What are the solutions of 3x^2 + 14x + 16 = 0?x = -8/3, –2

x = –2, -3/8

x = 3/8, 2

x = 8/3, 2

Answers

Answer 1
Answer:

Answer:

The correct option is A) x = -8/3, –2.

Step-by-step explanation:

Consider the provided equation 3x^2 + 14x + 16 = 0

The above equation is in the form of ax^2 +bx + c = 0

The quadratic formula to find the root of the equation is:

{\displaystyle x={\frac {-b\pm {\sqrt {b^(2)-4ac}}}{2a}}\ \ }

By comparing the above equation with the general equation we can conclude that:

a = 3, b = 14, and c = 16

Substitute the respective values in the above formula:

{\displaystyle x={\frac {-14\pm {\sqrt {14^(2)-4(3)(16)}}}{2(3)}}\ \ }

{\displaystyle x={\frac {-14\pm {\sqrt {196-192}}}{6}}\ \ }

{\displaystyle x={\frac {-14\pm {\sqrt {4}}}{6}}\ \ }

{\displaystyle x={\frac {-14\pm2}{6}}\ \ }

{\displaystyle x={\frac {-14+2}{6}}\ \ } or\ {\displaystyle x={\frac {-14-2}{6}}\ \ }

{\displaystyle x={\frac {-12}{6}}\ \ } or\ {\displaystyle x={\frac {-16}{6}}\ \ }

{\displaystyle x=-2}\ \ } or\ {\displaystyle x={\frac {-8}{3}}\ \ }

Hence the solutions of the provided equation is {\displaystyle x=-2}\ \ } or\ {\displaystyle x={\frac {-8}{3}}\ \ }.

Thus, the correct option is A) x = -8/3, –2.

Answer 2
Answer: the solution is :
x= -8/3 , -2

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Relative minimum: the point on the graph where the interval changes from A. Increasing B. Decreasing C. Input D. Output

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Answer:

c

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

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Answers

3.(4p−2)(p−4)
=(4p+−2)(p+−4)

=(4p)(p)+(4p)(−4)+(−2)(p)+(−2)(−4)

=4p2−16p−2p+8

=4p2−18p+8

Simplified form - 
4p2−18p+8

4.
(2x2+4x−3)(3x+1)

=(2x2+4x+−3)(3x+1)

=(2x2)(3x)+(2x2)(1)+(4x)(3x)+(4x)(1)+(−3)(3x)+(−3)(1)
=6x3+2x2+12x2+4x−9x−3

=6x3+14x2−5x3

Simplified form - 
6x3+14x2−5x3

A coordinate grid with 2 lines. The first line labeled f(x) passes through (negative 3, 3), (0, 2), and (3, 1). The second line labeled g(x) passes through the points at (negative 3, 0) and (0, 2) What is the solution to the system of linear equations? (–3, 0) (–3, 3) (0, 2) (3, 1)

Answers

The solution to the system of linear equations is (0,2). The correct option is C.

What is a system of linear equations?

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.

It is given that in a coordinate grid with 2 lines. The first line labelled f(x) passes through (-3, 3), (0,2), and (3, 1). The second line labelled g(x)passes through the points at (-3, 0) and (0, 2).

Plotting the two lines by using the points on the graph. After plotting the points there will be two lines that will intersect at the point ( 0, 2 ). Then the solution of the equation is ( 0,2).

Therefore,the solution to the system of linear equations is (0,2). The correct option is C.

To know more about equations follow

brainly.com/question/2972832

#SPJ15

Answer:

(0, 2) or C

Step-by-step explanation:

how do I figure out the weight loss of tina? she lost 3 pounds on the first week of her diet. she gained a pound on the second week, and then lost 2 pounds a week during every week afterwards. she has been dieting for a total of 13 weeks. how many pounds has tina lost in all?

Answers

1st week - Lost 3 pounds = +3 
2nd week - Gained 1 pound = -1    
3+13 = + 22       

So 22+3 = 25                 25-1 = 24 

So Tina lost 24 pounds in 13 weeks. 

Please help! I don't understand this question! 19 pts1.) A projectile launched straight up into the air with an initial velocity of 20 meters per second from a height of 10 meters. How long will it take for the projectile to hit the ground?

a.) Which formula should be used?
h(t) = -4.9t² + vot + ho
h(t) = -16t² + vot + ho

b.) What is the vo?
c.) What is the ho?
d.) Use the Quadratic Formula to solve

Answers

Hello,


gravity on earth :g=9.81 m/s²
h(t)=-(g*t^2)/(2)+v_(0)*t+h_(0)
9.81/2≈4.9
v_(0)\ is\ initial\ speed
h_(0)\ is\ initial\ height

Answer 1


2)
h(t)=-4.9*t²+20*t+10

To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²

t=(-20-4√35)/(-4.9*2)=4,4555...(s)

t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)









in a swimming race, a student swam the first 50 meters in 42 seconds. she swam the secons 50 meters in 40 seconds. what was the students average speed during the race?

Answers

All you have to do is add 40 and 42 together and divide by 2. It's basically finding the mean.