CHEMISTRY HIGH SCHOOL

How many electrons can the n=4 shell hold?
a. 8
b.16
c.32
d.64

Answers

Answer 1
Answer:

Answer:

             32 Electrons

Explanation:

                    In statement the letter "n" specifies the Principle Quantum Number. Principle Quantum number is main energy level of an atom. Hence, n = 4 means we are talking about the fourth energy level or fourth shell of an atom.

                    Also, the number of electrons present in any main energy level are calculated by using following formula,

                                                         2n²

Hence, as,

                 n = 4

So, by putting this value in above formula,

                                                         2 (4)²

                                                         2 (16)

                                                         32
Answer 2
Answer:

The maximum number of electrons that can be accommodated in the n=4 shell is 32.

(Option C).

How many electrons can the n=4 shell hold?

The maximum number of electrons that can be accommodated in the n=4 shell can be determined using the following formula.

maximum electrons = 2n²

where;

  • n is the orbital level

The given parameters include;

n = 4

The maximum number of electrons that can be accommodated in the n=4 shell is calculated as;

maximum electrons = 2n²

maximum electrons = 2 (4²)

maximum electrons = 32

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You are studying the equilibirum between S8 and S2 gases at 0 celcius, you place a smaple of s2 in an otherwise empty, rigid container at an initial pressure of 3.-0 atm. wher eit reactsto form S8. at equilimrium, the partial pressure of s2 is 2.07 atm. calculate kp and kc.

Answers

Answer:

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Explanation:

Please check document attached.

Which substance will require more energy to heat if all the samples have the same mass and same temperature change?

Answers

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Answers

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1. The speed limit on most city streets is (25 miles). How many meters per minutehour
is this?
This is a conversion.

Answers

Answer:

Speed = 670.56 (m)/(min)

Explanation:

Given

Speed = (25 mi)/(hr)

Required

Convert to meters per minutes

Speed = (25 mi)/(hr)

Start by converting the speed from miles to meters

1\ mile = 1609.34\ meters.

So, we have:

Speed = (25 * 1609.34\ m)/(hr)

Speed = (40233.5\ m)/(hr)

Next, we convert time from hours to minutes

1\ hour = 60\ minutes

So, we have:

Speed = (40233.5\ m)/(60\ min)

Speed = 670.56 (m)/(min)

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All atoms of the same element have the same ____.a. number of neutrons
c. mass numbers
b. number of protons
d. mass

Answers

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Reaction 2 occurs when an excess of 6 M HCI(aq) solution is added to 100. mL of NaOCl(aą) of unknown concentration. If the reaction goes to completion and 0.010 mol of Cl2(g) is produced, then what was the molarity of the NaOCl(aq) solution? (A) 0.0010 M
(B) 0.010 M
(C) 0.10 M
(D) 1.0 M

Answers

The molarity of the NaOCl solution is 0.10M

The correct answer to the question is Option C. 0.10 M

We'll begin by calculating the number of mole of NaOCl required to produce 0.010 mole of Cl₂.This can be obtained as follow:

NaOCl + 2HCl —> Cl₂ + NaCl + H₂O

From the balanced equation above,

1 mole of NaOCl reacted to produce 1 mole of Cl₂.

Therefore

0.010 mole of NaOCl will also react to produce 0.010 mole of Cl₂.

  • Finally,we shall determine the molarity of the NaOCl solution.

Mole of NaOCl = 0.01 mole

Volume = 100 mL = 100 / 1000 = 0.1 L

Molarity of NaOCl =?

Molarity = mole / Volume

Molarity of NaOCl = 0.01 / 0.1

Molarity of NaOCl = 0.1 M

Therefore, the molarity of the NaOCl solution is 0.1 M

Learn more: brainly.com/question/12755239

Answer:

Option C 0.10 M

Explanation:

you are not providing the reaction, but luckily we have data to write the equation. We know that we are taking HCl and NaOCl to produce Cl2, the reaction is as follow:

NaOCl + 2HCl ---------> Cl₂ + NaCl + H₂O

From this reaction, we know that we have excess of acid that is added to 100 mL (0.1 L) of NaOCl, and this produces 0.010 moles of Chlorine.

All we have to do here, is apply stechiometry. We already know that the acid is in excess, so the moles produced would be the moles of the limiting reactant, in this case, the NaOCl.

According to the reaction NaOCl and Cl2 has a mole ratio of 1:1, so the moles of Cl2 would be the same moles that NaOCl lost so:

moles Cl2 = moles NaOCl = 0.010 moles

Then the concentration:

M = 0.010 / 0.1

M = 0.10 M

This is the molarity of NaOCl
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