la suma de nataly y nicole es 18 años si nicole es mayor q nataly por 2 años ¿cual es la edad de nicole?
Answers
Nicole would be 16
Related Questions
If a spinner has 10 equal sized sections which of the following will be false
The sum of 9/10 and 1/32 is less than 1 or more than 1?
What is the difference between 3/7 and 1/14
What is 36,000 x 10 = ?
Answers
Haven translated the word problem into an algebraic expression, the unknown number is 6.
- Let the number be n.
In this exercise, you're required to find an unknown number by writing an algebraic expression for the word problem and solve for the unknown number.
Translating the word problem into an algebraic expression, we have;
Eight times a number increased by 9:
....equation 1.
15 more than 7 times the number:
....equation 2.
Next, we would equate the two equations since we were told that they are the same.
Therefore, the unknown number is 6.
Find more information: brainly.com/question/596290
Answer:
the number is 6
Step-by-step explanation:
8x+9=15+7x
8x-7x+9=15+7x-7x
x+9=15
x+9-9=15-9
x=6
x + 2y = 1
Answers
y=2x-7
sub 2x-7 for every y you se inother equation
x+2(2x-7)=1
x+4x-14=1
5x-14=1
add 14 both sides
5x=15
divide 5
x=3
sub back
y=2x-7
y=2(3)-7
y=6-7
y=-1
(3,-1) is solution
Answers
14x+10y=140
How many adults and how many children were in the group?
A.
5 adults and 7 children
B.
6 adults and 6 children
C.
7 adults and 5 children
D.
8 adults and 4 children
Answers
x + y = 12
14x + 10y = 140
lets multiply the first equation by -10 and then add it to the second equation:
-10x - 10y = -120
14x + 10y = 140
-----------------------
4x + 0 = 20
x = 20/4
x = 5
then substitute in the original equation:
x + y = 12
5 + y = 12
y = 12 - 5
y = 7
therefore there were 5 adults and 7 children
Answers
4 out of the 12 cups are decaf, so the odds of selecting a decaf cup by random is 4/12 or 1/3
Alternatively 8 of the 12 cups are caffeinated, so the odds of selecting a caffeinated cup by random is 8/12 or 2/3
P(decaf)=1/3
P(caf)=2/3
But those odds are only for the first cup picked. The second cup has 4 probabilities...
1. Picking a decaf cup for the second time
2. Picking a decaf cup for the first time
3. Picking a caf cup for the second time
4. Picking a caf cup for the first time
So lets find the probability of each event...
1. Picking a decaf cup for the second time. If a decaf cup has already been picked, then the odds of drawing another one is 3/11
2. Picking a decaf cup for the first time. If a decaf cup hasn't already been picked, then the odds of drawing one is 4/11
3. Picking a caf cup for the second time. If a caf cup has already been picked, then the odds of drawing one is 7/11
4. Picking a caf cup for the first time. If a car cup hasn't already been picked, then the odds of drawing one is 8/11.
Okay, so now we can solve for the various possibilities.
1. Picking a decaf cup for the second time
1/3*3/11=3/33
2. Picking a decaf cup for the first time
2/3*4/11=8/33
3. Picking a caf cup for the second time
2/3*7/11=14/33
4. Picking a caf cup for the first time
2/3*8/11=16/33
Both cups were caffeinated, so neither were decaf.
Answer= Neither cup is decaf.
Answers
1/4:2=3/2;x
1/4*1/2=3/2*1/x
1/8=3/2x
2x=8*3
x=24:2
x=12