Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is found that 1% of the legitimate users originate calls from two or more metropolitan areas in a single day. However, 30% of fraudulent users originate calls from two or more metropolitan areas in a single day. The proportion of fraudulent users is 0.01%. If the same user originates calls from two or more metropolitan areas in a single day, what is the probability that the user is fraudulent?

Answers

Answer 1
Answer:

Answer:

the probability that the user is fraudulent is 0.00299133

Step-by-step explanation:

Let be the events be:

G: The user generates calls from two or more areas.

NG: The user does NOT generate calls from two or more areas.

L: The user is legitimate.

F: The user is fraudulent.

The probabilities established in the statement are:

P (G | L) = 0.01//P (G | F) = 0.30//P (F) = 0.0001//P (L) = 0.9999//

With these values, the probability that a user is fraudulent, if it has originated calls from two or more areas is:

P (F|G) = (P(F\bigcap G))/(P(G)) = (P(F)P(G|F))/(P(G)) = (P(F)P(G|F))/(P(F)P(G|F)+P(L)P(G|L))

((0.0001)(0.30))/((0.0001)(0.30)+(0.9999)(0.01)) = 0.00299133


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Z=15+2(x+y) solve for x

Answers

Z=15+2(x+y) 
Use distributive property
Z= 15 + 2x + 2y
Subtract 2y from both sides
Z - 2y= 15 + 2x
Subtract 15 from both sides
Z - 2y - 15= 2x
Divide 2 on both sides
Final Answer: Z - 2y - 15(All over 2)= x
z=15+2x+2y
0=15+2x+2y-15
-2x=15+2y-15
x= -(15)/(2) - y +  (15)/(2)

3is (4,-5) a solution of the graphed inequality?
Choose 1 answer:
Yes
0
No

Answers

Yesssssssssssssssssssssss

What’s the answer to this

Answers

answer : x-intercept = (11,0)
y-intercept = (0,6)

The table of values shows the number of touchdown passes that a quarterback threw in each of his first five football games of the season.Game vs. Touchdown Passes
Game
Touchdown passes
1
3
2
1
3
3
4
2
5
3

Which would be a point on the scatterplot that represents touchdown passes based on these games played?
(1, 2)
(2, 4)
(3, 1)
(5, 3)

Answers

Answer:

D

Step-by-step explanation:

If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5

So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.

Answer:D

Step-by-step explanation:

PLEASE HELP ASAP!!! :)Using the remainder theorem, what is the remainder of the quotient of x^3– 6x^2 + 4x– 5 and 1 - 3?

A.88
B. -20
c.-74
D. 34

Answers

The remainder of the quotient is -20.

Option B is the correct answer.

What is an expression?

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

x³ - 6x² + 4x - 5 and x - 3

Now,

x - 3 ) x³ - 6x² + 4x - 5 ( x² - 3x - 5

         x³ - 3x²

       (-)    (+)

             -3x² + 4x

             -3x² + 9x

          (+)      (-)

                    -5x - 5

                    -5x + 15

                (+)      (-)

                          -20

Thus,

The remainder is -20.

Learn more about expressions here:

brainly.com/question/3118662

#SPJ2

Answer:

The correct answer is B. -20.

Step-by-step explanation:

I got it right on the Edmentum test.

observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

Answers

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

2xy =6.....(a)\n\nx-y= 3.....(b)\n\n

After solve equation (a) we get

\ equation: \n\n2xy= 6\n\nxy =(6)/(2) \n\nxy = 3.....(x)\n\n

After solve equation (b) we get

\ equation: \n\nx-y =3\n\nx= 3+y....(x1)\n

put the value of x in to equation (x)

(3+y)y = 3\n

y^2+3y-3=0\n\n\ compare \ the \ value \ with \ ay^2+by+c=0\na= 1\nb=3\nc=-3\n\ Formula: \ny= (-b\pm√(b^2-4ac))/(2a)\ny= (-3\pm √(9+12))/(2)\ny= (-3\pm √(21))/(2)\n

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29