A garden box has a perimeter of 27 1/2 feet. If the length is 9 feet ,what is the area of the garden box?
Answers
Data:
Perimeter= 27 1/2 ft=27.5 ft
lenght=9 ft
1)we have to calculate the width.
27.5 ft=2(9 ft)+2 width
27.5 ft=18 ft + 2 width
2 width=27.5 ft-18 ft
2 width=9.5 ft
width=9.5/2=4.75 ft
2) we calculate the area
area of a rectangle=length x width
area of this rectangle=9 ft * 4.75 ft=42.75 ft²,
answer: the area of the garden is 42.75 ft² (=42 3/4 ft²).
27 and 1/2=P=27.5
L=9
27.5=2(9+W)
divide bot hsids by 2
13.75=9+w
minus 9
4.75=W
area=LW
area=9*4.75
area=42.75
ara=42 and 3/4 feet^2
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See the attachment below for questions.
Answers
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Answers
x = the length of one piece
y = the length of the other piece
the total length is 100 cm this means
x + y = 100
one piece is 16 inches longer than the other
first we need to convert inches to cm:
1 in = 2.54 cm
16 in = 2.54*16 = 40.64
now we can write
x = y + 40.64
by solving the system of equations
x + y = 100
x = y + 40.64
we find
x = 70.32 cm
y = 29.68 cm
the lengths of the two pieces are 70.32 cm and 29.68 cm.
Answers
Answers
Answer:
Step-by-step explanation:
A linear equation in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A quadratic equation, on the other hand, involves one of the variables raised to the second power. It has the general form y = ax2 + bx + c
13.012 + 8.9 + 3.09
Equal
Ppl PLZ HELP MEH
Answers
the answer is 25.221