What is the proportion of 7/5=k/18
Answers
Related Questions
Whats the best way to do this operation?---------------------------------Phillip charged $400 worth of goods on his credit card. On his first bill, he was not charged any interest, and he made a payment of $20. He then charged another $18 worth of goods. On his second bill a month later, he was charged 2% interest on his entire unpaid balance. How muchinterest was Phillip charged on his second bill?
What's substitution for x=y-7;x+8y=2
Please, help me! A farm producing x tons of rice at a cost represented by C = 3x +3. If the total revenue from rice production is given by R = 7x + 2, to not have prejudice, the farm must produce at least:
What is the solution of the equation?-10 + sqrt x+8 = -4
Answers
Therefore, a = 1, b = 0, c = 2 and d = 3
The value of c from the given expression is 14.
Given that, the quantity 4 times x squared times y squared plus 8 times x cubed times y to the fifth power all over 2 times x times y squared is completely simplified to .
Here, expression is (4x²y²+8x³y)⁵/2xy²
= (4x¹⁰y¹⁰+8x¹⁵y⁵)/2xy²
= 4x¹⁰y¹⁰/2xy²+8x¹⁵y⁵/2xy²
= 2x⁹y⁸+4x¹⁴y³
By comparing 2x⁹y⁸+4x¹⁴y³ with , we get
a=9, b=8, c=14 and d=3
Therefore, the value of c from the given expression is 14.
To learn more about an exponents visit:
brainly.com/question/15993626.
#SPJ6
3. find the value of x,
3a. sin(x) = cos 31,
3b. sin 75 = cos(x),
3c. sin(x-4) = cos 50
Answers
Step-by-step explanation:
Answer:
\frac{7}{4}
4
7
Explanation:
______________________
We know the values of
i) cos0° = 1
ii) sin45° = \frac{1}{\sqrt{2}}
2
1
iii) sin30° = \frac{1}{2}
2
1
iv) sin90° = 0
v) cos45° = \frac{1}{\sqrt{2}}
2
1
vi ) cos60° = \frac{1}{2}
2
1
_____________________
Now,
The value of
(cos 0+sin 45+sin 30)(sin 90-cos 45+cos 60)
= \left(1+\frac{1}{\sqrt{2}}+\frac{1}{2}\right)\left(1-\frac{1}{\sqrt{2}}+\frac{1}{2}\right)(1+
2
1
+
2
1
)(1−
2
1
+
2
1
)
= \left(\frac{3}{2}+\frac{1}{\sqrt{2}}\right)\left(\frac{3}{2}-\frac{1}{\sqrt{2}}\right)(
2
3
+
2
1
)(
2
3
−
2
1
)
= \left(\frac{3}{2}\right)^{2}-\left(\frac{1}{\sqrt{2}}\right)^{2}(
2
3
)
2
−(
2
1
)
2
/* By algebraic identity
(a-b)(a+b) = a²-b² */
= \left( \frac{9}{4}-\frac{1}{2}\right)(
4
9
−
2
1
)
= \frac{9-2}{4}
4
9−2
= \frac{7}{4}
4
7
••••
A (3, 1), B (5, 4), C (6, — 1)