What is the arc length when θ = and the radius is 7 cm? (5 points)

Answers

Answer 1
Answer: What is the arc length when Θ=3 pi/5 and the radius is 7 cm?
Here are the available answers... 21pi/5 cm 12pi/5 cm 6pi/5 cm 3pi/35 cm

Given:
arc length = theta * radius
arc length = (3 pi/5)(7cm)
arc length = 21pi/5 cm   Answer is the 1st option.

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Julie's cell phone is 9 centimeters long. How many millimeters long is her cell phone?

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Plz help i'll mark u brainliest

Answers

Answer:

h = 34 *  \sin(27)  + 5 = 15.43 + 5 = 20.43

Help Me Please???:):Dfour years after a hedge maple tree was planted, its height was 9 feet. eight years after it was planted, the hedge maple tree's height was 12 feet. what is the growth rate of the hedge maple? what was its height when it was planted?? ...?

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Solve for x.
7x = 78

Answers

1.142 is the value of x in the equation  7x = 78.

The given equation is 7x = 78

In the equation x is the variable.

We need to find the value of x.

Divide both sides by 7 to get the value of x

x=78/7

x=11.142

Hence, the value of x in the equation  7x = 78 is 11.142.

To learn more on Equation:

brainly.com/question/10413253

#SPJ2

7x=78---- ---- = 11.147 7

Let f(x)=8x and g(x)=8x+5+1.Which transformations are needed to transform the graph of f(x to the graph of g(x)?

Select each correct answer.

horizontal translation 1 unit left

vertical translation 1 unit down

vertical translation 5 units up

vertical translation 1 unit up

horizontal translation 5 units right

horizontal translation 5 units left

Answers

Transformation involves changing the form of a function

The transformations are:

  • vertical translation 1 unit up .
  • horizontal translation 5 units left.

The functions are given as:

\mathbf{f(x) = 8x}

\mathbf{g(x) = 8(x + 5) + 1}

Considering f(x), we have:

\mathbf{f(x) = 8x}

Start by translating the function 5 units left.

The rule of this translation is:

\mathbf{f'(x) = f(x + 5)}

So, we have:

\mathbf{f'(x) = 8(x + 5)}

Next, translate the function 1 unit up

The rule of this translation is:

\mathbf{f''(x) = f'(x) + 1}

So, we have:

\mathbf{f''(x) = 8(x + 5) + 1}

Rewrite as:

\mathbf{g(x) = 8(x + 5) + 1}

Hence, the transformations are: vertical translation 1 unit up  and horizontal translation 5 units left

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If g(x) = (8x + 5) + 1, then the correct answers are in bold below

Select each correct answer.

horizontal translation 1 unit left

vertical translation 1 unit down

vertical translation 5 units up

vertical translation 1 unit up 

horizontal translation 5 units right

horizontal translation 5 units left

Evaluate limit as x approaches 0 sin^2x/(1-cosx).

Answers

\lim_(x \to 0) (sin ^(2)x )/(1-cos x) = ( (0)/(0) )= \n = \lim_(x \to 0) (1-cos ^(2)x )/(1-cosx)= \n = \lim_(n \to 0) ((1+cosx)(1-cosx))/((1-cosx))= \n = \lim_(x \to 0) (1+cos x) =
= 1 + cos 0 = 1 + 1 = 2
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