How is the motion of P waves different from the motion of S waves?

Answers

Answer 1

Answer: S waves travel slower than P waves.

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Every 6 seconds a pendulum completes one cycle. What are the period and frequency of this pendulum?

Answers

The period is the time it takes any repeating process
to complete one cycle. You just told us what it is for the
pendulum . . . 6 seconds.

The frequency is the reciprocal of the period. For the pendulum,
that's

1 / (6 sec) = (1/6) per second = 1/6 Hertz .

The period is 2.4 seconds and the frequency is I believe 1/6 I'm not entirely sure since I don't think this question has enough information.

The sun is important to is because of the heat it provides. The sun is just one of ________ of stars in the universe.

Answers

The sun is just one of the uncountable stars in the universe, as there are more than billions of galaxies containing billions of stars.

Polaris, the North Star, is almost always visible in the same location because A) it is the brightest star in the sky. B) it is gravitationally attracted to our sun. C) it is the closest star to the earth, besides our sun. Eliminate D) the axis of the earth passes directly through the North Star.

Answers

The north end of the Earth's axis points almost exactly toward Polaris.
The only time when Polaris is not visible at the same place in the sky
at night is when that part of the sky is cloudy.

Answer D, The axis of the earth passes directly through the north star.

Explanation: I did it on usatestprep

The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it accelerated down a 1.00 m rifle barrel, estimate the average power delivered to it during
the firing. (b) Neglecting air resistance, find the range of this projectile when it is fired
at an angle such that the range equals the maximum height attained.

Answers

Answer:

(a) Power= 207.97 kW

(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, $m=0.02 kg$

Kinetic energy imparted, $K=1200 J$

Length of rifle barrel, $d=1 m$

(a)

Let the speed of bullet when it leaves the barrel is $v$ .

Kinetic energy, $K=(1)/(2) mv^(2)$

$v=\sqrt{(2K)/(m) }$

$=\sqrt{(2*1200)/(0.02) }$

$=346.4m/s$

Initial speed of bullet, $u=0$

The average speed in the barrel, $v_a_v_g=(u+v)/(2)$

$=(0+346.4)/(2) \n=173.2 m/s$

Time taken by bullet to cross the barrel, $t=(d)/(v)$

$=(1)/(173.2)\n =0.00577 second$

Power, $P_a_v_g=(W)/(t)$

$=(1200)/(0.00577) \n=207.97kW$

(b)

In projectile motion,

Maximum height, $H_m=(v^2\sin^2\theta)/(2g) \n$

Range, $R=(v^2\sin2\theta)/(g)$

given that, $H_m=R$

then, $(v^2\sin^2\theta)/(2g)=(v^2\sin2\theta)/(g)\n\sin^2\theta=2\sin\theta\cos\theta\n\n\tan\theta=4\n\theta=\tan^-^14\n\theta=75.96^0\nR=(v^2\sin2\theta)/(g)\n=(346.4^2*\sin(2*75.96))/(9.8)\n5768.6 meter$

Ladybug walks 10 cm forward and 5 cm backwards in 20 seconds what is the average speed of ladybug what is the average velocity

Answers

Answer:

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

Explanation:

Speed is the ratio of distance and time and velocity is the ratio of displacement and time.

Distance traveled = 10 + 5 = 15 cm = 0.15 m

Displacement = 10 - 5 = 5 cm = 0.05 m

Time = 20 seconds

$\texttt{Average speed = }\frac{\texttt{Distance}}{\texttt{Time}}\n\n\texttt{Average speed = }(0.15)/(20)=7.5* 10^(-3)m/s\n\n\texttt{Average velocity = }\frac{\texttt{Displacement}}{\texttt{Time}}\n\n\texttt{Average velocity = }(0.05)/(20)=2.5* 10^(-3)m/s$

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

Hey!

---------------------------------------------------

Formula: Distance / Time = Speed

---------------------------------------------------

Solution:

Speed = 15/20 = 0.75cm/sec

Velocity = 5/20 = 0.25cm/sec

10 + 5 = 15 (distance traveled)

---------------------------------------------------

Answer:

Speed = 0.75cm/sec

Velocity = 0.25cm/sec going forward.

---------------------------------------------------

Hope This Helped! Good Luck!

6) Suppose a student throws a pencil at the wall, and upon hitting the wall, the pencilbreaks in half. What happens to the original momentum of the pencil?

Answers

The originalmomentum of a pencil is distributed equally to the other half of

the pencil.

The pencil breaking into two is as a result of the internalforces acting in

opposite direction which caused the breakage.

The total momentum of a body before collision being equal to the total

momentum of the two objects after collision has occurred which is why the

pencil will have momentum distributed equally in this scenario.

Read more on brainly.com/question/20182620

Answer:

ORIGINAL MOMENTUM OF THE PENCIL GETS DISTRIBUTED TO THE BROKEN HALFS EQUALLY .

Explanation:

GENERALLY :

For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.

The above statement tells us that the total momentum of a collection of objects (a system) is conserved - that is, the total amount of momentum is a constant or unchanging value.

Since the forces between the two objects are equal in magnitude and opposite in direction, and since the times for which these forces act are equal in magnitude, it follows that the impulses experienced by the two objects are also equal in magnitude and opposite in direction.

IN THIS CASE :

(neglecting the impulse and force of gravity)

The net external force on the system is ZERO
The collision and the breakage that happens is PURELY due to the internal force which are equal and opposite.
When we consider the wall and the pencil together as a system , the net external force on the system is zero.
We also assume that the wall is very heavy and thus it remains at rest even after the collision.
Thus , according to the law of conservation of momentum, the pencil must have the same momentum imparted to it initially.
Therefore , the ORIGINAL MOMENTUM OF THE PENCIL GETS DISTRIBUTED TO THE BROKEN HALFS EQUALLY .

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