Not sure how to solve. Julia uses the shadow of a flagpole to estimate its height. She stands so that the tip of her shadow coincides with the tip of the flagpole’s shadow, as shown. Julia is 5 feet tall. The distance from the flagpole to Julia is 28 feet, and the distance from the tip of the shadows to Julia is 7 feet. Calculate the height of the flagpole. a. 13 feet b. 980 feet c. 39 feet d. 25 feet

Answers

Answer 1

Answer: You are going to have to compare the height and shadow of Julia to the height and shadow of the flagpole.
Julia is 5 feet tall with a shadow of 7 feet.
The flagpole is "x" feet tall with a shadow of 35 feet (to get 35, I added 28 feet and 7 feet.)
So, you do 5/7 = x/35
You cross multiply and get 175 = 7x
Then, divide by 7 and you get 25.
25 feet is the height of the flagpole, so it would be option "D".

Answer 2

Answer:

Answer:

C. 25 feet.

I just wanted to clarify because he got the answer 25 correct however not the option.

mark him brainliest plox?

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A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from $9 to $15. Which price gives the store the maximum amount of revenue, and what is the maximum revenue? (Revenue = price mc023-1.jpg number of backpacks.) $9.00 per backpack gives the maximum revenue; the maximum revenue is $32.00. $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00. $12.50 per backpack gives the maximum revenue; the maximum revenue is $312.50. $15.00 per backpack gives the maximum revenue; the maximum revenue is $20.00.

Answers

Revenue = price * number of backpacks
number of backpacks = -2p + 50

p = 9 ; -2(9) + 50 = -18 + 50 = 32
revenue = 9 * 32 = 288

p = 12 ; -2(12) + 50 = -24 + 50 = 26
revenue = 12 * 26 = 312

p = 12.50 ; -2(12.50) + 50 = -25 + 50 = 25
revenue = 12.50 * 25 = 312.50 GIVES THE MAXIMUM REVENUE

p = 15 ; -2(15) + 50 = -30 + 50 = 20
revenue = 15 * 20 = 300

Answer:

Its C on Edge

Step-by-step explanation:

$12.50 per and maximum of $312.50

Took the Test and got it right.

What is (24 times 25)50 50=?

Answers

the answer to this is 600

What is the range of the data set 22 30 49 71 85 88 92 97 99

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Can anyone do question 25 part c? :)

Answers

$\begin{cases}x^3\qquad\qquad\ \ \ when\ x\geq3\n5\qquad\qquad\quad \ when\ 0\ \textless \ x\ \textless \ 3\nx^2-x+2\quad\ when\ x\leq0 \end{cases}\n\n\n (a)\n f(0)\iff x=0\implies f(x)=x^2-x+2\n\nf(0)=0^2-0+2=2\n\n(b)\n \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\n\n f(2)=5\quad\wedge\quad f(1)=5\n\n f(2)-f(1)=5-5=0$

$(c)\n \big\forall \limits_( n\in R)\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_( n\in R)\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \ f(x)=x^2-x+2\n\nf(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2$

4|x+5|=20
Thanks for the help

Answers

4 |x = 5| = 20

First, divide both sides by 4. / Your problem should look like: $|x + 5| = 5$
Second, simplify $(20)/(4)$ to 5. / Your problem should look like: $|x + 5| = 5$
Third, break the problem into 2 equations. / x + 5 = 5 and -(x + 5) = 5
Fourth, solve x + 5 = 5. /
Cancel 5 on both sides. / $x = 0$
Fifth, solve -(x + 5) = 5 /
Simplify brackets / $-x - 5 = 5$
Add 5 to both sides / $-x = 5 + 5$
Add 5 + 5 / $-x = 10$
Multiply both sides by -1 / $x = -10$
x = -10
Sixth, collect the solutions to the problems. / Your problem should look like: $x = -10, 0$

Answer: x = -10, 0

4Ix+5I=20
$4(-(x+5))=20$
$4(-x-5)=20$ distributhing 4 through parantheses
$-4x-4*5=20$
$-4x-20=20$
$-4x=20+20$
$-4x=40$ divide by -4
$x= (40)/(-4)$ simplify
$x=-10$
The answer is : - 10

124 ÷ 7283 i need help understanding it

Answers

Answer:

0.01702595084 or 0.⁻0⁻ (line is above the second zero)

Step-by-step explanation:

it is not a full number and its rational

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