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When 282 gr of glycine are dissolved in 950 gr of a certain mystery liquid, the freezing point of the solution is 8.2 C less than the freezing point of pure. Calculate the mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answers

Answer 1

Answer:

Answer: $1.4* 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i* K_f* m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like glycine)

$K_f$ = freezing point constant = ?

m= molality

$\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

Weight of solvent = 950 g = 0.95 kg

Molar mass of glycine = 75.07 g/mol

Mass of glycine added = 282 g

$8.2=1* K_f* (282g)/(75.07 g/mol* 0.95kg)$

$K_f=2.2^0C/m$

Thus freezing point constant is $2.2^0C/m$

2) $\Delta T_f=i* K_f* m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

i= vant hoff factor = 4 (for $FeCl_3$ )

$K_f$ = freezing point constant = $2.2C/m$

m= molality

$\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

Weight of solvent = 950 g = 0.95 kg

Molar mass of $FeCl_3$ = 162.2 g/mol

Mass of $FeCl_3$ added = ?

$8.2=4* 2.2* (xg)/(162.2 g/mol* 0.95kg)$

$x=1.4* 10^2g$

Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is $1.4* 10^2g$

Answer 2

Answer:

Answer:

$mass_(FeCl_3)=1.5x10^2gFeCl_3$

Explanation:

Hello,

In this case, by using the given data for glycine, one computes the freezing point constant of the mystery liquid as shown below, considering the molality of the glycine and its van't Hoff factor equal to the unity:

$\Delta T=i*Kf*m_(Glyc)\n\nKf=(\Delta T)/(i*m_(glyc)) =(8.2^oC)/(1*(282gGlyc)/(950gX)*(1molGlyc)/(75.07gGlyc)*(1000gX)/(1kgX) ) \n\nKf=2.1^oC/m$

Now, as we are looking for the mass of iron(III) chloride at the same conditions of the aforesaid case, at first, one solves for the molarity of such compound considering that its theoretical van't Hoff factor is 4 as follows:

$m_(FeCl_3)=(\Delta T)/(i*Kf) =(8.2^oC)/(4*2.1^oC/m_(FeCl_3)) =0.98m$

Now, one obtains the requested mass via:

$mass_(FeCl_3)=0.98(molFeCl_3)/(kgX)*0.95kgX*(162.35gFeCl_3)/(1molFeCl_3) \n\nmass_(FeCl_3)=151.1gFeCl_3\nmass_(FeCl_3)=1.5x10^2gFeCl_3$

Best regards.

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The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (M) Initial Rate (10–3 M/s) 0.4 0.4 0.2 160 0.2 0.4 0.4 80 0.6 0.1 0.2 15 0.2 0.1 0.2 5 0.2 0.2 0.4 20 Using the initial-rate method, what is the order of the reaction with respect to C? a. zero-order b. first-order c. third-order d. second-order e. impossible to tell from the data given

Answers

The dependence of the power of the reaction rate on the concentration is called the order of the reaction. The order of the reaction is the first order.

What is the initial-rate method?

The initial rate method is the estimation of the order of the reaction by the initial rates of the reactants and products and by performing the reaction several times by measuring the rate.

The reaction is given as,

$\rm A + B + C \rightarrow Products$

The rate of reaction can be given as:

$\rm rate = k[A]^(x)[B]^(y)[C]^(z)$

Here the variables x, y and z are orders respective to the reactant concentration and k is the rate constant.

Value of x with respect to A:

$\begin{aligned} \rm \frac {Rate 3}{Rate 4} &= \rm [([A(3)])/([A(4)])]^(\rm x)\n\n(15)/(5) &= [([0.6])/([0.2])]^(\rm x)\n\n\rm x &= 1\end{aligned}$

Value of y with respect to B:

$\begin{aligned}\rm \frac {Rate 2}{Rate 5} &= \rm [([B(2)])/([B(5)])]^(\rm y)\n\n(80)/(20) &= [([0.4])/([0.2])]^(\rm y)\n\n\rm y &= 2\end{aligned}$

Value of z with respect to C:

$\rm \frac {Rate 1}{Rate 2} &= [([A(1)])/([A(2)])]^(x) [([B(1)])/([B(2)])]^(y) [([C(1)])/([C(2)])]^(z)$

Substituting value of x = 1 and y = 2 in the above equation:

$\begin{aligned}(160)/(80) &= [([0.4])/([0.2])]^(1)[([0.4])/([0.4])]^(2) [([0.2])/([0.4])]^(\rm z)\n\n1 &= (0.5)^(\rm z)\n\n&= 1\end{aligned}$

Therefore option b. with respect to C = 1, the order of the reaction is first-order.

Learn more about the order of reaction here:

brainly.com/question/8139015

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

[A]₀ [B]₀ [C]₀ Initial Rate (10⁻³ M/s)

1. 0.4 0.4 0.2 160

2. 0.2 0.4 0.4 80

3. 0.6 0.1 0.2 15

4. 0.2 0.1 0.2 5

5. 0.2 0.2 0.4 20

The rate of the above reaction is given as:

$Rate = k[A]^(x)[B]^(y)[C]^(z)$

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

$(Rate3)/(Rate4)= [([A(3)])/([A(4)])]^(x)$

$(15)/(5)= [([0.6])/([0.2])]^(x)$

$3 = 3^(x) \n\nx =1$

Order w.r.t B : Use trials 2 and 5

$(Rate2)/(Rate5)= [([B(2)])/([B(5)])]^(y)$

$(80)/(20)= [([0.4])/([0.2])]^(y)$

$4 = 2^(y) \n\ny =2$

Order w.r.t C : Use trials 1 and 2

$(Rate1)/(Rate2)= [([A(1)])/([A(2)])]^(x)[([B(1)])/([B(2)])]^(y)[([C(1)])/([C(2)])]^(z)$

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

$(160)/(80)= [([0.4])/([0.2])]^(1)[([0.4])/([0.4])]^(2)[([0.2])/([0.4])]^(z)$

$1 = (0.5)^(z)$

z = 1

Therefore, order w.r.t C = 1

Please it's due today

Answers

Answer:

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate. CH3CH2 C C CH3 H2O/H2SO4/HgSO4

Answers

Answer:

Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate.

CH3CH2 C C CH3 H2O/H2SO4/HgSO4

Explanation:

The given compound is: pent-2-yne.

When it reacts with water, in presence of sulphuric acid and mercuric sulphate then a ketone is formed as shown below:

This reaction is an example of nucleophilic attack of water on carbon carbon triple bond.

The general mechanism of the reaction is hsown below:

Pent-2-yne reacts with water and form 3-pentanone.

The reaction is shown below:

Final answer:

The reaction is the hydration of an alkene in an acidic environment, resulting in the formation of 2-butanol. This result is in accordance with Markovnikov's rule, which determines the position of the hydroxyl group in the resultant product.

Explanation:

The question refers to the acidity-catalyzed hydration of an alkene. In this case, you have an alkene CH3CH2 - CC - CH3 reacting in an acidic environment with water (H2O). The reactants have been exposed to H2O/H2SO4/HgSO4. In this reaction scenario, the acidic medium (H2SO4) and the water enact the role of a nucleophile and attack the alkene, thereby hydrating it.

The product of this reaction will be 2-butanol. Its formation is guided by Markovnikov's rule, which states that in the addition of a protic acid HX to an alkene, the acid hydrogen (H) becomes attached to the carbon with fewer alkyl substituents, and the halide (X) group becomes attached to the carbon with more alkyl substituents. This rule is why the hydroxyl group (-OH) attaches itself to the 2nd carbon atom in the major (predominant) product.

Learn more about Acidity-catalyzed hydration here:

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#SPJ3

What is the mass of oxygen in 250 go of sulfiric acid, H2CO4

Answers

Hope this helps you.

Your answer is 160 grams I hope this helps

A 2.00 L container of gas has a pressure of 1.00 atm at 300 K. The temperature of the gas is halved to 150K, and the measured pressure of the same 2.00 Liter sample is 0.420 atm. Which of the following is the best explanation for these observations? A. Pressure is proportional to temperature for a fixed volume of gas. B. The molecules of the gas occupy a significant portion of the volume. C. The molecules of the gas have negligible volume of their own. D. The molecules have significant attractive forces at 150 K. E. The gas is closer to an ideal gas at 150 K.

Answers

The best explanation for the observation is that, the Pressure is proportional to temperature for a fixed volume of gas. (Option A)

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 1 atm

Initial temperature (T₁) = 300 K

Final temperature (T₂) = 150 K

Final volume (V₂) = 2 L = constant

Final pressure (P₂) = 0.420 atm

From the above, we can see that the volume is constant.

Applying the combine gas equation, we can conclude as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

V₁ = V₂

P₁ / T₁ = P₂ / T₂

P/T = constant

P = constant × T

Thus, we can conclude that the pressure is proportional to the temperature at constant volume. This simply implies that the pressure will increase if the temperature increase and it will also decrease if the temperature decreases.

The correct answer to the question is Option A.

Learn more about gas laws: brainly.com/question/9631148

Answer:

Explanation:

PV=nRT

PV/nT

V/T -> (1)/(300)=(x)/(150)

x=.420

Which of the following required Bohr's model of the atom to need modification ? A. Energies of electrons are quantized. B. Quantized electron energies are responsible for emission spectra lines. C. An electron's energy increases the farther it moves from the nucleus. D. Electrons do not follow circular orbits around the nucleus..

Answers

Answer:

Electrons do not follow circular orbits around the nucleus

Explanation:

Bohr's model of the atom is a combination of elements of quantum theory and classical physics in approaching the problem of the hydrogen atom. According to Neils Bohr, stationary states exist in which the energy of the electron is constant. These stationary states were referred to as circular orbits which encompasses the nucleus of the atom. Each orbit is characterized by a principal quantum number (n). Energy is absorbed or emitted when an electron transits between stationary states in the atom.

Sommerfeld improved on Bohr's proposal by postulating that instead of considering the electron in circular orbits, electrons actually orbited around the nucleus in elliptical orbits, this became a significant improvement on Bohr's model of the atom until the wave mechanical model of Erwin Schrödinger was proposed.

Answer:

Electrons do not follow circular orbits around the nucleus

Explanation:

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