Find -x + 10 less than 0.

0
-x + 10
x - 10

Answers

Answer 1

Answer: for
-x+10 < 0
x<-10

for
x-10<0
x<10

Related Questions

Marcie bought a can of corn at the supermarket. The price on the shelf said $3.99, but when Marcie went through the checkout lane, she presented the cashier with a piece of paper that allowed the cashier to reduce the price by $0.25. Which type of discount is this?A. A saleB. A gift cardC. A couponD. A rebate
Solve for x: 3x^2-5x=2
Can someone help me out real quick?
What is 95 percent of 240
Question is: Solve -7(x+6)=4(x+6)

The types of flowers shown in the table make up an arrangement. What percent of the flowers in the arrangement are rosesFlower Arrangement
Lilies: 4
Roses: 15
Snapdragons: 6

Answers

step 1) 4 lilies + 15 roses + 6 snapdragons = 25 total flowers which equals 100%
step 2) 15 roses / 25 total flowers IS EQUAL TO x% / 100%
step 3) cross multiply
1500 = 25x
step 4) divide
1500/25 = 25x/25
answer: x= 60%

I think it is 60% cause 15 ÷ 25= 0.6

If someone asked you, "Are debt and delinquency a problem in America?" What other information would you want to know in order to give an accurate answer?

Answers

To give an accurate answer, I'd request information relating to the total number of loans that are delinquent in relation to the total number that are being held by financial institutions.

Debt and Delinquency in America

In order to give an accurate answer when trying to ascertain whether or not a nation has delinquency and debt issues one must know the following:

the total number of loans that are delinquent; and the total number of loans that the financial institutions have given out.

The former is then divided by the latter. That is :

the number of loans that are delinquent

the total number of loans that an institution holds

The answer is left in a percentage format.

For example: 500/5,000 equals 10%.

See the link below for more about debt and delinquency:

brainly.com/question/9326088

Find out the expected value and the standard deviation of the number of aces obtained in 60 rolls of a fair 6-face die. Ditto for 600 rolls. Use them to explain why the observed count of aces obtained is more likely to be within 2 from the expected value with 60 rolls than with 600 rolls.

Answers

Answer:

E(X) = 60*1/6 = 10

sd(X) = √8.666 = 2.886

E(Y) = 600*1/6 = 100

sd(Y) = √86.666 = 9.1287

Step-by-step explanation:

Lets call X the amount of aces obtained in 60 rolls, and Y the amount of aces obtained in 600 rolls.

Note that both X and Y are obtained from counting the amount of successful tries from repetitions of independent experiments that have 1/6 of probability of success. Thus, both X and Y are random variables with binomial distribution, with n = 60 and 600 respectively and probability 1/6.

Remember that if Z is a random variable, Z ≈ Bi(n,p), then

E(Z) = np, where E(Z) denotes the expected value of Z
V(Z) = np(1-p), where V(Z) denotes the variance of Z. Hence, the standard deviation is the square root of V(Z), √(np(1-p)).

As a result

E(X) = 60*1/6 = 10
V(X) = 10*(1-1/6) = 50/6 ≅ 8.666
sd(X) = √8.666 = 2.886
E(Y) = 600*1/6 = 100
V(Y) = 100*(1-1/6) = 500/6 ≅ 86.666

sd(Y) = √86.666 = 9.1287

The observed amount of aces is more likely to be closer from the expected value with 60 rolls because, since we have less rolls, it is more difficult to obtain spread results.

You can also notice that X and Y can be obtained by summing independent variables with distribution BI(1,p) (also called Bernoulli(p) ). When you sum independent variables with the same distribution you have this property:

E(r1+r2+...+rn) = n*E(r1)
V(r1+r2+...+rn) = n*V(r1)

sd(r1+r2+...+rn) = √n*sd(r1)

X can be obtained by summing 60 independent variables r1, ...., r60 with mean 1/6 and variance 1/6*(5/6) = 5/36. So we obtain that V(X) = 60*5/36, and sd(X) = √60 * √(5/36). While for the same argument sd(Y) = √600*√(5/36). The higher the number of rolls, the more spread the results are.

I hope this helped you!

The expected number of aces from 60 rolls of a fair die is 10 with a standard deviation of approximately 3.72. For 600 rolls, the expected number is 100 with a standard deviation of about 11.79. The observed count of aces is more likely to be closer to the expected value with fewer rolls due to the smaller standard deviation relative to the number of trials.

The expected value for the number of aces in a fair die roll is computed by multiplying the probability of rolling an ace $((1)/(6))$ by the number of rolls. For 60 rolls, the expected number is $60 * ((1)/(6)) = 10 aces$ . For 600 rolls, the expected number is $600 * ((1)/(6)) = 100 aces$

The standard deviation for the number of aces is calculated using the formula for the standard deviation of a binomial distribution, $\sqrt(n* p* (1-p))$ , where n is the number of trials, p the probability of success ( $((1)/(6))$ for an ace). For 60 rolls, it is $\sqrt(60* ((1)/(6))* ((5)/(6))) \approx 3.72$ . For 600 rolls, it's $\sqrt(60* ((1)/(6))* ((5)/(6))) \approx 11.79$ .

When you roll the die 60 times, the chances of the observed count of aces being within 2 from the expected value (10) is higher because the standard deviation is smaller relative to the number of trials than when you roll the die 600 times.

As the number of trials increases, the expected standard deviation grows larger, and the observed count is more likely to be within a wider range from the expected value (100).

Learn more about standard deviation here:

brainly.com/question/32256698

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Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x).

Answers

Substitute the two functions according to a given condition of function:
f(x) - g(x) = 3x² + x - 3 - (x² - 5x + 1)
= 3x² + x - 3 - x² + 5x - 1
= 2x² + 6x - 4 or 2(x² + 3x - 2)

f(x) - g(x) = 3x² + x - 3 - (x² - 5x + 1)
f(x) - g(x) = 3x² + x - 3 - x² + 5x - 1
f(x) - g(x) = 3x² - x² + x + 5x - 3 - 1
f(x) - g(x) = 2x² + 6x - 4

9(n-4)-7n=32-2(n+8)

Answers

Answer:

answer is 13

Step-by-step explanation:

hope it helps.

A nurse mixes 50 cc of a 60% saline solution with a 10% saline solution to produce a 20% saline solution. How much of the 10% solution should he use?

Answers

Answer:

The nurse should use 200cc of the 10% saline solution in order to produce a 20% saline solution.

Step-by-step explanation:

to the given mix we add a quantity of a lower mix to generate another.

50cc at 60% + Xcc at 10% = (50 + X)cc at 20%

50 x 60% + X x 10% = (50 + X) x 20%

30 + 0.1X = 10 + 0.2X

30 - 10 = 0.2X - 0.1X

20 = 0.1X

20/0.1 = X

X = 200

Final answer:

To produce a 20% saline solution, the nurse should use 200 cc of the 10% saline solution.

Explanation:

To find out how much of the 10% saline solution the nurse should use, we can set up an equation using the idea that the amount of saline in the mixture is equal to the sum of the amounts of saline in each solution.

Let's say the nurse uses x cc of the 10% saline solution. The amount of saline in the 60% saline solution will be 0.6 * 50 cc = 30 cc. The amount of saline in the 10% saline solution will be 0.1 * x cc = 0.1x cc.

Since the resulting solution is 20% saline, the total amount of saline in the mixture will be 0.2 * (50 + x) cc. Setting up the equation, we have 30 + 0.1x = 0.2 * (50 + x).

Simplifying the equation, we get 30 + 0.1x = 10 + 0.2x. Solving for x, we find that x = 200 cc.