NEED HELP ASAP , I’d appreciated it!!

Answers

Answer 1

Answer: the scale ratio should be 3 to 1

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At a restaurant, your food bill was $80, and you left a tip of $16. What percentage of the food bill did you leave for the tip?5%16%20%80%
Expand the brackets and simplify a. 5(x+4) + 2(x+3)b. 3(y+6) + 4(y-5)
1/6 of a ship's crew are engineers, 1/4 are stewards and the rest are soldiers. if there are 48 crew members in all, how many sailors are on the board of the ship?
Which expression can be used to find the value of the expression below?
The figure is made up of two identical squares and has a perimeter of 42 inches. What is the area of one square?

A $300 tablet is on sale for $234. what is the percent of discount ?

Answers

I like to think of these like this.

What was the amount of the discount? 300 - 234 = $66 dollars.

66 is to 300 as ? is to 100?

This is how that question looks in an equation:

66/300 = x/100 Solve for x by cross multipying.

66 x 100 = 300 x

660 = 300 x

x = 22

The discount amount on the tablet is 22% off the regular price.

Check it!

300 x .22 = $66 dollars off. 300 - 234 = $66 off.

Yes! It checks.

Choose the function whose graph is given below.

Answers

Answer:

D. y = cot x

Step-by-step explanation:

Answer:

The correct answer is D) cot(x)

Step-by-step explanation:

We can tell this by the placement of the asymptotes. Each of them (0, pi 2pi, etc) are all at points where tan(x) = 0. As a result, we know that these would not exist on the graph of cot(x) since it is the inverse of tan(x)

What are all the common factors of 24 and 44? A. 1, 2

B. 1, 2, 4

C. 1, 2, 4, 8

D. 1, 2, 4, 12

Answers

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

Factors of 44: 1, 2, 4, 11, 22, 44

Factors that are common to 24 and 44: 1, 2, 4

Your answer is B.

The perimeter of a rectangle is 30 inches. If it's length is three times it's width, find the dimensions. Show work if possible.Next, a volleyball coach plans her daily practices to include 10 minutes of stretching, 2/3 of the entire practice scrimmaging, and the remaining practice time working on drills. On Wednesday, the coach planned 100 minutes of stratching and scrimmaging. How long, in hours, is the entire practice? Show work if possible.

Homework due tommorrow......PLEASE HELP!!!!!

Answers

The rectangle problem:

First, create some variables.
w = width
l = length

Then you know that the length is 3 times the width, so
l = 3w

The equation for perimeter is
P = 2(l+w)

Now you use substitution, substituting the 3w for l because you found that earlier.

P = 2((3w) + w)

And simplify.
P = 2(4w)
P = 8w

And you know P = 30 because they told you that.
30 = 8w
w = 15/4 inches, or 3.75 inches

Now substitute that value back into that first equation,
l = 3w
l = 3(15/4)
l = 45/4 inches, or 11.25 inches.

The dimensions are 11.25in for length and 3.75in for width.

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The volleyball problem:

100 minutes of stretching and scrimmaging combined, and you know 10 have to be stretching, so 90 is scrimmaging.

s = scrimmaging
T = total time

s = 2/3T (they gave you this)
90 = 2/3T
T = (90*3)/2
T = 270/2
T = 135 minutes, or 2 hours and 15 minutes.

How many eighths are in 5 5/8?

Answers

45/100 or 9/20 because:
5 5/8=5.625 and 1/8=0.125 and 5.625/0.125=45
and 45 as a fraction is 45/100 or 9/20

8/8 are in one whole number. 8 × 5 = 40. 5/8 (from the fraction) 40 + 5 = 45 45 "8"'s

The soccer league needs to transport all 133 players to the tournament if 4 players can ride in one car how many cars are needed...PLZ HELP ALSO I NEED TO SHOW MY WORK

Answers

You would need 34 cars.
133/4 = 33.25
Since you cannot have 33.25 cars, you can have 34 cars.
34 * 4 = 132.
This means that one of the players is going to ride alone, whereas in all of the other cars there will be 4 players.

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