Describe each of the three types of hazardous weather forecasts

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Answer 1
Answer: Well, there can be a tornado that is very severe when hot and cold air mixes making air swirl and create a triangular shaped spinning air. There are lightning storms when lightning bolts come from the sky, and there are hurricanes when there are lots of rain coming towards your way due to change in climate such as global warming, it often occurs in humid places.

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If you are driving 128.4 km/h along a straight road and you look down for 3.0s, how far do you travel during this inattentive period?

Answers

Answer:

107 m

Explanation:

Convert km/h to m/s:

128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s

Distance = rate × time

d = 35.67 m/s × 3.0 s

d = 107 m

a pebble sinks in water a twig floats on top of the water compare the densities of the water, the pebble and the twig

Answers

A pebble that sinks in water has greater density than a twig floats on top of the water. A pebble has more mass in it and more compact compared to a twig. The water cannot easily penetrate the pores of the pebble unlike twigs. That is why pebbles have greater densities than twigs.

If an object is falling downward, is the acceleration due to gravity (9.8 m/s/s) negative?

Answers

NO! ACCELERATION IS NEVER NEGATIVE UNLESS IT IS SLOWING DOWN.
No because the acceleration is getting larger. If the object was slowing down it would be negative. It does not matter in direction. Its wether is is speeding up or slowing down.

What net is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/second^2 (assume a flat,frictionless surface.)

Answers

Newton's 2nd Law of Motion:  Force = (mass) · (acceleration)

Do I need to go any further ?

I get  575.25 Newtons .

Oh !  Look at that !  Right there at the top, it says "Using Newton's Second Law".  This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.

Three resistors (R1 = 120 Ohms, R2 = 330 Ohms, and R3 = 240 Ohms) and an ideal inductor (L = 1.6 mH) are connected to a battery (V = 9 V) through a switch as shown in the figure below.The switch has been open for a long time before it is closed at t = 0. At what time t0, does the current through the inductor (I3) reach a value that is 63% of its maximum value?

Answers

The time at which the current through the inductor reaches 63% of the maximum current is 4.85 \mus

What is current?

The current is defined as the flow of the charge in the circuit is is the rate of flow of the charge.

At  t=0 s there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when the switch is closed, and becomes steady after a certain time.

Given that

The value of resistor is .120 ohm

The value of resistor is .330 ohm

The value of resistor is .240ohm

The value of the inductor is .1.6 mh

The voltage applied across the circuit is .9 V

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors  is connected in series with the parallel combination of resistors  

The effective resistance of the circuit is:

    R_(eff)=R_a+(R_1* R_2)/(R_1+R_2)                    …… (1)

Here,  R{eff is the effective resistance of the circuit. Now substituting the values.

R_(eff)=240+(120* 330)/(120+330)=328\  ohm

The current through the inductor is:

i=i_o(1-e^{(tR_(eff))/(L)})                                       ...... (2)

Here,  is the current across the inductor, io is the maximum current in the circuit and  L is the inductance across the inductor.

The current across the inductor is equal to the 63% of the maximum current in the circuit.

The current across the inductor is:

i=0.63io

Substitute 0.63io for 328 ohm ,  for 1.6 mH and  for L in equation (2).

0.63 i_o=i_o(1-e^(-t(328))/(1.6)})

Simplify the above expression.

e^((-2.05*10^6))=0.37

Taking natural log on both sides and simplify.

t=4.85* 10^(-6)\ s

t=4.85 \mu s

Thus, the time at which the current through the inductor reaches 63% of the maximum current is t=4.85 \mu s

To know more about current follow

brainly.com/question/24858512

The time at which the current through the inductor reaches 63% of the maximum current is \fbox{\begin\n4.85 \mu s\end{minispace}} or \fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}.

Further Explanation:

At t = 0\,{\text{s}} there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when switch is closed, and becomes steady after certain time.

Given:

The value of resistor is 120\,\Omega.

The value of resistor is 330\,\Omega.

The value of resistor is 240\,\Omega.

The value of the inductor is 1.6\,{\text{mH}}.

The voltage applied across the circuit is 9\,{\text{V}}.

Concept:

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors {R_3} is connected in series with the parallel combination of resistors {R_1} and {R_2}.

The effective resistance of the circuit is:

\fbox{\begin\n{R_(eff)} = {R_3} + \frac{{{R_1} * {R_2}}}{{{R_1} + {R_2}}}\end{minispace}}                         …… (1)

Here, {R_(eff)} is the effective resistance of the circuit.

Substitute the 120\,\Omega for {R_1}, 330\,\Omega  for {R_2} and 240\,\Omega for {R_3} in equation (1).

\begin{aligned}{R_(eff)}&=240\,\Omega+\frac{{\left( {120\,\Omega } \right) * 330\,\Omega }}{{120\,\Omega +330\,\Omega }} \n&=328\,\Omega\n \end{aligned}

The current through the inductor is:

\fbox{\begin\ni = {i_0}\left( {1 - {e^{ - \frac{{t{R_(eff)}}}{L}}}} \right)\end{minispace}}                                       ...... (2)

Here, i is the current across the inductor, {i_0} is the maximum current in the circuit and L is the inductance across the inductor.

The current across the inductor is equal to the 63% or   times of the maximum current in the circuit.

The current across the inductor is:

i = 0.63{i_0}

Substitute 0.63{i_0} for i, 328 \Omega for {R_(eff)} and 1.6\,{\text{mH}} for L in equation (2).

0.63{i_0} = {i_0}\left( {1 - {e^{ - \frac{{t\left( {328\Omega } \right)}}{{\left( {1.6\,{\text{mH}}} \right)}}}}} \right)

Simplify the above expression.

{e^{ - \left( {2.05 * {{10}^6}} \right)t}}= 0.37

Taking natural log on both sides and simplify.

\begin{aligned}t&=4.85\, * {10^( - 6\,)}\,{\text{s}} \n&=4.85\mu \text{s}}\n\end{aligned}  

Thus, the time at which the current through the inductor reaches 63% of the maximum current is \fbox{\begin\n4.85 \mu s\end{minispace}} or \fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}.

Learn more:

1.  Conservation of energy brainly.com/question/3943029

2.  Average translational energy brainly.com/question/9078768

3. The motion of a body under friction brainly.com/question/4033012

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Current Electricity

Keywords:

Resistor circuit, LR circuit, current, current across inductor, time constant, 4.85 microsecond, 4.85 microsec, 4.85 micros, 4.85*10-6 s, 4.85*10^6 s, 4.85*10-6 sec, 4.85*10^6 sec.

What changes to landforms are caused by movements at transform boudaries

Answers

not much changes, but there are some great pressure so some hills may form.