What does sealant restorations mean?

Answers

Answer 1
Answer: Sealants are used to protect healthy teeth that have a high potential for decay. Most often, these are the molars with deep grooves. A PRR, preventive resin restoration, is a type of filling that is placed when a cavity has begun and is infiltrating the grooves in the chewing surface of the tooth............

Related Questions

If an oxygen has 8 protons in its nucleus what is its atomic number A.6 B.8 C.4 D.12
Which electromagnetic waves emitted from the sun produce a heating effect?
Find the equivalent resistance in the circuit between A and B ​
What role does Nitrogen play for all living organisms?​
What is the mass of a car that has a speed of 30 m/s and a momentum of 45,000 kg, m/s

What is the relashinship between the mass and size of a planet?

Answers

size is in relation to distance(how far across or around)mass is measuring how much there is, mass is related to both size and DENSITY, EX: A balloon has a large size but a tiny mass, compared to a bowling ball, which has a similar size but a much larger mass 

When light moves from one medium to another it can be ______________

Answers

When light moves from one medium to another it can be Refraction

Explanation:

Refraction is the term used to define light movement travelling from one medium to another. Light waves are propagated, will cross the boundary and their direction is also changed during the process of refraction.

Velocity is also induced in the light which keeps changing during its propagation through mediums. There are other phenomenons of light like reflection, interference, diffraction which are slightly different from each other and hence proper understanding is required to differentiate between them.

when light moves from one medium to another it can be refracted

An Atwood machine is constructed using twowheels (with the masses concentrated at the
rims). The left wheel has a mass of 2.5 kg and
radius 22.2 cm. The right wheel has a mass
of 2.7 kg and radius 27.49 cm. The hanging
mass on the left is 1.59 kg and on the right
1.24 kg
m
mz
What is the acceleration of the system?
The acceleration of gravity is 9.8 m/s.
Answer in units of m/s.

Answers

Left:
2*g-TL=2*aL
aL=α*0.231
therefore
TL=2*(g-α*0.231)

Right:

TR-1.4*g=4*aR
aR=α*0.272
therefore
TR=1.4*(g+α*0.272)

Wheels:
TL*0.231-TR*0.272=
(2*0.231^2+2.3*0.272^2)*α

combine and solve for α

Imagine that you are baking brownies for a bake sale at school. Which of the following pans is least likely to cause you to burn the bottoms of your brownies?a glass pan, an aluminum pan, a cast iron pan or a copper pan

Answers

glass will work the best

When traveling at top speed, a roller coaster train with a mass of12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed is

Answers

Answer:

The kinetic energy of the train at top speed is 5,400,000 J

Explanation:

Kinetic Energy

It's the capacity that an object has to do work in virtue of its velocity. If we use UI units for the mass and velocity, the kinetic energy is expressed in Joules, or Nw.m or Kg.m^2/sec^2. It can be computed with the formula

\displaystyle K=(mv^2)/(2)

The roller coaster train has a mass of 12,000 kg and a velocity of 30 m/s. Replacing those values in the formula, we have:

\displaystyle K=(12,000\ 30^2)/(2)

\displaystyle K=(12,000\ 900)/(2)

\displaystyle K=5,400,000\ J

Answer: the first answer is 5,400,000 the second one is 46

Explanation: hope it helps : ]

Earth has a mass of 5.97 x 1024kg, and a mean radius of 6.38 x 10m. What would be the orbitasatellite in orbit 1.44 x 108 m above Earth?
a. v, = 630m/s,
c. v, - 1630m/s,
T = 2.78 x 10 s
T=5.78 x 10s
b. V = 1820m/s,
d. V, - 1260m/s,
T = 6.78 x 106 s
T=5.78 x 10's
Please select the best answer from the choices provid​

Answers

Answer:

v = 1630 m/s

T = 5.78 x 10^5 s

Explanation:

The tangential speed of the satellite can be found by requiring that the gravitational force on the satellite is equal to the centripetal force:

G(Mm)/((R+h)^2)=m(v^2)/(R+h)

where

G is the gravitational constant

M=5.97 x 1024kg is the Earth's mass

m is the satellite's mass

R=6.38 \cdot 10^6 m is the Earth's radius

h=1.44\cdot 10^8 m is the altitude of the satellite

v is the speed of the satellite

Solving for v,

v=\sqrt{(GM)/(R+h)}=\sqrt{((6.67\cdot 10^(-11))(5.97\cdot 10^(24)kg))/(6.38\cdot 10^6 m+1.44\cdot 10^8 m)}=1627 m/s \sim 1630 m/s

And the period of the orbit is equal to the ratio between the distance covered during one revolution (the circumference of the orbit) and the speed:

T=(2 \pi (R+h))/(v)=(2\pi (6.38\cdot 10^6 m+1.44\cdot 10^8 m))/(1630 m/s)=5.79\cdot 10^5 s

So the correct answer is

v = 1630 m/s

T = 5.78 x 10^5 s