Please help!! This topic is incredibly confusing and assistance is very much needed & appreciated! Thanks :)
Please help!! This topic is incredibly confusing and assistance is - 1

Answers

Answer 1
Answer: I got 8/10 or 80% because if you add up all sandwichs together, you get 50, then you add up ham and tuna sandwichs and get 40 so 40/50 would be 80/100 to make it a percent or fraction.. hopefully this makes sense and i helped:) i wish i could just send the work to you so it could make more sense lol

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Susie earns $9 per hour at her part-time job. On Tuesday, she spent $5 of her pay that day on lunch. If she took home $49 that day, how many hours did she work? Which mathematical sentence matches the problem?5h + 9 = 49 9h + 5 = 49 9(h - 5) = 49 9h - 5 = 49
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1) In a grocery store, a $21 case of toilet paper is labeled, "Get a 20% discount." What is the discount? What is the sale price of the toilet paper?

Write a division expression for Alaska population density

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if you are wondering about a word divion problem using Alaska Population density than you could do something like this




Hope this helps ;3

What is the answer for 16% of 150

Answers

In order to find a percent of a certain number, you just have to multiply the percentage times the number you are finding the percentage of.
To do this, we must first convert the percentage into a decimal. We can do this by either dividing the percentage by 100, or (my personal shortcut) just shifting the decimal point over 2 places to the left.

16% = 0.16

Now, we multiply

0.16 * 150 = 24

16% of 150 is 24.
Hope that helped! =)
its 24 hope it helps

One cell phone plan charges $20 per month plus $0.15 per minute used. A second cell phone plan charges $35 per month plus $0.10 per minute used. Write and solve an equation to find the number of minutes you must talk to have the same cost for both calling plans.

Answers

The equations are as follows where x represents the number of minutes the cell phone is used.

For plan one: Total cost = $20 + $0.15x

For plan two: Total cost = $35 + $0.10x

For both the costs to be the same, we need to use the cell phone for

300 minutes.

What are equations?

Equations are relations showing the value of one quantity related to another quantity when it can change. The changing value is the variable.

How do we solve the given question?

We are informed that one cell phone plan charges $20 per month plus $0.15 per minute used. A second cell phone plan charges $35 per month plus $0.10 per minute used.

We are asked to write and solve an equation to find the number of minutes you must talk to have the same cost for both calling plans.

Let the number of minutes the cell phone is used be x minutes.

Now we solve for equations for both plans in the following way:-

Plan one:

Charges $20 per month plus $0.15 per minute used.

When the use is for x minutes, the additional charge = $0.15*x = $0.15x

∴ Total cost = Fixed cost + Additional cost

or, Total cost = $20 + $0.15x.

Plan two:

Charges $35 per month plus $0.10 per minute used.

When the use is for x minutes, the additional charge = $0.10*x = $0.10x

∴ Total cost = Fixed cost + Additional cost

or, Total cost = $35 + $0.10x.

We are asked to find the number of minutes used so that the costs in both the plans are equal. To find this we equate the equation of total costs in both the cases to get:

$20 + $0.15x = $35 + $0.10x.

Subtracting ($20 + $0.10x) from both sides of the equation, we get

$20 + $0.15x - ($20 + $0.10x) = $35 + $0.10x - ($20 + $0.10x).

or, $20 + $0.15x - $20 - $0.10x = $35 + $0.10x - $20 - $0.10x.

or, $0.05x = $15

Dividing both sides of the equation by $0.05, we get

$0.05x/$0.05 = $10/$0.05

or, x = 300.

∴ We must talk for 300 minutes for both the plans to cost the same to us.

Learn more about equations at

brainly.com/question/2972832

#SPJ2

Both of these equations are linear, so you have to write equations in the y=my+b format. And then you have to set the equations to equal each other to find x


Answer: 300 minutes

Ken keeps paper clips in a box that is the shape of a cube. Each side of the cube is 3inches. What is the volume of the box?

Answers

volume of cube = L^3 
so, volume = 3^3 = 27 inch^3
Hi there! We know that the side of the cube is 3 inches so V=a³=3³=27 in³. Therefore, the answer is 27 in³.

Harry and Terry are each told to calculate 8−(2+5)8−(2+5). Harry gets the correct answer. Terry ignores the parentheses and calculates 8−2+58−2+5. If Harry's answer is HH and Terry's answer is TT, what is H−TH−T?

Answers

Harry's Answer:
8-(2+5)8-(2+5) = 8-(16+40)-(2+5) ⇒ 8 - 16 - 40 - 2 - 5 = -55

Terry's Answer:
8 - 2 + 58 - 2 + 5 = 67

H = -55
T = 67

H - TH - T

-55 - (67*-55) - 67 = -55 - (-3685) - 67 = -55 + 3685 - 67 = 3,563

Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450450450 kilograms (\text{kg}kgstart text, k, g, end text), but Renna and her load of identical packages mass a total of 620\,\text{kg}620kg620, start text, k, g, end text. Each package has a mass of 37.4\,\text{kg}37.4kg37, point, 4, start text, k, g, end text.Write an inequality to determine the number of packages, ppp, Renna could remove from the elevator to meet the mass requirement.
What is the minimum whole number of packages Renna needs to remove from the elevator to meet the mass requirement?

Answers

Answer:

Part A. 37.4p  ≥ 170

Part B. p  ≥ 5 (rounding to the next whole)

Renna needs to remove at least 5 packages from the elevator to meet the mass requirement.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mass limit for the elevator = 450 kg

Renna and her load of packages mass = 620 kg

Each package mass = 37.4 kg

2. Write an inequality to determine the number of packages, p, Renna could remove from the elevator to meet the mass requirement.

Number of packages * Each package mass ≥ Renna and her load of packages mass - Mass limit for the elevator

Replacing with the values and variables we know:

p * 37.4 ≥ 620 - 450

37.4p  ≥ 170

3. What is the minimum whole number of packages Renna needs to remove from the elevator to meet the mass requirement?

Solving for p in the equation above, we have:

37.4p  ≥ 170

p  ≥ 170/37.4

p  ≥ 4.55

p  ≥ 5 (rounding to the next whole)