Peter figures he can build the entire tree house by himself in 20 hours. He figures that each additional friend who helps him would improve the time by 10%. He created a table using the algebraic expression n – n(0.10), where n is the previous number of hours.To the nearest tenth of an hour, how long will it take to build the tree house if 4 friends are helping?
It will take
hours.

Answers

Answer 1
Answer:

If four friends assist, it will take 13.12 hours to construct the tree home.

What is algebraic Expression?

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Given this, Peter figures he can build the entire tree house by himself in 20 hours. He figures that each additional friend who helps him would improve the time by 10%.

An algebraicexpression that determines the given condition is:

n – n(0.10)

=> n(1- 0.1)

=> n* 0.9

Since the above equation is for A friend and it's given there are four friends helping him.

Thus,

The final time is taken in building the tree house if 4 friends are helping:

=> n * 0.9^4

Where n is 20

=> 20 * 0.9^4

=> 13.122

Therefore, it will take 13.12 hours to build the tree house if 4 friends are helping.

Learn more about algebraic Expression here:

brainly.com/question/953809

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Answer 2
Answer:

Answer:

the answer is 13.1 i just did the assignment and got it right.

Step-by-step explanation:


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sam is practicing long track speed skating at an ice skating rink.the distance around the ring is 250 yards he has skated around the rink 9 times so far how many more yards does he need to skate around the rink to complete 3 miles?

Answers

Sam would need to travel around the rink 12 more times to reach 3 miles.
Roughly 12 more times but to be exact 12.12 times

teams of four are competing in a quarter mile relay. each runner must run the same exact distance. what is the distance each teammate runs?

Answers

Each teammate runs 1/16 miles.

Further Explanation

Given:

  • There are four people in a team
  • The running distance  is 1/4 mile
  • Each runner must run the exact distance

Question:

what is the distance each teammate runs?

Each person will run =        the total distance              

                                      number of person in a team

\boxed {= (1)/(4) : 4 }

we can write that equation in multiplication form as follow:

\boxed {= (1)/(4) *(1)/(4) = (1)/(16) }

So, each person in the team will run \boxed {(1)/(16) } miles

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Keywords: fraction, fraction multiplication, improper fraction, proper fraction, numerator, denominator, divide a whole number by unit fraction


A quarter is 1/4, and each runner runs 1/4 of that distance, so multiply the two numbers together to find the distance run by each runner: 1/16 of a mile, or 0.0625 miles.

I need help im desperate i'll give 30 points to anyone who answers.Fill in the missing pieces of the problem using distributive property. You will need to get an answer of 48.

4 ( __ + __)

answer = 48

Answers

Anything that adds up to 12 has to go in the parethese.

48 / 4 = 12

So 1 and 11

2 and 10

3 and 9

4 and 8

5 and 7

or

6 and 6

Answer:

answer =48

Step-by-step explanation:


Jerome added two numbers. The sum was 83. One of the numbers was 45.What was the other number? Work shown please

Answers

Put one number as x and the other as  y
x+y=83
Since we already know one is 45, we substitute one of them for 45.
45+x=83
Subtract 45 on each side
x=38
The other number is 38. Hope this helps. 

For 1 through 3, use grid paper to draw two different rectangles with the given perimeter. Tell the dimensions and area of each rectangle. Circle the one that has the greater area. 1. 12 meters. 2. 28 inches 3. 20 feet

Answers

12 meters has the greatest area. A foot is equal to about .3 meters (i believe it is .305)

I need help with the answer

Answers

I believe your answer would be 3/4.
2/5+1/4+1/10=?
find the lowest commune denominator
20 
5×4=20  4×5=20   10×2=20
2×4=8    1×5=5     1×2=2
8+5+2=15
15/20
redoes to lowest terms
3/4