The height of a ball when it is thrown into the air is shown by equation h = −16t2 + 20t + 3, where h is the height of the ball and t is time in seconds since the ball was released.A or B?
A.
linear model
B.
nonlinear model
Answers
h = -16t² + 20t + 3
This is a quadratic equation, it is degree 2 equation.
A degree 1 equation is a linear equation or model.
Any degree greater than 1, as 2 is a non linear.
So h = -16t² + 20t + 3, is a non linear model.
It is B.
I hope this helped.
a quadratic equation is not a linear model.
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Answer:
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Step-by-step explanation:
Answers
30 miles at 30 degrees north of east
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You calculate the horizontal and vertical component using these equations
x = d cos θ
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Jack walks 30 miles at 30 degrees north of east, then walks 30 miles at 45 degrees north of east. how many miles east of his starting point will he end up?
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The 9 is in the hundred thousands place.
932805
5- ones
0- tens
8-hundreds
2-thousands
3-ten thousands
9-hundred thousands
To solve the problem you can you place value.
The number 9 is in the hundred thousands place.
= Number (932805)
5- ones
0- tens
8-hundreds
2-thousands
3-ten thousands
9-hundred thousands
Answers
that line is:
Answers
The equation of the line perpendicular to the given line that passes through the point (-4, 6) is y = (2/3)x + 26/3.
Here, we have to find a line that is perpendicular to the given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope.
Perpendicular lines have slopes that are negative reciprocals of each other.
Given points: (-4, 6) and (-2, 3)
The slope of a line passing through two points and
is given by:
Let's plug in the values:
The negative reciprocal of a number is the negative value of its reciprocal.
The reciprocal of a number a is 1/a.
So, the negative reciprocal of is:
The perpendicular line has a slope of 2/3.
Now, we have the slope of the line perpendicular to the given line.
To find the equation of this perpendicular line, we also need a point on the line.
We can use one of the given points from the original line.
Let's use the point (-4, 6):
Use the point-slope form of a line to write the equation of the perpendicular line:
Substitute the values:
y - 6 = (2/3)(x - (-4))
y - 6 = (2/3)(x + 4)
Now, if we want to put the equation in slope-intercept form (y = mx + b), we can simplify further:
y - 6 = (2/3)x + 8/3
Add 6 to both sides:
y = (2/3)x + 8/3 + 6
y = (2/3)x + 8/3 + 18/3
y = (2/3)x + 26/3
So, the equation of the line perpendicular to the given line that passes through the point (-4, 6) is y = (2/3)x + 26/3.
To learn more on equation click:
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Answer: A line with a slope of 2
Step-by-step explanation: the slope of the line is -1/2 so the negative reciprcal of the slope is 2 (It would be perpendicular to it)
i used m=y2-y2/x2-x1 to figure ou the slope and -(x/y) as the negative reciprcal for the perpendicular line.