What role do aquifers play in the water cycle

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Answer 1
Answer: A aquifer is the underground layer which is composed of water-bearing rocks. Sandstone, sands, gravel, and other sedimentary rocks are examples of water-bearing rocks. They are permeable and have openings that gases and liquids can pass through. In a water cycle, a water will be added to the aquifer during the precipitation.

Related Questions

A hot air balloon is filled with of an ideal gas on a cool morning ( The air is heated to What is the volume of the air in the balloon after it is heated? Assume that none of the gas escapes from the balloon.
Which scientist is credited with developing the first scientific atomic theory?
Which phase change absorbs energy? A. H2O (g) --> H2O (s) B. H2O (g) --> H2O (l) C. H2O (l) --> H2O (g) D. H2O (l) --> H2O (s)
An experimental procedure requires 10 ml of acid to be dissolved into a beaker of water. An additional 5 ml of acid is added to the solution. Which statement best describes the new solution?
Calculate the number of atoms of carbon in 3.8 moles of methane (CH4)

Element X has five valence electrons, element Y has one valence electron, and element Z has five valence electrons. Which two of these elements are most likely to have similar properties? Explain your answer

Answers

Explanation:

It is known that elements which contain same number of valence electrons when present in their neutral state then they tend to show similar chemical properties.

This is because only the valence electrons actively participate in a chemical reaction. As a result, these valence electrons determine their reactivity.

This is why, elements of same group tend to show similar chemical properties.

For example, element X and element Z have same number of valence electrons.

Therefore, we can conclude that both elements X and Z are most likely to have similar properties.

X and Z- because they have the same amount of valance electrons they will be in the same column of the periodic table and elements of the columns have similar properties. 

Mercury has a specific gravity of 13.6. how many milliliters of mercury have a mass of 0.35 kg

Answers

The formula for specific gravity is:

Specific gravity = (\rho _(substance))/(\rho _(water))

where \rho _(substance) is the density of the substance and \rho _(water) is the density of water.

The density of water, \rho _(water) = 1 g/mL

Substituting the values in above formula we get,

13.6 = (\rho _(substance))/(1)

\rho _(substance) = 13.6 g/mL

The formula of density is:

density = (mass)/(volume)

The density of mercury is 13.6 g/mL

The mass of mercury is 0.35 kg = 0.35 kg * 1000 (g)/(kg) = 350 g

Substituting the values in density formula:

13.6 g/mL = (350 g)/(volume)

volume = (350 g)/(13.6 g/mL) = 25.73 mL

The amount, in milliliters, of mercury that will have a mass of 0.35 kg would be 25.74 mL.

If the specific gravity of mercury is 13.6, the density can be obtained such that:

Density of mercury = specific gravity of mercury/density of water

The density of water is 1 g/mL. Thus:

Density of mercury = 13.6/1

                              = 13.6 g/mL

Also; density = mass/volume

       volume = mass/density

                    = 350/13.6

                       = 25.74 mL

Thus, the number of milliliters of mercury that will have a mass of 0.35 kg would be 25.74.

More on density can be found here: brainly.com/question/14940265?referrer=searchResults

How many grams are in 2.4 moles of sulfur?

Answers

According to the mole concept, there are 76.94 g in 2.4 moles of sulfur atoms.

What is a mole?

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Mass is found out by number of moles by formula , mass=number of moles×molar mass

Substitution in above formula gives, mass=2.4×32.06=76.94 g

Thus, there are 76.94 g in 2.4 moles of sulfur.

Learn more about mole,here:

brainly.com/question/26416088

#SPJ6

Use the equation 
Given molesX Molar Mass(g)/1 mol= Mass in grams
2.4 moles X 32.065/1
76.96 Grams :)

For every liter of sea water that evaporates, 3.7 g of magnesium hydroxide are produced. How many liters of sea water must evaporate to produce 5.00 moles of magnesium hydroxide?

Answers

The liters of sea water must evaporate to produce 5.00 moles of magnesium hydroxide - 78.8 litres.

A mole is a special unit of quantity of a chemical species that contains exactly Avogadro's number of particles.

  • The mass of one mole of an element or a compound, called the molar mass, can be found from a periodic table.
  • The unit of molar mass is g/mol.

=> the molar mass of Mg(OH)₂

Mg + 2O + 2H

= (24.31) + (2×16) + (2×1.01)

= 58.33 gmol⁻¹.

then,

=> the number of moles:

n = m/M

= (3.7)/(58.33)

= 0.0634 mol

=> the amount of water in liters needed to evapourate to produce 5.00 moles:

=> (0.0634)/(1L) = (5)/( x L)

=> 0.0634x = 5×1

=> x = (5)/(0.0634)

=> x = 78.8 litres.

Thus, the liters of sea water must evaporate to produce 5.00 moles of magnesium hydroxide - 78.8 litres.

learn more:

brainly.com/question/21911991

We can use Algebra and ratios to find this value, but first we must convert 3.7g to moles.

First we find the molar mass of Mg(OH)₂
Mg + 2O + 2H = 24.31 + 2×16 + 2×1.01 = 58.33 gmol⁻¹.

Then find the number of moles: n = m/M = 3.7 / 58.33 = 0.0634 mol

So now we know that 0.0634 mol are produced per litre of sea water.
Let the amount of water in litres needed to evapourate to produce 5.00 moles be x.

We can express this as a ratio.

0.0634 mol / 1 l = 5 mol / x l.
Solve for x by cross-multiplication:
0.0634x = 5×1
x = 5/0.0634 = 78.8 litres. (rounded to three significant figures)

Hope this helps!

Which notion is incorrect?A. Dispersion forces are present in all molecular substances.
B. The greater the dipole moment, the stronger the dipole-dipole forces.
C. The polarizability of elongated molecules is greater than that of compact, more spherical molecules.
D. London dispersion forces weaken in the order Xe < Kr < Ar
E. Hydrogen bonding leads to the strongest intermolecular forces.

Answers

Answer:

D.  London dispersion forces weaken in the order Xe < Kr < Ar is an incorrect order,  the correct order of  London dispersion forces weaken in the order Ar < Kr < Xe.

Explanation:

A. Dispersion forces are present in all molecular substances.

is a correct statement London dispersion forces are weak intermolecular forces found in all molecular substances.

B. Clearly, greater the dipole moment, greater will be dipole-dipole forces. Hence true.

C) The polarizability of elongated molecules is greater than that of compact, more spherical molecules. The more elongated the molecule is more will be its ability to get polarized.

D.  London dispersion forces weaken in the order Xe < Kr < Ar is an incorrect order,  the correct order of  London dispersion forces weaken in the order Ar< Kr < Xe.

E) Hydrogen bonding leads to the strongest intermolecular forces is also a correct statement. Hydrogen bonding leads to increase in boiling point.

Which of the following is physical change a. Corrosion
b. explosion
c. Evaporation
d. rotting of food ***

Answers

rotting food
hope this helps
all of the above corrosion, explosion, evaporation and rotting food all have physical change in different aspects