How can I solve this system of linear equations by substitution 3x-2y=9 and y=2x-7

Answers

Answer 1

Answer: y=2x-7
therfor we can SUBSITUTE 2x-7 for y whereever we see y in the other equation

3x-2(2x-7)=9
3x-4x+14=9
-x+14=9
minus 14 both sides
-x=-5
mulitly -1
x=5

sub back

y=2x-7
y=2(5)-7
y=10-7
y=3

(5,3)

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What is a 15 yard gain

Answers

Are you by any chance referring to football? If you are, it is either a play in which by running or passing the offense moves down the field towards the opponent's endzone 15 yards, or it can be obtained by the defense committing an egregious penalty, such as a facemask, unsportsmanlike conduct, or unnecessary roughness.

What do you divide 32 to get 96

Answers

Answer:

You divide 32 by 1/3.

Step-by-step explanation:

This is because 96/32 equals to 3/1 so the reciprocal of that is what you divide 32 by to get 96.

1/3 is your answer your welcome :)

there are 12 girls and 18 boys in a class. What is the largest number of groups they can be split up into and have the same number of boys and girls on each team?

Answers

They all can be split up to 6 groups because 12+18=30 so each group will have 5 kids in it.

What is 5d=470 and what is 8a=47

Answers

5d=470:

in this case we have to divide both sides by 5:

d=94

8a=47:

in this case we have to divide both sides by 8:

a=5.875

as a general rule, if you want to find out a value of a in
ab=c

you have to divide both sides of the equation by b (if it's not zero); then you will have left:

a=c/b

and if you calculate c/b, this will give you the answer

$5d= 470 \n \n d=470:5 \n \n \boxed{\boxed{d= 94}} \n \n 8a=47 \n \n a=47:8 \n \n \boxed{\boxed{a=5.875}}$

3x + 7y =47
-4x +7y =19

Answers

3x+7y=47
-1(-4x+7y=19)

Distribute the -1 and add the equations together...you'll get:

7x=28
x=4

Plug X=4 back in...
12+7y=47
7y=35
y=5

You exercise for one hour each day and you burn 8.5 calories per minute. If you graphed the number of calories you burned as the output, compared to the number of minutes you exercise as input, what would the graph look like? Which of the following would not be true?A.The graph would be a line.
B.The graph would rise from left to right.
C.The graph would be only in the first quadrant.
D.The larger the number of minutes, the fewer calories you would burn.

Answers

In a graph, the general rule is that the output is the y axis and the input is the x axis. Therefore, we can say that the number of calories burned will be along the y axis and the minutes will be along the x axis.

(A) The graph would be a line.
This would be true, because you are burning calories at a steady rate. This means that the graph will also be increasing steadily, rather than dropping randomly.

(B) The graph would rise from left to right.
This would be true, because your graph will be increasing positively. If it rose right to left, that would mean the more time passed, the less calories burned.

(C) The graph would be only in the first quadrant.
This would be true, because your graph, as said before, will be increasing positively. At the rate you're going at, it isn't possible to burn negative calories or spend a negative amount of time exercising.

(D) The larger the number of minutes, the fewer calories you would burn.
This would be false, because you burn 8.5 calories per minute. This indicates that the more time passed, the more calories you will burn. In order for it to be true, 8.5 would have to be negative.

The picture attached is an idea of what the graph would look like.

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