MATHEMATICS HIGH SCHOOL

If an object is dropped from a height of 85 feet, the function h(t)=-16t^2+85 gives the height of the object after t seconds. Approximately, when will the object hit the ground?a. 85.00 seconds
b. 69.00 seconds
c. 0.33 seconds

Answers

Answer 1
Answer: c because all you need to do is compare the 2 variables and then add the variables and the multiply it and then divide it. Then your golden.

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If 2 is added to seven times a number and equals 8 more than six times a number what is the number

Answers

Seven times a number is 7x; 6 times a number is 6x and then solve7x+2=6x+8X+2=8X=6
Your word equation turned into an operation would be: 2+7n=8+6n. To complete this equation you have to balance it out so only n would be put on one side. So, try subracting 6n on both sides so it can be on the same side as 7n:2+7n-6n=8+6n-6n.Therefore the 6n on the right side has now switched over to the left. Then, you need to switch the 2 onto the right side by subtracting it on both sides as well:2+7n-6n-2=8-2The 2 has now been switched. After, subtract 7n-6n=1n, and 8-2=6. The equation then becomes:1n=6.To isolate n from 1, divide 1n by 1 and 6 by 1. Your equation afterwards should be: n=6/1, or as simplified: n=6.

A box of oranges weighs 4 kg. If one orange weighs 80 g, how many oranges are in the box?

Answers

Answer:

50 oranges

Step-by-step explanation:

Convert the measurements for them to be the same ie 4kg to g

1kg=1000g. 4kgx1000=4000g

4000g is the mass of all oranges

1 orange=80g

? =4000g that is 4000/80

=50 oranges

Answer:

50 oranges

Step-by-step explanation:

Since each orange is measured in grams, we convert the 4 kg to g to start.

4 kg is equal to 4000 g.

Each orange weighs 80 g, so we divide 80g into 4000g.

80 divided by 4000 equals 50.

50 oranges are in the box.

I Hope This Helps!

Please help me. Attached is a picture of a triangle. I need to find the length of X through the Pythagorean theorem. Can you explain how to do this? I need to do numbers 30-32. But if you can just do one that would help greatly!

Answers


First, let's make sure you know what Pythagoras said.
It's very important, mainly because it's so useful:

       In any RIGHT triangle, the square of the longest side
       is the sum of the squares of the other two sides.

Now let's look at #30:

This is two right triangles back-to-back.

'x' is the longest side of the one on the left, but we can't
   solve for 'x' yet because we only know one of the other sides.

But look at the right triangle on the right side.  We know the
longest side, and the vertical one, so we can find the base of it.

           (longest side)² = (one short side)² + (the other short side)²

                  (15)²          =  (9)²   +   (the base)²

Subtract (9)² from each side:

                   (The base)² = (15)²  -  (9)²

                   (The base)² = 225 - 81  =  144

                   The base  =  √144  =  12 .

Do you see where we are now ?
The base of the right half is  12, 
   so the base of the left half is  (25 - 12) = 13 .

Pythagoras again, on the left half:

                               x²  =  (13)² + (9)²

                               x²  =  169  +  81  =  250

                               x = √250 = (√25)·(√10) = 5 √10 .
________________________________

#31:

Again, two right triangles back to back.
You know two sides in each one.
So you can find the base of each one, then add the bases to get 'x'.

Left half:     (Base)²  =  (10)² - (6)²
                   (Base)²  =  100  -  36  =  64
                    Base  =  √64    <== you know what that is

Right half:    (Base)²  =  (7)² - (6)²
                    (Base)²  =  49   - 36 = 13
                     Base     = √13

       x = sum of the two bases = √64 + √13 .
_________________________________

#32: 
Two right triangles again.
Not back to back.

Right half:      (Missing leg)²  =  (7)² - (2)²
                      (Missing leg)²  =  49 - 4 = 45
                       Missing leg    = √45 = (√9)·(√5) = 3 √5 .

Left half:  The longest side is  3√5 .

                x²  +  (5)²  =  (3√5)²

I'm sure you got the idea by now.

Most likely to describe the change received from a cash purchase? A: Whole number
B: Negative numbers
C: Rational numbers

Answers

Answer:

C: Rational numbers

Step-by-step explanation:

The change received in a cash purchase, if given in £ (or $) would most certainly be a Rational number (that is a number that can be represented as a/b where a and b are coprimes). However if measured in p (or cents) then the answer would be whole numbers.

You cannot go wrong with option C as whole numbers (integers) are a subset of rational numbers. That is, all whole numbers are rational numbers.

What was the greatest challenge cities faced as a result of rapid industrialization in the 1800s?

Answers

The greatest challenge cities faced as a result of rapid industrialization in the 1800 was the dramatic increase in the number of the people that are moving into the cities. There was mass movement of the people from the rural regions into the cities where industries are located. This led to overcrowding in the cities.

Answer:

D

Step-by-step explanation:

The greatest challenge cities faced as a result of rapid industrialization in the 1800s was providing enough city services to protect and support new citizens. Option D is correct.

Julian and stacey needed 10 liters of water to fill a tank. Stacey filled the tank with 3 11/12 liters of water. Julian poured 1 2/5 liters less than Stacey into the tank. How much more water is still needed to fill the tank?

Answers

The amount of water Julian and Stacey needed to fill the tank = 10 liters
Amount of water filled by Stacey individually = 3 11/12 liters
                                                                       = 47/12 liters
It is given in the question that Julian poured 12/5 liters less than Stacey.
Then Amount of water filled by Julian = (47/12) - (12/5) liters
                                                            = (235 - 144)/60
                                                             = 91/60
So Julian filled 91/60 liters of water in the tank.
Amount of water still needed to fill the tank = 10 - [(47/12) - (91/60)]
                                                                     = 10 - [(235 - 91)/60]
                                                                     = 10 - (144/60)
                                                                     = 10 - 12/5
                                                                     = (50 - 12)/5
                                                                     = 38/5
                                                                     = 7 3/5
so 7 3/5 liters of water is still required to fill the tank.

Answer:

20

Step-by-step explanation:
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