Johnathan can jog 3 2/3 miles in 7/8 hour. Determine his average speed in miles per hour.

Answers

Answer 1

Answer: If you would like to know Johnathan's average speed in miles per hour, you can calculate this using the following steps:

3 2/3 = 11/3 miles ... 7/8 hour
x miles = ? ... 1 hour

11/3 * 1 = 7/8 * x
11/3 = 7/8 * x
x = 11/3 * 8/7
x = 88/21
x = 4 4/21 miles

The correct result would be 4 4/21 miles per hour.

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Which lines are parallel? Justify your answer.

Answers

parallel lines never touch, if that helps.

Answer:

Step-by-step explanation:

this is a example of parallel the lines must be equal and not touch or cross each other

Reason Lena is making a puzzle, she cuts a shape into5. two pieces and rearranges them to make the shape below.Which shape did she start with?6. Draw a picture to show how you can rearrangerthe four triangles cut from a rectangle to makea concave hexagon.

Answers

The answer to 5 is D

Solve for the missing variable :> thank you

Answers

1. 3x+16 = 5x-54

-3x -3x

16=2x-54

+54 +54

70 = 2x

35=x

2. 4x-10 = 58

+10 +10

4x = 68

x=17

3. 2x+43 = 2x-3

x=0

no solution

4. x+16 = 4x-5

-x -x

16=3x-5

+5 +5

21=3x

x=7

5. 11y-36 = 63

+36 +36

11y=99

y=9

Find all possible value of the given variable 1.h²+5h=0
2.z²-z=0
3.m²+13m+40=0
4.z²-3z=0
5.q²+7q=0
6.k²+2k=0
7.x²-3x-70=0
8.q²+7q-60=0
9.z²+9z-36=0
10.d²-13d+22=0

Answers

$1.\n \n h^2+5h=0 \n \nh(x+5)=0\n \nx=0 \ \ \ or \ \ \ x+5 =0\ \ |-5\n \nx+5-5=0-5\n \nx=0 \ \ \ or \ \ \ x=-5$

$2.\n \n z^2-z=0\n \nz(x-1)=0\n \nz=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\n \nz-1+1 =0 +1 \n \nx=0 \ \ \ or \ \ \ z=1$

$3.\n \nm^2+13m+40=0 \n \na=1 ,\ b=13, \ c=40 \n \n\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \n \nand \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution$

$4.\n \nz^2-3z=0 \n \n (z-3)=0\n \nz=0 \ \ \ or \ \ \ z-3 =0\ \ |+3\n \n z-3+3=0+3\n \nz=0 \ \ \ or \ \ \ z=3$

$5.\n \nq^2+7q=0 \n \nq(q+7)=0\n \nq=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\n \nq+7-7=0-7\n \nq=0 \ \ \ or \ \ \ q=-7$

$6.\n \nk^2+2k=0\n \nk(k+2)=0\n \nk=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\n \nk+2-2=0-2\n \nk=0 \ \ \ or \ \ \ k=-2$

$7. \n \n x^2-3x-70=0 \n \na=1,\ b=-3, \ c=-70 \n \n\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\n \n x_(1)=(-b-√(\Delta) )/(2a)=(3-√(289))/(2 )=( 3-17)/(2)=(-14)/(2)=-7$

$x_(2)=(-b+√(\Delta) )/(2a)=(3+√(289))/(2 )=( 3+17)/(2)=(20)/(2)=10\n \n(x+7)(x-10)=0$

$8.\n \nq^2+7q-60=0 \n \na=1,\ b=7, \ q=-60 \n \n\Delta =b^2-4ac = 7^2-4\cdot 1\cdot (-60)=49+240=289 \n \n x_(1)=(-b-√(\Delta) )/(2a)=(-7-√(289))/(2 )=( -7-17)/(2)=(-24)/(2)=-12$

$x_(2)=(-b+√(\Delta) )/(2a)=(-7+√(289))/(2 )=( -7+17)/(2)=( 10)/(2)= 5\n \n(x+12)(x-5)=0$

$9.\n \nz^2+9z-36=0 \n \na=1,\ b=9, \ q=-36 \n \n\Delta =b^2-4ac = 9^2-4\cdot 1\cdot (-36)= 81+144=225\n \n x_(1)=(-b-√(\Delta) )/(2a)=(-9-√(225))/(2 )=( -9-15)/(2)=(-24)/(2)=-12$

$x_(2)=(-b+√(\Delta) )/(2a)=(-9+√(225))/(2 )=( -9+15)/(2)=(6)/(2)=3\n \n(x+11)(x-3)=0$

$10.\n \nd^2-13d+22=0 \n \na=1,\ b=-13, \ q=22 \n \n\Delta =b^2-4ac = (-13)^2-4\cdot 1\cdot 22= 169-88=81\n \n d_(1)=(-b-√(\Delta) )/(2a)=(13-√(81))/(2 )=( 13-9)/(2)=(4)/(2)=2$

$d_(2)=(-b+√(\Delta) )/(2a)=(13+√(81))/(2 )=( 13+9)/(2)=(22)/(2)=11\n \n(d-2)(d-11)=0$

A group of 10 friends had lunch together at a restaurant. The meal cost a total of $99.50, including a 15% tip. How much was the total bill for lunch before the tip?

Answers

Cost of meal before tip + 15% = $99.50

Adding 15% is equal to multiplying by 1.15

Cost of meal before tip x 1.15 = 99.5

This can be rearranged to give;

Cost of meal before tip = $(99.5)/(1.15)$

Cost of meal before tip = $86.52

each meal was $9.95 a peice aND EACH HAD TO pay $1.50 on the tip

Can someone help please??

Answers

Answer:

BC= 5.87 (nearest hundredth)

Step-by-step explanation:

Please see attached picture for full solution.

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