What is gravity at north pole, South pole and at different point on the equatorial regions. Give reasoning for your answers why do you think it is different or same. Can you imagine same concept for the electric charge, yes or No

Answers

Answer 1
Answer:

Answer:

The gravity at Equator is 9.780 m/s2 and the gravity at poles is 9.832 m/s2. The gravity at poles are bigger than at equator, principally because the Earth is not totally round. The gravity is inversely proportional to the square of the radius, that is the reason for the difference of gravity (The radius at Poles are smaller than at Equator).

If Earths would have a net charge Q. The Electric field of Earth would be inversely proportional to the square of the radius of Earth (Electric field definition for a charge), the same case as for gravity. So there would be a difference between the electric field at poles and equator, too.


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A small child weighs 60 N. If mommy left him sitting on top of the stairs, which are 12 m high, how much energy does the child have!Please help ASAP

Answers

Answer:

6000 joules

Explanation:

I jus learned dis

Answer:6000j

Explanation:

Hope that helps

What is the angular width of a person's thumb viewed at arm's length? Assume that the width of the thumb is 17.3 mm and that the distance between the eyes and the thumb is 71.9 cm. Use the small-angle approximation and then convert the answer to degrees.

Answers

Answer:

\theta_(degrees) =0.024\°=0\°1'26.62''

Explanation:

To solve the problem it is necessary to take into account the concepts related to arc length and the radius that make up the measurements of an angle.

An angle is given by the length of arc displaced as a function of the radius, that is

\theta = (Arc_(length))/(Radius)

\theta = (17.3*10^(-3))/(71.9*10^(-2))

\theta = 0.02406rad

360° is equal to do 2\pi rad, therefore:

\theta_(degrees) = 0.02406rad *((180\°)/(2\pi rad))

\theta_(degrees) =0.024\°=0\°1'26.62''

A radioactive nucleus has a half-life of 5*108 years. Assuming that a sample of rock (say, in an asteroid) solidified right after the solar system formed, approximately what fraction of the radioactive element should be left in the rock today? The age of the solar system is 4.5*109 years. (No calculator is necessary, but if it helps use it.)

Answers

Answer:

0.002

Explanation:

The half-life of the radioactive nucleus is related to its quantity, by the following equation:

N_(t) = N_(0)2^{-t/t_(1/2)}

Where:

N(t): is the quantity of the radioactive nucleus at time t

N₀: is the  initial quantity of the radioactive nucleus

t: is the time = 4.5x10⁹ years

t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years

(N_(t))/(N_(0)) = 2^{-4.5 \cdot 10^(9) y/5 \cdot 10^(8) y} = 2 \cdot 10^(-3)

Therefore, the fraction of the radioactive element in the rock today is 0.002.

I hope it helps you!  

A revolutionary war cannon, with a mass of 2260 kg, fires a 21 kg ball horizontally. The cannonball has a speed of 105 m/s after it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired?

Answers

Answer:

0.97566 m/s

Explanation:

m_1 = Mass of cannon = 2260 kg

v_1 = Velocity of cannon

m_2 = Mass of ball = 21 kg

v_2 = Velocity of ball = 105 m/s

As the momentum of the system is conserved we have

m_1v_1=m_2v_2\n\Rightarrow v_1=(21* 105)/(2260)\n\Rightarrow v_1=0.97566\ m/s

The velocity of the cannon is 0.97566 m/s

A pilot performs an evasive maneuver by diving vertically at 270. If he can withstand an acceleration of 9.0 's without blacking out, at what altitude must he begin to pull out of the dive to avoid crashing into the sea? y= ?m

Answers

Answer:

The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

Explanation:

Given that,

Velocity = 270 m/s

Acceleration = 9.0g s

We need to calculate the altitude

Using formula of centripetal acceleration

a_(c)=(v^2)/(r)

r=(v^2)/(a_(c))

Where, v = velocity

r = altitude

a = acceleration

Put the value into the formula

r=(270^2)/(9.0*9.8)

r=826.53\ m

Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

Why Coulomb force is called "Mutual Force"???????????????????????????????????????

Answers

Answer

The Columb's law is the same as Gravitational law

Explanation

As we see the formula of both Coulomb and Gravitational Law,

F_g = GM_1M_2/R_2     (1)

F_c = kq_1q_2/r_2         (2)

The masses (M) in formula (1) experiencing the force of gravitational pull with each other which varies with changing the distance. In the formula (2), the charges also are felling the forces on each other which varies with distance. The charges and masses are just like the objects which are experiencing the forces which have a common factor as distance. The gravitational force is also called the mutual forces.