An electronic salesperson carries 6 identical amplifier tubes, 5 identical rectifiers, 2 identical condensers, and 4 identical relays. In how many different ways can these parts be arranged in a row?

Answers

Answer 1

Answer:

The number of ways of arranging these items in a row is:

85,765,680

Step-by-step explanation:

It is given that:

An electronic salesperson carries 6 identical amplifier tubes, 5 identical rectifiers, 2 identical condensers, and 4 identical relays.

Hence, the total number of items are:

17 ( since 6+5+2+4=17)

Hence, the number of ways it could be arranged in a row is calculated as:

$=(17!)/(6!* 5!* 2!* 4!)\n\n\n=(17* 16* 15* 14* 13* 12* 11* 10* 9* 8* 7* 6!)/(6!* 5!* 2!* 4!)\n\n=(17* 16* 15* 14* 13* 12* 11* 10* 9* 8* 7)/( 5!* 2!* 4!)$

which on solving gives us: 85,765,680

Hence, the number of ways of doing so is:

85,765,680

Answer 2

Answer: No of arrangement = (6+5+2+4)! / (6! * 5! * 2! * 4!) = 17! / (6! * 5! * 2! * 4!) = (17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) / (6 * 5 * 4 * 3 * 2 * 1 * 5 * 4 * 3 * 2 * 1 * 2 * 1 * 4 * 3 * 2 * 1) = 85,765,680

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Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2. If AB = 18, find EF.

Answers

Answer: EF = 12 units

Step-by-step explanation:

Given : Quadrilateral ABCD is similar to Quadrilateral EFGH.

The scale factor is 3:2.

We know that the scale factor is the ratio of the corresponding sides of two similar figures.

So if Quadrilateral ABCD is similar to Quadrilateral EFGH, the side AB corresponds to side EF.

If AB = 18, then we have the following equation:-

$(AB)/(EF)=(3)/(2)\n\n\Rightarrow(18)/(EF)=(3)/(2)\n\n\Rightarrow\ EF=(2*18)/(3)\n\n\Rightarrow\ EF=12$

EF =12

do you want to know how I got my answer...

What is the geometric mean of 50 and 8?

Answers

Answer: a = 8 b= 50.

Step-by-step explanation:

How do i solve 89 times 69

Answers

$89\cdot 69\n \n =\left( 90-1 \right) \left( 70-1 \right) \n \n =90\cdot 70-90-70+1$

$\n \n =6,300-160+1\n \n =6,140+1\n \n =6,141$

89 x 69 = 6141
hope this helps!!!!!!!!!!

whats the lateral area of a right circular cone if the diameter of the base is 4m and the slant height of the cone is 15m? round your anwser the the nearest whole number.

Answers

Answer:

94 m ^2

Step-by-step explanation:

Answer for Penn

Answer:

94 m²

Step-by-step explanation:

The lateral area of a right circular cone if the diameter of the base is 4m and the slant height of the cone is 15m. Solution: Lateral Area = pi*r ( h²+r²) r = 4/2 r = 2 meters Lateral Area = 3.14*2 ( 15²+2²) Lateral Area = 94 m²

PLEASE HELP I WILL GVE BRAINLIEST