MATHEMATICS MIDDLE SCHOOL

What is 29 x 35 double digit

Answers

Answer 1

Answer:

Answer:

29 times 35 is 1015

Step-by-step explanation:

there is no way it can be a double digit to get my answer just multiply them together

Answer 2

Answer:

Answer: 1,015

Step-by-step explanation:

x 35

5x9 is 45

5x2 is 10

3x9 is 27

3x2 is 6

add it up and u get the answer

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N =⟨−2, −1⟩ and D= $\left[\begin{array}{cc}-3&0\n4&1\n\end{array}\right]$ What is D⋅n?

Answers

Answer:

-9

Step-by-step explanation:

-3(-2) + 0(-1)

4(-2) + 1(-1)

6 + 0

-8 + -1

-9

*don't forget to add brackets on each side of every calculation okay :)

Please help me! im really stuck on this one!

Answers

Dependent variable. Its fairly easy if you plug in the problem into
:)

Please help me asap!

Answers

Answer:

$(7x + 7)/((x-3)(x+4))$

Excluded values are 3 and -4

Step-by-step explanation:

To simplify the expression multiply to create a common denominator.

Multiply the first fraction by (x-3) and the second fraction by (x+4).

$(3)/(x+4) + (4)/(x-3)\n\n(3(x-3))/((x+4)(x-3)) + (4(x+4))/((x-3)(x+4))$

$(3(x-3))/((x+4)(x-3)) + (4(x+4))/((x-3)(x+4)) \n\n(3(x-3) + 4(x+4))/((x-3)(x+4))\n\n(3x - 9 + 4x + 16)/((x-3)(x+4))\n\n(7x + 7)/((x-3)(x+4))$

Excluded values are values which make the denominator 0. This means (x-3)(x+4) cannot be 0. This means x cannot be 3 or -4. These are excluded values.

Mr. Conrad's pecan pie recipe calls for 1 3/4 cups of pecans. He plans to make 6 pies for his family reunion. How many cups of pecans will Mr. Conrad need

Answers

According to my calculations the answer is 19.5 or 19.50 you can pick either one but your teacher will probably want the first.

$1 (3)/(4)$ x 6 (or $(6)/(1)$

Change 1 3/4 to an improper fraction = $(7)/(4)$

$(7)/(4)$ x $(6)/(1)$ = $(42)/(4)$ = 10 $(2)/(4)$ cups
Reduce the answer and get 10 $(1)/(2)$ cups

If x and y are real numbers such that x > 1 and y < −1,then which of the following inequalities must be true?
A. x/y> 1
B. |s|^2 > |y|
C. x/3− 5 > y/3 − 5
D. x^2 + 1 > y^2 + 1
E. x^(−2) > y^(−2)

Answers

$x > 1\ \wedge\ y < -1\n\nA.\ (x)/(y) > 1-FALSE;example:x=2;\ y=-2\ then\nL=(2)/(-2)=-1;R=1;\ L < R\n\nB.\ |x|^2 > |y|-FALSE;example:x=2;\ y=-6\ then\nL=|2|^2=2^2=4;R=|-6|=6;\ L < R\n\nC.\ (x)/(3)-5 > (y)/(3)-5-TRUE;(x)/(3)-5 > (y)/(3)-5\to(x)/(3) > (y)/(3)\to x > y$

$D.\ x^2+1 > y^2+1-FALSE;example:x=2;\ y=-3\ then\nL=2^2+1=4+1=5;R=(-3)^2+1=9+1=10;L < R\n\nE.\ x^(-2) > y^(-2)-FALSE;example:x=3;\ y=-2\ then\nL=3^(-2)=(1)/(9);R=(-2)^(-2)=(1)/(4);\ L < R$

sketch the graph of each line.

y=x-3

Answers

$y=x-3\n\nfor\ x=0\to y=0-3=-3\to A(0;-3)\n\nfor\ x=3\to y=3-3=0\to B(3;\ 0)$

Answer:

Draw a line crossing through -3 on the y axis (3 under the middle, or the origin) and then draw a straight line that crosses through exactly one square on the graph from corner to corner.

Step-by-step explanation:

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