Evaluate x0 + y0 for x = 3 and y = 2.

Answers

Answer 1
Answer:

Answer:

The value of given expression is 2

Step-by-step explanation:

Given: Expression is x^0+y^0

To find : Value of expression when x = 3 and y = 2

Consider,

x^0+y^0

To find value we put value of x = 3 and y = 2

\implies 3^0+2^0

Now we know that value of expression whose power 0 is 1 irrespective of value of base .i.e, a^0=1 ∀ a ∈ any no.

3^0=1\:and\:2^0=1

\implies 3^0+2^0 = 1 + 1

⇒ 2

Therefore, The value of given expression is 2

Answer 2
Answer:

Good evening


x^0+y^0 for x=3 and y=2

First thing we need to do is to replace their value

3^0+2^0

Remember: Any number that raised to the zero power equal 1

so now we have

3^0=1 and y^2=1

1+1

= 2


I hope that's help :0


Any Questions /

 


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Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, andm∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.

Answers

         m∠A + m∠B = 90
(3x + 5) + (2x - 15) = 90
(3x + 2x) + (5 - 15) = 90
                  5x - 10 = 90
                      + 10  + 10
                         5x = 100
                          5      5
                           x = 20

m∠A = 3x + 5
m∠A = 3(20) + 5
m∠A = 60 + 5
m∠A = 65

m∠B = 2x - 15
m∠B = 2(20) - 15
m∠B = 40 - 15
m∠B = 25
m∠A + m∠B = 90

(3x + 5) + (2x - 15) = 90

(3x + 2x) + (5 - 15) = 90

5x - 10 = 90

5x - 10 +10 = 90+10

5x = 100

5x/5 = 100/5      Divide \ both \ sides \ by \ 5

x = 20                 Solutions

m∠A = 3x + 5     (x=20)

m∠A = 3(20) + 5          Substitute \ x \ for \ 20

m∠A = 60 + 5               Simplify

m∠A = 65


m∠B = 2x - 15

m∠B = 2(20) - 15

m∠B = 40 - 15

m∠B = 25

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Answers

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An initial investment of $150,000 grows at 22% per year. What function represents the value of the investment after t years?​

Answers

Answer:

150000(1.22)^t

Step-by-step explanation:

A-150000

R- 0.22 plus the 1 since it’s positive y=A(1+r)

Sooo 150000(1+0.22)^t

How can you evaluate this expression using the distributive property?
5×(7+6)

Answers

Answer:

35+30=65

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

you first do what is in the ( ) then multiply by 5

A chocolate factory produces mints that weigh 10 grams apiece. The standard deviation of the weight of a box of 10 mints is 3 grams. You buy a box of mints that weighs 95 grams. What is your confidence that the box you bought did not come from the factory?A 90%
B 95%
C 10%
D 5%

Answers

Answer:  Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Population Mean weight (\mu)= 10 grams a piece

Standard deviation of the weight of a box = 3 grams

Number of mints = 10

We need to buy a box of mints that weighs 95 grams.

Sample mean is given by

x=(95)/(10)=9.5\ grams

First we find out the standard error which is given by

s=(\sigma)/(√(n))\n\n=(3)/(√(10))\n\n=0.94868

Since it is normal distribution, so, we will find z-score.

z=(x-\mu)/(s)\n\nz=(9.5-10)/(0.94868)\n\nz=-0.527\n\nz=-0.53

The area to the left of a z-score of -0.53 = 0.29805.

So, it may be 90% or 95 % confidence.

For 95% confidence level,

\alpha=(1-0.95)/(2)=0.025

Similarly,

For 90% confidence level,

\alpha=(1-0.90)/(2)=0.05

We have little confidence that the box he bought did not come from the factory. that is much smaller than 0.05.

So, it is safe to assume 90% confidence.

So, we will get 90% confidence, critical value = 1.645

Margin of error is given by

(Standard\ deviation)* (critical\ value)\n\n=0.94868* 1.645\n\n=1.56

So, confidence interval will be

(10-1.56,10+1.56)

=(8.44,11.56)

Hence, Option 'A' is correct.

The right answer for the question that is being asked and shown above is that: "C 10%." A chocolate factory produces mints that weigh 10 grams apiece. The standard deviation of the weight of a box of 10 mints is 3 grams. You buy a box of mints that weighs 95 grams. 

Indicate whether the following statements are True (T) or False (F). 1. The difference of two integers is always a natural number. 2. The difference of two integers is always an integer. 3. The sum of two integers is always an integer. 4. The quotient of two integers is always an integer (provided the denominator is non-zero). 5. The ratio of two integers is always positive 6. The product of two integers is always an integer. 7. The quotient of two integers is always a rational number (provided the denominator is non-zero).

Answers

1. False (F): Example: 2-3=-1∉N
2. True (T)
3. True (T)
4. False (F): Example: 3/4=0.75 which is not an integer
5. False(F) : Ratio can be negative if one but not the other integer is negative. Example: 5 : (-1)= -5
6. True (T) 
7. True (T)