = -1 , q = 2
D .f(x) = 2(x – 1)² + 2   we reject

The point (2,20)  substitute
A f(x) = (x +1)² + 2
   20 = (2 + 1 )² + 2
   20 ≠ 9 +2
   20 ≠ 11   we reject

D f(x) = 2* (x + 1)² + 2
    20 = 2* (2+1)² + 2
    20 = 2 * 3² + 2
    20 = 2 * 9 + 2
    20 = 18 + 2

Reply C

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1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . . a. cos^2x+sin^2x=1.
b. cot x= cosx/sinx.
c. cos x= 1/sec x.
d. sin x= 1/csc x. .
2.What basic trigonometric identity would you use to verify that sin^2x+cos^2x/cosx= sec x?.
a. sin x=1/csc x.
b. 1+cot^2x=csc^2x.
c. cos^2x+sin^2x=1.
d. cos x= 1/sec x

Answers

1 ) cot x * sin x = cos x
(cos x / sin x) * sin x = cos x 
cos x = cos x
Answer: B ) cot x = cos x / sin x
2 ) ( sin² x + cos² x ) / cos x = sec x
1/cos x = sec x
sec x = sec x
Answer: C ) cos² x + sin² x = 1

Answer:

C

Step-by-step explanation:

What should be done to both sides of the equation in order to solve p - 17 = -23?

Answers

Answer:

the number 17 should be added to it

Step-by-step explanation:

brainliest pls =}
Solve with one variable for both sides.

If EG=10x+20, FG=43. EG=183, find the value of x.

Answers

Answer:

Option (3)

Step-by-step explanation:

Given: EF = 10x + 20

           FG = 43

           EG = 183

From the figure attached,

Length of segment EF + length of segment FG = length of segment EG

By substituting the values of each segment in the equation,

(10x + 20) + 43 = 183

10x + 20 = 183 - 43

10x = 140 - 20

x = (120)/(10)

x = 12

Therefore, x = 12 will be the answer.

Option (3) will be the correct option.

C(-2,-1), K(8,3) find distance between each pair of points

Answers

D=square root sign (x2-x1)^2+(y2-y1)^2
If u need help plugging the numbers in lmk.

Liquid A has a density of 0.7g/cm^3liquid B has a density of 1.6g/cm^3

140g of liquid A is and 128g of liquid B are mixed to make liquid C

work out the density of liquid C

Answers

density is defined as mass per unit volume

in this case liquids A and B with 2 different densities are mixed and we are asked to find the density of the liquid C


liquid A has a density of 0.7 g/cm³

mass of liquid A added is 140 g

therefore volume of liquid A added is - 140 g / 0.7 g/cm³ = 200 cm³


liquid B has a density of 1.6 g/cm³

mass of liquid B added is 128 g

volume of liquid B added is - 128 g / 1.6 g/cm³ = 80 cm³


the total mass of liquid C after adding liquid A and B = 140 g + 128 g = 268 g

total volume in liquid C - 200 cm³ + 80 cm³ = 280 cm³

density of liquid C = mass / volume

= 268 g / 280 cm³ = 0.957 g/cm³

density of liquid C - 0.957 g/cm³
\rho = (m)/(V) \Rightarrow V=(m)/(\rho)
ρ - density, m - mass, V - volume

Liquid A:
\rho=0.7 \ (g)/(cm^3) \nm=140 \ g \n\n V=(140 \ g)/(0.7 \ (g)/(cm^3))=200 \ cm^3

Liquid B:
\rho=1.6 \ (g)/(cm^3) \nm=128 \ g \n\n V=(128 \ g)/(1.6 \ (g)/(cm^3))=80 \ cm^3

Liquid C:
m=140 \ g + 128 \ g=268 \ g \nV=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \n \n\rho=(268 \ g)/(280 \ cm^3) \approx 0.96 \ (g)/(cm^3)

The density of liquid C is approximately 0.96 g/cm³.

What is the GCF of 12x and 44xy

Answers

12x=4x\cdot3\n\n44xy=4x\cdot11y\n\nGCF(12x;\ 44xy)=4x
If we don't know what 'x' and 'y' are, the best we can say is that the GCF is 4x .
But 'x' and 'y' can easily take on values that would change the GCF.
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