MATHEMATICS HIGH SCHOOL

Joe, Keitaro, and Luis play tennis. To decide who will play against each other in the first match, they put their names in a hat and choose two names without looking.What subset, A, represents the complement of the event in which Joe plays in the first match?

A = {KL}

A = {KJ, KL}

A = {KL, LK}

A = {KJ, KL, LJ}

Answers

Answer 1

Answer:

Answer: First Option is correct.

Step-by-step explanation:

Since we have given that

There are three person : Joe, Keitaro, Luis.

And two names will be selected for he game .

Possible events will be

$\{JK,JL,KL\}$

But we want to find the complement of the event in which Joe plays in hte first match,

As we know that complement of any events means eliminate that event from the universal set.

Event of getting Joe plays in the first match is given by

$\{JK,JL\}$

So, complement of this event that Joe plays in the first match is given by

$\{KL\}$

so, First Option is correct.

Answer 2

Answer: The possible events are:

{JK, JL, KL}

The events where J does not play (the first game) are: {KL}

Answer: A = {KL}

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What is 1/3 written as a decimal?
O 0.45
O 0.8
O 0.8
O 4.5

Answers

Hey there!

In order to convert a fraction to a decimal you have to DIVIDE the NUMERATOR (the TOP number) by the DENOMINATOR (the BOTTOM number).

The formula is:

a/b

= a ÷ b

= c

Whereas, “a” is your numerator, “b” is your denominator, & “c” is your decimal

Now that we have that information out the way we can answer your question.

4/5

= 4 ÷ 5

= 0.80

Therefore, your answer is: Option B. 0.8

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

0.80

Step-by-step explanation:

4/5 as a decimal is 0.80

Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing? (–∞, 1.5)

(–∞, 10.25)

(1.5, ∞)

(10.25, ∞)

Answers

The answer for this question is (-infinity,1.5) because
when f(x) is increasing f'(x) > 0
-2x + 3 > 0
-2x > -3
x< 3/2 or 1.5

Answer:

Step-by-step explanation:

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

Answers

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

Answer:

-0.3 Or 3.3

Step-by-step explanation:

-2y^2 + 6y + 2 = 0

X = -6 + 7.21/-4 or -7 - 7.21/-4

X = -0.3 or X = 3.3

Please help me with this

Answers

Answer: 312 balcony seats and 396 ground seats

Step-by-step explanation:

Multiplying the second equation by 10, we get 10b+10g=7080.

Subtracting this from the first equation, we get that 5b = 1560, and thus b=312.

Thus, g=396.

Brownies are now on sale. Each brownie costs $0.20 less than the original price. Right now, if you buy 8 of them it will cost $15.20

Answers

Answer: The original price of brownie was $2.1 each.

Step-by-step explanation:

since we have given that

Let the original price will be x

Number of brownie purchased = 8

According to question , each brownie costs $0.20 less than the original price.

So, it becomes

$8* (x-0.20)=\$15.20\n\n8x-1.6=15.20\n\n8x=15.20+1.60\n\n8x=16.8\n\nx=(16.8)/(8)\n\nx=\$2.1$

Hence, the original price of brownie was $2.1 each.

You drive 6.0 km at 50 km/h and then another 6.0 km at 90 km/h. Your average speed over the 12 km drive will be _________

Answers

Answer:

$64.29\ (km)/(h)$

Step-by-step explanation:

hello

the speed is the relation between a distance traveled and the time used for it and it is given by the equation

$v =(displacement)/(time)\n (1)v=(d)/(t)$

Now, the average speed will be

$v_(average) =(displacement\ total)/(total\ time)\n (1)v=(d)/(t) \n(2)v_(average)=(d_(t) )/(t_(t) )$

Step 1

I drive 6.0 km at 50 km/h

from (1) it is possible to isolate t

$(1)v=(d)/(t)\nt=(d)/(v)$

Let

$v=50 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(50 (km)/(h))\nt_(1)=0.12\ hours\n$

Step 2

then I drive 6.0 km at 90 km/h

$v=90 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(90 (km)/(h))\nt_(2)=0.067\ hours\n$

Step 3

FInd total time and total displacement

$Total\ time=t_(1) +t_(2) \nt_(t) =0.12\ hours +0.067\ hours =0.187\ hours\n\ntotal\ distance\ =d_(1) +d_(2)=6.0\ km +6.0\ km= 12\ km\n$

step 4

finally, put these values into the equation(2)

$v_(average)=(d_(t) )/(t_(t) )\nv_(average)=(12\ km )/(0.187\ h )\nv_(average)=64.29\ (km)/(h)$

V=64.29 km/h

Have a good day

Answer:

64.2857 km/h

Step-by-step explanation:

Time taken to drive the first 6.0 km in hours = 6/50

Time take to drive another 6.0 km in hours = 6/90

Total time taken to drive 12 km in hours = (6/50) + (6/90)

= 6(50+90)/50x90

= 6x140/50x90

= 840/4500

The average speed over the 12 km is therefore 12 divided by 840/4500

= (12 x4500)/840

= 64.2857 km/h

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