MATHEMATICS HIGH SCHOOL

In triangle ABC, c = 8, b = 6, and ∠C = 60°. sin∠B = _____

Answers

Answer 1
Answer:

Answer:

sin∠B=0.649°  

Step-by-step explanation:

Given: In triangle ABC, c = 8, b = 6, and ∠C = 60°.

To find: sin∠B

Solution: using the sine formula that is (SinA)/(a)=(SinB)/(b)=(SinC)/(c), we get

(SinA)/(a)=(SinB)/(6)=(Sin60^(\circ))/(8)

Taking the second and third  equality, we get

(SinB)/(6)=(Sin60^(\circ))/(8)

⇒(SinB)/(6)=((√(3))/(2))/(8)

⇒(SinB)/(6)=(√(3))/(16)

⇒SinB=\frac{√(3){*}6}{16}

⇒SinB=(3√(3))/(8)

⇒SinB=0.649^(\circ)

Thus, SinB=0.649^(\circ).
Answer 2
Answer: Hello,

sin B/b=sin C/c
==>sin B=√3 / 2 * 6/8=3√3 /8

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For each of the functions below, describe the domain of definition that is understood: f(z) = (1/x²)+1

Answers

Answer: x \neq 0

Step-by-step explanation:

The domain of a function consists of the x-values that have a y-value in a function. The +1 shifts the graph upwards 1 unit. This only affects the range, the y-values. The x is in the denominator of a function, and the denominator of a function can never be 0, so we can say x \neq 0. There are no other restrictions on the domain; x can be negative, x can be positive, but x cannot be 0.

If we graph this function, we'll see that there are no y-values when x = 0. We say that there is a vertical asymptote at x = 0, an imaginary line at an x-value that does not have any y-values.

I hope this helps! :)

Which statement is not always true about irrational numbers

Answers


"Irrational numbers start with  37.2 ."

If this is not one of the statements on the list of choices that comes
with this question, then perhaps you could let us see the list of choices
that comes with this question, so that we can guide you to the best choice.

Answer:

here are the statements  I need help on this too help for iready!!!

(08.01, 08.02, 08.03, 08.05, 08.06 MC)Part A: Factor x2y2 + 6xy2 + 8y2. Show your work. (4 points)

Part B: Factor x2 + 8x + 16. Show your work. (3 points)

Part C: Factor x2 − 16. Show your work. (3 points)

Answers

Answer: The factorization of all the parts are :

Part A : x^2y^2+6xy^2+8y^2=y^2(x+2)(x+4).

Part B :  x^2+8x+16=(x+4)(x+4).

Part C :  x^2-16=(x+4)(x-4).

Step-by-step explanation:  We are given to factorize the following quadratic polynomials :

Part A : Factor x²y² + 6xy² + 8y².  

Part B : Factor x² + 8x + 16.

Part C: Factor x² − 16.

We will be using the following factorization formulas :

(i)~x^2+ax+bx+ab=(x+a)(x+b),\n\n(ii)~x^2+2xa+a^2=(x+a)^2=(x+a)(x+a),\n\n(iii)~x^2-a^2=(x+a)(x-a).

The factorization of all the parts area as follows :

Part A :

We have

x^2y^2+6xy^2+8y^2\n\n=y^2(x^2+6x+8)\n\n=y^2(x^2+4x+2x+8)\n\n=y^2(x(x+4)+2(x+4))\n\n=y^2(x+2)(x+4).

So,x^2y^2+6xy^2+8y^2=y^2(x+2)(x+4).

Part B :

We have

x^2+8x+16\n\n=x^2+2* x*4+4^2\n\n=(x+4)^2\n\n=(x+4)(x+4).

So, x^2+8x+16=(x+4)(x+4).

Part C :

We have

x^2-16\n\n=x^2-4^2\n\n=(x+4)(x-4).

So,x^2-16=(x+4)(x-4).

Thus, all the parts are factorized.
is it x times 2 times y times 2? is that what it is asking or is it meaning squared

Isosceles triangle, the altitude and median are __________.

Answers

Answer: The Same Segment

Step-by-step explanation: APEX
the altitude and the median are not the same

A pizza place offers 3 different cheeses and 8 different toppings. In how many ways can a pizza be made
with 1 cheese and 3 toppings?

Answers

The cheese can be any one out of 3 = 3 choices.  For each of those . . .
The first topping can be any one of 8.  For each of those . . .
The second topping can be any one of the remaining 7 . For each of those . . .
The third topping can be any one of the remaining 6 .

Total number of ways to assemble a pizza = (3 x 8 x 7 x 6) =  1,008 ways.

BUT . . .

You could choose the SAME 3 toppings in (3 x 2) = 6 different ways, and
nobody could tell the difference once they were selected.  All 6 different
ways would result in the same pizza.

So, out of the 1,008 total different ways there are of choosing ingredients,
there are only ( 1,008 / 6 ) = 168 different and distinct pizzas.
1\ cheese\ is\ choose\ from\ 3:\ \ \ {3 \choose 1} =3\nand\ 3\ toppings\ are\ choose\ from\ 8:\ \ \ {8 \choose 3} = (8!)/(3!\cdot(8-3)!)= (5!\cdot6\cdot7\cdot8)/(2\cdot3\cdot5!)=56 \n\na\ pizza\ can\ be\ made\ on\ \ 3 \cdot 56=168\ \ ways

Which of the sets of ordered pairs represents a function?A = {(1, −5), (8, −5), (8, 7), (2, 9)}
B = {(7, −4), (7, −2), (6, −3), (−9, 5)}

Only A
Only B
Both A and B
Neither A nor B

Answers

Answer:

The correct option is 4. Neither A nor B represents a function.

Step-by-step explanation:

The given sets of ordered pairs are

A=\{(1,-5), (8,-5), (8,7), (2,9)\}

B=\{(7,-4), (7,-2), (6,-3), (-9,5)\}

A set of ordered pairs represents a function if there exist unique outputs for all inputs. It means for each values of x there exist, a unique value of y.

In set A the value of y-coordinates are -5 and 7 at x=8.

At x=8, there exist more than one value of y, so the set A is not a function.

In set B the value of y-coordinates are -4 and -2 at x=7.

At x=7, there exist more than one value of y, so the set B is not a function.

Therefore neither A nor B represents a function and option 4 is correct.

Answer:

The answer is D, "Neither A or B."

Step-by-step explanation:

In most cases (including this one), there can only be one input or x-value for every unique output, or y-value. In other words, the x-values cannot repeat themselves. Both (8, -5) and (8, 7) are invalid in ordered pairs A, and (7, -4), and (7, -2) make ordered pairs B unable to represent a function. I also took this test and it was correct.
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