A plane flew 1,000 miles away from London for one flight. For the next flight, it flew 500 miles toward London. How far was the plane from London after the second flight?

Answers

Answer 1

Answer: So, It First Flew 1000 Miles Away. So, It Is Positive 1000 Miles. Now, It Flew 500 Miles Closer, So Negative (closer) Distance. So, Add. 1000+(-500)
Adding Negative Is The Same As Subtracting So, 1000-500 = The Distance.
So, The Distance Away Is 500 Miles.

Answer 2

Answer:

Answer:

500 miles

Step-by-step explanation:

Hope this helps!

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8 pencels cost 3.44 whates the unit rate of one pencil

Answers

The unit rate of one pencil is $0.43
3.44/8=0.34

One pencil costs $0.43, you just divide 3.44 by 8

Solve the equation: 1/4 + w = 6 1/3

Answers

$(1)/( 4)+w= 6(1)/(3) \ \ |(-(1)/(4))\n \n (1)/( 4)-(1)/(4)+w= 6(1)/(3)-(1)/(4)\n \nw= 6(4)/(12)-(3)/(4)\n \nw=6(1)/(12)$

1/4 + w = 6 1/3
- 1/4 - 1/4
------------------
w = 6 1/12

If h(x) = −2x − 10, find h(−4). (1 point) −2 −18 −3 −16

Answers

Use the substitution method

h(x) = −2x −10

h(-4)= -2(-4)-10

Multiply first then do -10

8-10

h(-4)= -2

Answer : h(-4)= -2 : first choice

Answer:

answering so you can give the other person branliest

Step-by-step explanation:

3(5x+2)=2(3x-6)

What is the answer, with shown work, please

Answers

Answer:

X=-2

Step-by-step explanation:

3(5x+2)=2(3x+6)

15x+6=6x-12

-6 -6

15x=6x-18

-6x -6x

9x=-18

x=-2

When the width of a rectangle with a length of 3/5 foot was decreased by 1/3 foot, the area of the rectangle became 7/25. Find the original width of the rectangle.

Answers

Answer:

$\large\boxed{\text{The original width}\ =(4)/(5)\ ft}$

Step-by-step explanation:

$\text{The dimensions of rectangle:}\ (3)/(5)* w.\n\n\text{The dimensions of new rectangel:}\ (3)/(5)*\left(w-(1)/(3)\right)\n\n\text{The area of the new rectangle:}\ A=(7)/(25)\ ft^2\n\n\text{We have the equation:}\n\n(3)/(5)\left(w-(1)/(3)\right)=(7)/(25)\qquad\text{multiply both sides by 25}\n\n25\!\!\!\!\!\diagup^5\cdot(3)/(5\!\!\!\!\diagup_1)\left(w-(1)/(3)\right)=25\!\!\!\!\!\diagup^1\cdot(7)/(25\!\!\!\!\!\diagup_1)$

$15\left(w-(1)/(3)\right)=7\qquad\text{use the distributive property}\n\n15w-15\!\!\!\!\!\diagup^5\cdot(1)/(3\!\!\!\!\diagup_1)=7\n\n15w-5=7\qquad\text{add 5 to both sides}\n\n15w=12\qquad\text{divide both sides by 15}\n\nw=(12:3)/(15:3)\n\nw=(4)/(5)$

Answer:

The original width is 4/5

Step-by-step explanation:

To find this, note that the new dimensions of the rectangle and 3/5 (lengths) and x - 1/3 (width), in which x is the original width. Now we multiply them together and set equal to 7/25

3/5(x - 1/3) = 7/25

3/5x - 1/5 = 7/25

3/5x = 12/25

x = 4/5

the bottom of a ladder must be placed 5 feet from a building. the ladder is 14 feet long. how far above the ground does the ladder touch the wall?

Answers

$h^2+5^2=14^2\n h^2+25=196\n h^2=196-25\n h^2=171\n h=3√(19)$

Answer:

Hope this helps

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