6. Jessie sorted the coins in her bank. Shemade 7 stacks of 6 dimes and 8 stacksof 5 nickels. She then found 1 dime and1 nickel. How many dimes and nickelsdoes Jessie have in all? (Lesson 2.12)
Answers
Jessie has 7 stacks of 6 dimes, so Jessie has a total of 6*7 dimes
Dimes=7*6=42dimes
Jessie has 42 dimes, but then she found another one so lets add one more dime.
42+1=43 dimes
Jessie has 8 stacks of 5 nickels, so Jessie has 8*5 nickels
Nickels=8*5=40nickels
Jessie has 40 nickels, but then she found another one so lets add 1 to the total number of nickels.
40+1=41nickels
Now we can answer the question.
How many dimes and nickels does jessie have in all?
nickels+dimes=
41+43=84 coins
Jessie has 84 coins in total
8 stacks of 5 nickles = 8•5 which is 40
1 dime + 1 nickle
Add all of them together .......42+40+1+1=84
Hope this helped!❤️
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Answer:
area or two triangular faces = 2 × 1/2 x 6× 4 = 24
area of three rectangular faces= 3x 5x10 = 150
total area = 174cm^2
Answers
The ... means that the 6 keeps repeating infinitely
Answers
3x=24
x=8 Divide both sides by 3
Subtract 6 on both sides
3x=24
Now divide by 3
x=8
7/10+6/100= how do solve this problem
Answers
10 x 10, 20, 30, 40, 50, 60, 70, 80, 90, 100
100 x 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000. which is the lowest and common? 100
7/10 /100 how many times can 10 go into 100? 10 times. so we will multiply 10 time the numerator which is 7, and now will be 70/100
6/100 /100 how many times can 100 go into 100? 1 time. so we will multiply 1 time the numerator 6 which equals 6. 6/100
now add the new fractions. 70/100 + 6/100 = 76/100
Answers
Example:-
4 + x = 8
-4 -4
x = 8 -4
x = 4
Answer; x = 4
Ex. 5 + 5 = x
-5 -5
Now, let's try a real problem:
10 + x = 15
Now, I know this may seem to be an easy problem, but by using the method I am about to show you, you will be able to solve any addition, subtraction, even multiplication, and division equation!
This would be how you solve:
10 + x = 15
-10 -10
----------------------------------------
x = 5
Hope this helped!
4 three-dice (with sides labeled 1, 2, and 3) are rolled and the numbers face up on the 4 dice
are recorded. Give the sample space for this experiment. What is the probability that at least
one of the dice rolled is showing a 2?
What is the probability that at least one of the dice rolled is showing a 2?=
Answers
The sample space for the experiment N(S) = 12 and the probability of showing 2 on at least one die is 41/81.
What is probability?
Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.
Given that four three-sided dice(4, 5, 6 are replaced by 1, 2, 3) are rolled.
As each die has two 1's, two 2's, and two 3's the no. of distinct sample space N(S) each die has is 3, and there are a total of four dice so the total no.of sample space is (3×4) = 12.
∴ The probability that one of the die is showing 2 is (2/6) = 1/3.
So, the probability that at least one of the die is showing two is sum of one die showing two to sum of 4 dice showing 2 which is,
= 2/6 + (2/6)(2/6) + (2/6)(2/6)(2/6) + (2/6)(2/6)(2/6)(2/6).
= 1/3 + 1/9 + 1/27 + 1/81.
= (27 + 9 + 3 + 1)/81.
= 40/81.
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