These values are standardized test scores. What is the mean score to the nearest tenth?27.2 13.5 42.1 37.9 25.0

Answers

Answer 1

Answer: First add up the numbers.
27.2+13.5+42.1+37.9+25=145.7
Now divide it by 5
29.14 or 29.1 rounded is the answer

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Jesse loves to go hiking on rustic trails through trees and along rivers. One day in 20 minutes of hiking she hiked 1 mile. If Jesse hike at a constant rate what would the rate be

Answers

Answer:

0.05 mile per minutes

Step-by-step explanation:

Jesse's rate of hiking (miles per minute) = Total miles covered / Time covered

Miles covered = 1 mile

Time covered = 20 minutes

Jesse's rate of hiking (miles per minute) = Total miles covered / Time covered(minutes)

= 1 mile / 20 minutes

= 0.05 mile per minutes

20 minutes

= 20 × 60 seconds

= 1200 seconds

Jesse's rate of hiking (miles per seconds) = Total miles covered / Total time taken (seconds)

= 1 mile / 1200 seconds

= 0.0008333333333 miles per seconds

Approximately 0.000833 miles per seconds

How do I factor
4x^3 - 6x^2 - 28x
show work please

Answers

4x^3 - 6x^2 - 28x

2x (x + 2) (2x - 7)

. Write the equation in slope intercept form for the line that goes through point (−10, 8) with slope =6.

Answers

y = mx + b is slope intercept form

x = -10
y = 8
m = 6

1. Solve for b

8 = (6)(-10) + b
b = 68

2. Plug m and b back into your slope intercept equation

y = 6x + 68

An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to get a 12% mixture? 30 lb 40 lb 60 lb

Answers

so, they alloy is hmmm some piece of metal.

it has tin, among other metals, regardless of what other metals it may have, we know that for the first one, 15% is tin, the rest something else, and we also know that the alloy itself, weights 20 lbs.

now, how much is just the weight of the tin metal in it alone? well, is 15% of 20 lbs, or (15/100) * 20, or 3 lbs, so of all those 20 lbs, only 3 lbs or 15% is tin.

for the second alloy, let's say we'll add "x" lbs, we know the second alloy is 10% tin, how much of that weight is tin? well 10% of x, or (10/100) * x, or 0.10x lbs.

now, we're looking for a mixture, say the resulting lbs of mix will be "y" lbs, and we know the mixture will be 12% of tin, how much is 12% of y? (12/100) * y, or 0.12y.

now, regardless of what "x" and "y" is, we know that 20 + x = y, and that 3 + 0.10x = 0.12y, thus

$\bf \begin{array}{lccclll} &\stackrel{lbs}{amount}&\stackrel{tin~\%}{quantity}&\stackrel{tin~lbs}{quantity}\n &------&------&------\n \textit{15\% alloy}&20&0.15&3\n \textit{10\% alloy}&x&0.10&0.10x\n ------&------&------&------\n mixture&y&0.12&0.12y \end{array} \n\n\n \begin{cases} 20+x=\boxed{y}\n 3+0.10x=0.12y\n ----------\n 3+0.10x=0.12\left( \boxed{20+x} \right) \end{cases} \n\n\n 3+0.10x=2.4+0.12x\implies 3-2.4=0.12x-0.10x \n\n\n 0.6=0.02x\implies \cfrac{0.6}{0.02}=x\implies 30=x$

Answer:

30 lb

Step-by-step explanation:

49.5 is what percent of 33?

Answers

$\begin{array}{ccc}33&-&100\%\n\n49.5&-&p\%\end{array}\n\ncross\ multiply\n\n33\cdot p=49.5\cdot100\ \ \ \ /:33\n\np=(4950)/(33)\n\np=150\n\nAnswer:150\%.$