MATHEMATICS HIGH SCHOOL

Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.Which notation shows the relationship between set C and set D?

A: C ∪ D
B: C ∩ D
C: D ⊆ C
D: C ⊆ D

Answers

Answer 1
Answer: 1. If it is intersection then it SHOULD be included in both the sets right? Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!! So A={51,53,57,59,61......99} B={55,60,65,70.......95} [We stop till 100 because set A has no such element] So what is A ∩ B here? A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}

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Given: ∠LKM ≅ ∠JKM∠LMK ≅ ∠JMK

Prove: ∆LKM ≅ ∆JKM

Which method can you use to prove these triangles congruent?

the ASA Postulate


the SAS Postulate


the HL Theorem


the AAS Theorem

Answers

Answer: the ASA Postulate

Step-by-step explanation:

In the given picture , we have two triangles ∆LKM and ∆JKM , in which we have

\angle{LKM}\cong\angle{JKM}\n\n\angle{LMK}\cong\angle{JMK}

\overline{KM}\cong\overline{KM} [common]

By using ASA congruence postulate , we have

∆LKM and ∆JKM

ASA  congruence postulate tells that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle then the triangles are congruent.

Answer:

ASA

Step-by-step explanation:

Can you answer these? I don't understand this part either. Thanks

Answers

9x+10=12x-11
We put 12x on the left side and 10 on right side
9x-12x=-11-10
Now we add x and free numbers 
-3x=-21
And our result is:
x=7

3(x-8)=5x+7
3x-24=5x+7
3x-5x=7+24
-2x=31
x=- (31)/(2)
9x+10=12x-11\n 3x=21\n x=7\n\n 3(x-8)=5x+7\n 3x-24=5x+7\n 2x=-31\n x=-(31)/(2)

Helpp me please. click the photo to see the question

Answers

Answer:

.42n = p

Step-by-step explanation:

We can write ratios to solve

2.52 / 6 = p/n

.42 = p/n

Multiply each side by n

.42n = p

Answer:

A is the answer

Step-by-step explanation:

You have to divide $2.42 by 6.

2.52/6=0.42

The unit rate would be

p=0.42n

So for every orange it will cost $0.42

Hope this helps

Prove this (sinx-tanx)(cosx-cotx)=(sinx-1)(cosx-1)

Answers

(sinx−tanx)(cosx−cotx)

=(sinx−sinxcosx)(cosx−cosxsinx)

=sinx(1−1cosx)cosx(1−1sinx)

=sinx(cosxcosx−1cosx)cosx(sinxsinx−1sinx)

=sinxcosx(cosx−1)cosxsinx(sinx−1)

=(cosx−1)(sinx−1)
distribute first
sinx cosx - sinx cotx - cosx tanx+tanx cotx
sinx cosx - sinx (cosx/sinx) - cosx (sinx/cosx) + tanx (cosx/sinx)
sinxcosx - cosx - sinx +1
and factor
cosx(sinx -1) -1(sinx - 1)
(sinx -1)(cosx-1)

Which of the following represents the factorization of the polynomial below?
2x2 +11x +5

Answers

Answer:

(2x + 1)(x + 5)

Step-by-step explanation:

2x² + 11x + 5 =

= 2x² + 10x + x + 5

= 2x(x + 5) + (x + 5)

= (2x + 1)(x + 5)

Discriminant of 9x^2+12x+4=0

Answers

the\ discriminant\ of\ ax^2+bx+c=0:\ \ \ \ \Delta=b^2-4\cdot b\cdot c \n---------------------------\n9x^2+12x+4=0\ \ \ \Rightarrow\ \ \ \Delta=12^2-4\cdot9\cdot4=144-144=0\n\n\Delta=0\ \ \ \Rightarrow\ \ \ x_0=- (b)/(2a) =- (12)/(2\cdot9) =- (2\cdot2\cdot3)/(2\cdot3\cdot3)= - (2)/(3) \n\nAns.\ The\ discriminant\ is\ \Delta=0
9x^2+12x+4=0\n\n(3x)^2+2\cdot3x\cdot2+2^2=0\n\n(3x+2)^2=0\iff3x+2=0\n\n3x=-2\ \ \ /:3\n\nx=-(2)/(3)\n\n-------------------------------\n\n(a+b)^2=a^2+2ab+b^2
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