Consider a colony of E.Coli bacteria that is growing exponentially. A microbiologist finds that, initially, 1,000 bacteria are present and 50 minutes later there are 10,000 bacteria. a) Find expression for the number of bacteria Q(t) after t minutes. b) When will there be 1,000,000 bacteria?

Answers

Answer 1

Answer:

Answer:

a) $Q(t)=Q_(0)e^((ln10/50)t)$

b) 150min

Step-by-step explanation:

a) Using the formula for colony growth $Q(t)=Q_(0)e^(kt)$ we need to find the specific value of k, to do this you'll use the time, initial and final number of colonies provided in your problem.

$Q(t)=Q_(0)e^(kt)\n\n10000=1000e^(k(50)) \n\n(10000)/(1000)=e^(50k) \n\n10=e^(50k)\n ln(10=e^(50k))\n\nln10=50k\n\nk=ln10/50\n\nQ(t)=Q_(0)e^((ln10/50)t)\n\n$

b) Once we have our expression we only have to use our final and initial number of bacteria to find t.

$Q(t)=Q_(0)e^((ln10/50)t)\n\n\n1000000=1000e^(0.046t)\n 1000=e^(0.046t)\nln( 1000=e^(0.046t))\nln1000=0.046t\nt=ln1000/0.046\nt=150 minutes$

I hope you find this information useful! good luck!

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In a survey of students, 60% were in high school and 40% were in middle school. Of the high school students, 30% had visited a foreign country. If a surveyed student is selected at random, what is the probability that the student is in high school and has visited a foreign country?

Answers

Answer:

The probability that the student is in high school and has visited a foreign country is 0.18.

Step-by-step explanation:

We are given that in a survey of students, 60% were in high school and 40% were in middle school.

Of the high school students, 30% had visited a foreign country.

Let the Probability that students were in high school = P(H) = 60%

Probability that students were in middle school = P(M) = 40%

Also, let F = event that students had had visited a foreign country

So, Probability that high school students had visited a foreign country = P(F/H) = 30%

Now, probability that the student is in high school and has visited a foreign country is given by = Probability that students were in high school $*$ Probability that high school students had visited a foreign country

= P(H) $*$ P(F/H)

= 0.60 $*$ 0.30

= 0.18 or 18%

HELP WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 98 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!At the middle school, the bell rings every 40 minutes to tell the students to change classes.
Across the street the clock above city hall chimes every 30 minutes. Both the school bell
and the clock ring at noon. When will both bells ring again at the same time? Use Prime Factorization

Answers

Hello.

The answer is:

First find Lcm of 40 and 30 that is 120 (2*2*2*3*5)

the convert 120 by divinding by 30 = 120/30=4

So that means 2 hours later (2 hours after 12) so the answer is 2 pm

Have a nice day

2:00 is when they will both ring next

In all, 54 children were assigned to the Montessori school and 115 to other schools at age three. When the children were five, parents of 38 of the Montessori children and 34 of the others could be located and agreed to and subsequently participated in testing. This information reveals a possible source of bias in the comparison of outcomes. Explain why. (Round your answers to the nearest whole number.) About % of Montessori parents participated in the study, compared to about % of the other parents. (c) One of the many response variables was score on a test of ability to apply basic mathematics to solve problems. Here are summaries for the children who took this test:

Answers

Full question attached

Answer:

Option C: because the percent of children compared differ too much

Explanation:

Sample Proportion of students from Montessori = students that participated from Montessori /total number of students assigned to Montessori

=30/54= 0.56

Sample proportion of students from other schools = students that participated I'm the study /total number of students assigned to other schools

=25/112

=0.22

We observe that there is a large difference(0.56-0.22) between the two sample proportions hence the bias

Zoning activityIf you wanted to build a new house, or add an addition to the house you own, where would you go to get permission? What codes would you have to follow?

Answers

Final answer:

To build a new house or add an addition to an existing house, you would need to get permission from your local zoning and planning department, or a similar local government office. You would need to follow building codes, zoning codes, and possibly environmental regulations.

Explanation:

If you wanted to build a new house or add an addition to the house you own, you would generally need to go to your local zoning and planning department or a similar local government office. These local departments enforce regulations and laws related to land and property use, including residential construction.

As for the codes you would need to follow, these typically include building codes, zoning codes, and sometimes environmental regulations.

Building codes pertain to the actual construction of the structure, ensuring that it is safe and meets certain standards. Zoning codes, on the other hand, govern what types of buildings and uses are allowed in certain areas. Environmental regulations may apply if the construction could affect local ecosystems.

Additionally, if you live in a neighbourhood with a homeowners association (HOA), you may also have to follow their guidelines and get their approval too.

Learn more about Building and Zoning Codes here:

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If y varies directly as x and y=3 when x=10, find x when y=8Please, somebody, I need help

Answers

Answer:

26.6

Step-by-step explanation

3=10*k

3/10=.3

y=8

8=.3*x

8/.3=26.6

A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 5 answer choices - a, b, c, d, e- and only one correct answer. What is the probability that she answered neither of the problems correctly? Do not round your answer. (If necessary, consult a list of formulas.)

Answers

Answer:

there is a 64% chance that the student got both problems wrong

a 32% chance that they got only 1 correct

and a 4% chance that they got both correct

Step-by-step explanation:

There are 25 total possible combinations of answers, with 8 possible combinations where the student would get 1 answer right, and 1 combination where the student would get both answers correct.

$25-9=16$