Mike's car, which weighs 1,000 kg, is out of gas. Mike is trying to push the car to a gas station, and he makes the car go 0.05 m/s2. Using Newton's Second Law, you can compute how much force Mike is applying to the car.

Answers

Answer 1

Answer:

The magnitude of applied force on the car by Mike is 50 N.

Given data:

The mass of car is, m = 1000 kg.

The magnitude of acceleration of car is, $a = 0.05 \;\rm m/s^(2)$ .

According to Newton's second law of motion, the force applied on the object is expressed as the product of mass of object and magnitude of acceleration caused by the applied force on the object.

Therefore,

$F = m * a$

Here, F is magnitude of applied force on car.

Solving as,

$F = 1000 * 0.05\nF = 50 \;\rm N$

Thus, we can conclude that Mike is applying 50 N of force on his car.

learn more about the Newton's second law here:

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Answer 2

Answer:

Answer:

The answer to your question is: F = 50 N

Explanation:

Data

mass = 1000 kg

acceleration = 0.05m/s2

F = ?

Formula

F = m x a

Substitution

F = 1000 kg x 0.05 m/s2 = 50 kgm/s2 = 50 N

Mike is applying a force of 50 N to the car.

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A book is resting on a table. The table is raised on one end to an angle of 15° to the floor. If the book remains at rest, what keeps the book from sliding

Answers

Answer:

Static Friction is acting upon the book

A particle is being accelerated through space by a 10 N force. Suddenly the particle encounters a second of 10 N force in the opposite direction. The particle with both forces acting?

Answers

Answer:

The particle will be rendered still

Explanation:

The particle will be rendered still because of the Newton’s 1st law of motion states that a body will continue to move on forever until contacted by an equal and opposite force. The same case has been produced here and it is justifying the law. If the Force has another direction and magnitude than 10 N then the body will continue to move on in the direction of the greater force.

Which of the following scenarios would cause a sound to stop being produced?A. A molecule moves through its normal position to the opposite side of its normal position.
B. A molecule moves in the same direction as a wave.
C. The vibration results in a molecule moving vertically.
D. The vibration of the point in the medium ends.

Answers

The scenario that would cause a sound to stop being produced is when a molecule moves through its normal position to the opposite side of its normal position. The answer is letter A. This is also known as destructive interference.

D. The vibration of the point in the medium ends.

Help me with this problem please? c:Which appliance uses more energy?

A.) a 30-watt CD player used for 3 hours (10,800 seconds)
B.) a 300-watt blender used for 2 minutes (120 seconds)
C.) a 1,500-watt hair dryer used for 3 minutes (180 seconds)
D.) a 200-watt computer used for 10 hours ( 36,000 seconds)

Answers

30*3*60=5400
300*2=600
1500*3=4500
200*10*60=120000

the computer uses more energy.
(you can multiply all results by 60 to get the energy in J, but it's not necessary for the comparison)

Answer:

a 200-watt computer used for 10 hours ( 36,000 seconds)

Explanation:

Two objects with different masses collide and bounce back after an elastic collision. Before the collision, thetwo objects were moving at velocities equal in magnitude but opposite in direction. After the collision,
A. the less massive object had gained momentum.
B. the more massive object had gained momentum.
C. both objects had the same momentum.
D. both objects lost momentum.

Answers

The more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

Let the mass of the first object = m₁
Let the mass of the second object = m₂
let the initial velocities of the two objects = u
let the final velocity of the first object after collision = v₁
Let the final velocity of the second object after collision = v₂

Apply theprinciple of conservation of linear momentum for elastic collision;

let the heavier object = m₁

m₁u + m₂(-u) = m₁(-v₁) + m₂v₂

m₁u - m₂u = -m₁v₁ + m₂v₂

where;

m₁u and m₂u are initial momentum of both objects before collision

m₁v₁ and m₂v₂ are final momentum of both objects after collision

Thus, from the equation above we can conclude the following, the more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

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Answer:A

Explanation:

Given

mass of two objects are $m_1$ and $m_2$

taking $m_1>m_2$

Suppose $u_1$ and $u_2$ are the velocities of $m_1$ and

$u_1=u$ and $u_2=-u$

therefore after elastic collision velocity of $m_1$ and $m_2/[tex] are [tex]v_1$ and $v_2$

$v_1=(m_1-m_2)/(m_1+m_2)\cdot u_1+(2m_2)/(m_1+m_2)\cdot u_2$

$v_2=(2m_1)/(m_1+m_2)\cdot u_1-(m_1-m_2)/(m_1+m_2)\cdot u_2$

for $u_1$ and $u_2$

$v_1=(m-m)/(m+m)\cdot u+(2m)/(m+m)\cdot (-u)$

$v_1=(m_1+m_2)/(m_1+m_2)\cdot u=u$

$v_2=(2m)/(m+m)\cdot u-(m-m)/(m+m)\cdot (-u)$

$v_2=(3m_1-m_2)/(m_1+m_2)\cdot u$

$v_2=u+2\cdot (m_1-m_2)/(m_1+m_2)\cdot u$

so velocity of mass $m_2$ is more as compared to $m_1$

so less massive object gained some momentum

Of waterfalls with a height of more than 50 m , Niagara Falls in Canada has the highest flow rate of any waterfall in the world. The total average flow rate of the falls is 2.80×10³ m³/s and its average height is 52.0 m (Niagara Falls Live, 2017). Given that the density of water is 1.00×10³ kg/m³, calculate the average power output of Niagara Falls.Average power output: _________.

Answers

The height of more than 50 m then the average power output of Niagara Falls will be equal to 426.9 MW.

What is Power?

Power can be defined as the amount of workcompleted in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

Average power is calculated by dividing the total energy used by the total time required. The average quantity of work completed or energy converted per unit of time is known as average power.

The change in potential energy of the falls mostly determines its power output:

Q = -ΔP = -(P2 - P1)

Use the equation of Potential energy:

P = mgh

If we take the base of the falls as the reference height, the height at point 1 is 52 meters, and at point 2 h=0, P2=0,

Q = P1 = mgh

The rate of change in potential energy over time can be calculated by substituting the mass rate M for m. As a result, the power produced:

W = mgh

W = 2.8 × 10³ × 1 × 10³ × 9.8 × 52

W = 1426.9 MW.

To know more about Power:

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Answer:

Power output: W=1426.9MW

Explanation:

The power output of the falls is given mainly by its change in potential energy:

$Q=-P_(tot)=-(P_(2)-P_(1))$