MATHEMATICS MIDDLE SCHOOL

What Is the equation of the graph? y=7/4x-5/2
y=3/2x-5/2
y=5/2x+3/2
y=-5/2x+3/2​
what Is the equation of the graph? y=7/4x-5/2 y=3/2x-5/2 y=5/2x+3/2 - 1

Answers

Answer 1
Answer:

Answer:  y=(7)/(4)x-(5)/(2)

Step-by-step explanation:

The equation of a line passing through points (a,b) and (c,d) is given by :-

(y-b)=(d-b)/(c-a)(x-a)

From the given graph , it can be seen that the line is passing through (0,-2.5) and (2,1).

Then, the equation of line passing through (0,-2.5) and (2,1) will be:-

(y-1)=(1-(-2.5))/(2-0)(x-2)\n\n\Rightarrow\ (y-1)=(1+2.5)/(2)(x-2)\n\n\Rightarrow\ y-1=(3.5)/(2)(x-2)\n\n\Rightarrow\ y-1=(7)/(4)(x-2) \ \ [\because 3.5=(7)/(2)]\n\n\Rightarrow\ y-1=(7)/(4)x-(7)/(4)*2\n\n\Rightarrow\ y=(7)/(4)x-(7)/(2)+1\n\n\Rightarrow\ y=(7)/(4)x+(-7+2)/(2)\n\n\Rightarrow\ y=(7)/(4)x-(5)/(2)

Hence, the equation of the graph is y=(7)/(4)x-(5)/(2)
Answer 2
Answer:

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 2.5) and (x₂, y₂ ) = (2, 1) ← 2 points on the line

m = (1+2.5)/(2-0) = (3.5)/(2) = (7)/(4)

Note the line crosses the y- axis at (0, - 2.5) ⇒ c = - 2.5 = - (5)/(2)

y =  (7)/(4) x - (5)/(2) → A

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What is 12 cats to 15 dogs simplest form

Answers

Answer:

4 cats : 5 dogs is your answer

Step-by-step explanation:

Divide common factors from both ratios. Find the factors:

12: 1, 2, 3, 4, 6

15: 1, 3, 5, 15

The greatest common factor is 3 (as they are factors for both). Divide 3 from both numbers:

12:15

(12)/3 : (15)/3

4:5

4 cats : 5 dogs is your answer

~

I need help, I have tried looking it up but can’t find any help

Answers

Answer: (sin (4x))/(cos(14 x))

Step-by-step explanation:

We have the following expression:

(tan(9x)-tan(5x))/(1+tan(9x)tan(5x))

In order to work in a better way this expression, let's call \alpha=9x and  \beta=5x and rewrite:

(tan(\alpha)-tan(\beta))/(1+tan(\alpha)tan(\beta))

Now, we know tan \theta=(sin \theta)/(cos \theta). Let's apply it here:

((sin (\alpha))/(cos(\alpha))-(sin(\beta))/(cos(\beta)))/(1+(sin (\alpha))/(cos(\alpha))(sin(\beta))/(cos(\beta)))

((sin(\alpha)cos (\beta)-sin(\beta)cos(\alpha))/(cos(\alpha)cos(\beta)))/((cos(\alpha) cos(\beta)+sin(\alpha) sin(\beta))/(cos(\alpha)cos(\beta)))

Simplifying:

(sin(\alpha)cos (\beta)-sin(\beta)cos(\alpha))/(cos(\alpha) cos(\beta)+sin(\alpha) sin(\beta))

According these trigonometric identities, we have:

sin(\alpha-\beta)=sin(\alpha)cos (\beta)-sin(\beta)cos(\alpha)

cos(\alpha+\beta)=cos(\alpha) cos(\beta)+sin(\alpha) sin(\beta))

Then:

(sin(\alpha-\beta))/(cos(\alpha+\beta))

Writing again the actual values:

(sin(9x-5x))/(cos(9x+5x))

Finally:

(sin(4x))/(cos(14x))

How do i evaluate expression below? 4(3)
4 * {3}^(2)

Answers

Answer:

4 x 3 x 3 x 3

Sorry if not.
SOLUTION:

According to the order of operations, we will evaluate the expression as displayed below:

= 4 × 3^2

First we will solve the indice.

= 4 × 3 × 3

OR

= 4 × 9

Then we will solve the multiplication.

= 36

Hope this helps! :)
Have a lovely day! <3

Choose the answer. A rectangular side yard was 9 yards long and 3 yards wide. What is the area of the side yard?a.
27 yd

B.
27 yd²

C.
18 yd

D.
18 yd²

Answers

area=legnth times width

legnt=9
width=3
area=9 times 3=27
answer is 27 squaer yards
(square yards since it is 2 dimentional)
 aka
27 yd^2

answer is B
Area of a rectangle is Length x Width. 
So 9yards*3yards= 27yards^2 
your answer is B

Can the fraction 2/1 be simplified

Answers

Yes. 2/1=2

It's the same as saying 2 divided by 1.
Yes, If you want a whole number, 2 but if you want a fraction then no it can't be simplified.
Hope it helps! :-)

How many solutions are there for the system of equations shown on the graph? No solution
One solution
Two solution
Infinitely many solutions

Answers

Since the two lines are parallel, there will be no solutions.

Your answer is No solutions.

If there were two lines, one on top of the other, there would be infinitely many solutions.
If there were two lines that intersected at one point, there would be one solution.
But keep in mind that there can never be two solutions.
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