Three resistors are connected in series across a battery. The value of each resistance and its maximum power rating are as follows: 6.7Ω and 15.9 W, 30.4Ω and 9.12 W, and 16.3Ω and 12.3 W. (a) What is the greatest voltage that the battery can have without one of the resistors burning up? (b) How much power does the battery deliver to the circuit in (a)?

Answers

Answer 1
Answer:

Answer:

a) greatest voltage = 29.25 V

b) power = 16 W

Explanation:

The total resistance R of the three resistors in series is:

R = (6.7 + 30.4 + 16.3) \Omega = 53.4 \Omega  

a) The greatest current I is the one that will burn the resistor with lower power rating, which is 9.12 W:

P_(max) = I_(max)^2 R = I_(max)^2 30.4\Omega = 9.12W\nI_(max) = 0.54 A

The voltage is:

V_(max)=IR = 0.54*53.4V= 29.25 V

b) When the current is 0.54 A, the power is:

P = RI^2=53.4*0.3 W = 16W


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A body with initial velocity 8.0 m/s moves along a straight line with constant acceleration and travels640 m in 40 s. For the 40 s interval, find (a) the average velocity, (b) the final velocity, and (c) the
acceleration.​

Answers

Answer:

(a) The average velocity is 16 m/s

(b) The acceleration is 0.4 m/s^2

(c) The final velocity is 24 m/s

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity (or the speed) of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, final speed is calculated as follows:

v_f=v_o+at\qquad\qquad [1]

The distance traveled by the object is given by:

\displaystyle x=v_o.t+(a.t^2)/(2)\qquad\qquad [2]

(a) The average velocity is defined as the total distance traveled divided by the time taken to travel that distance.

We know the distance is x=640 m and the time taken t= 40 s, thus:

\displaystyle \bar v=(x)/(t)=(640)/(40)=16

The average velocity is 16 m/s

Using the equation [1] we can solve for a:

\displaystyle a=(v_f-v_o)/(t)

(c) From [2] we can solve for a:

\displaystyle a= 2(x-v_ot)/(t^2)

Since vo=8 m/s, x=640 m, t=40 s:

\displaystyle a= 2(640-8\cdot 40)/(40^2)=0.4

The acceleration is 0.4 m/s^2

(b) The final velocity is calculated by [1]:

v_f=8+0.4\cdot 40

v_f=8+16=24

The final velocity is 24 m/s

Final answer:

The average velocity is 16 m/s, the final velocity is 8.0 m/s + (acceleration * 40 s), and the acceleration can be found by solving the equation 640 m = (8.0 m/s * 40 s) + (0.5 * acceleration * (40 s)^2.

Explanation:

To find the average velocity, we use the formula: average velocity = total displacement / total time. In this case, the total displacement is 640 m and the total time is 40 s, so the average velocity is 640 m / 40 s = 16 m/s.

To find the final velocity, we can use the formula: final velocity = initial velocity + (acceleration * time). In this case, the initial velocity is 8.0 m/s and the time is 40 s. Since the question states that it moves with constant acceleration, we can assume that the acceleration is the same throughout the 40 s interval. Therefore, the final velocity is 8.0 m/s + (acceleration * 40 s).

To find the acceleration, we can use the formula: total displacement = (initial velocity * time) + (0.5 * acceleration * time^2). In this case, the total displacement is 640 m, the initial velocity is 8.0 m/s, and the time is 40 s. Solving for acceleration, we have 640 m = (8.0 m/s * 40 s) + (0.5 * acceleration * (40 s)^2).

Learn more about Average velocity, Final velocity, Acceleration here:

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A container has a large cylindrical lower part with a long thin cylindrical neck open at the top. The lower part of the container holds 22.8 m^3 of water and the surface area of the bottom of the container is 9.10 m^2. The height of the lower part of the container is 2.50 m, and the neck contains a column of water 8.50 m high. The total volume of the column of water in the neck is 0.200 m^3.(a) What is the magnitude of the force exerted by the water on the bottom of the container? (b) Explain why it is not equal to the weight of the water.

Answers

Answer:

(a) 1045.5 KN

(b) 225.63 KN

Explanation:

Since Pressure, P=\frac {F}{A} where F is force exerted and A is area of the bottom of container

Making F the subject then

F=PA

Height of container=8.5m+2.5m=11.0 m

Density of water \rho_(water)=1000 Kg/m^(3)

Surface area of the bottom of the container is 9.10 m^(2)

Pressure at the bottom of container

P=P_(atm)+h\rho_(water) g where P_(atm) is atmospheric pressure taken as 101.3*10^(3) Kg/m.s^(2), h is height which is 11 m, \rho_(water) is density of water and g is acceleration due to gravity which is taken as 9.81 m/s^(2)

P=101.3*10^(3) Kg/m.s^(2) +11m*1000 Kg/m^(3) *9.81 m/s^(2)=209.1*10^(3) Kg/m.s^(2)

Force exerted is then found by

F=PA=209.1*10^(3) Kg/m.s^(2)*5 m^(2)=104.55*10^(4) N

Therefore, force at the bottom is 1045.5 KN

(b)  

Volume of container at lower part is given as 22.8 cubic meters hence mass of water =volume*density of water

Mass=22.8*1000=22800 Kg

Volume of water confined in the column is 0.2 cubic meters hence the mass of water confined in the column is 0.2*1000=200 Kg

Total mass=200+22800=23000 Kg

Weight of water, W=mg=23000*9.81=225630 N=225.63 KN

Therefore, the weight of water is less than force applied at the bottom of container since pressure exerted by atmosphere on the surface of water is considered during calculation of force exerted at the bottom of the container

While the block hovers in place, is the density of the block (top left) or the density of the liquid (bottom center) greater?

Answers

Answer:

for the body to float, the density of the body must be less than or equal to the density of the liquid.

Explanation:

For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.

Weight is

        W = mg

let's use the concept of density

        ρ_body = m / V

        m = ρ_body V

        W = ρ_body V g

The thrust of the body is given by Archimedes' law

        B = ρ_liquid g V_liquid

 

as the body floats the submerged volume of the liquid is less than or equal to the volume of the block

       ρ_body V g = ρ_liquid g V_liquid

     

       ρ_body = ρ liquid Vliquido / V_body

As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.

A toy car is tied to a string and pulled across a table horizontally. Which is thecorrect free-body diagram for this situation?
T
FN
FN
T
FN
EN
T
W
W
W
w
А
B
С
D
Ο Α. Α

Answers

y axis:NandW and also f x axis:T and F T away from car.

Which of the following wouldhave low electromagnetic
energy?
A. X-rays
B. ultraviolet waves
C. radio waves

Answers

Final answer:

Radio waves have low electromagnetic energy compared to X-rays and ultraviolet waves.


Explanation:

Electromagnetic energy refers to the energy associated with electromagnetic waves, which are a form of energy that can travel through empty space. The energy of an electromagnetic wave is directly proportional to its frequency. Therefore, the frequency determines the energy level of the wave.

In the given options, radio waves would have the lowest electromagnetic energy. Radio waves have the longest wavelength and lowest frequency among the three options. X-rays, on the other hand, have a higher frequency and shorter wavelength, making them more energetic. Ultraviolet waves have an even higher frequency and shorter wavelength, making them the most energetic among the three options.


Learn more about Electromagnetic energy here:

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Please help really easy

Answers

Answer:

I am sure it is A because no chemical change occurs and it is a physical change.  If you can Brainllest than that would be great but if you wanna you don't have to. Hope this helps!! If wrong sorry.

Explanation: