What information in the MSDS would be most important to know at the end of an experiment?

Answers

Answer 1

Answer: The most important information in the MSDS that is useful at the end of an experiment is how to manage or dispose of the waste materials of the experiment. This is important especially if the materials used are toxic. They cannot just be disposed in the sink or the trash bin. They must be disposed in a waste bottle or other methods.

Answer 2

Answer:

Answer:

I think it is

C. the disposal procedure

Explanation:

if im wrong im very sorry

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Bird man is flying horizontally at a speed of 33m/s and a height of 86m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hold the bucket to catch the turd.

Answers

Answer:

2838

Explanation:

88.0 km to m (in physics prefixes )

Answers

We know that,

kilometre = 1000 metre

1000 can be written as 10³ which is kilo.

Given,

88.0km = 88.0×1000

= 88.0×10³m

Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?

Answers

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

$d = d_(1) + d_(2) = 50 km + 30 km = 80 km$

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

$x = x_(1) + x_(2) = 50 km + (-30 km) = 20 km$

Therefore, Tyler's displacement is 20 km.

You can find more about displacement and distance here: brainly.com/question/4307551?referrer=searchResults

I hope it helps you!

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

A biconvex lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvature with magnitudes of R 1= 10cm and R 2 = 15cm. The lens is made of glass with index of refraction n=1.5. We will employ the convention that R 1 refers to the radius of curvature through wich light will enter the lens, and R 2 refers to the radius of curvature from which the light will exit the lens.Is this lens converging or diverging?

What is the focal length of this lens in air?

Answers

Answer:

The focal length is 12 cm and the lens is converging.

Explanation:

Given that,

Radius, R ₁=10 cm

R₂ =15 cm

Index of refraction n= 1.5

We need to calculate the focal length of the lens

Using formula of focal length

$(1)/(f)=(n-1)((1)/(R_(1))+(1)/(R_(2)))$

Put the value into the formula

$(1)/(f)=(1.5-1)((1)/(10)+(1)/(15))$

$(1)/(f)=0.0833$

$f =12\ cm$

The focal length of the lens is positive so the lens is converging.

Hence, The focal length is 12 cm and the lens is converging.

Final answer:

A biconvex lens is a type of converging lens. Using the Lensmaker's formula and the given values, the focal length of the lens in air is calculated to be 30cm.

Explanation:

A biconvex lens, which is defined by both surfaces of the lens bulging outwards, is a form of converging lens due to its ability to bend parallel light rays toward a single focal point after they pass through the lens. The focal length of the lens can be calculated using the Lensmaker's formula, which is 1/f = (n-1)[(1/R1) - (1/R2)]. Applying the given values, we find that the focal length f = 1/[(1.5-1)[(1/10)-(1/15)]] = 30cm.

Therefore, this biconvex lens is a converging lens with a focal length of 30cm in air.

Learn more about Biconvex Lens here:

brainly.com/question/34783124

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In Alamogordo, New Mexico, falling rocks are a hazard along US Highway 82. If a rock falls from a cliff with 157 N of force,what was the mass of the rock?