What type of compound is always an electrolyte?a. polar covalent
b. nonpolar covalent
c. ionic
d. network solid

Answers

Answer 1
Answer:

Answer:

Options A and C

Explanation:

An electrolyte is a substance that produces an electrically conducting solution when dissolved in a polar solvent, such as water. The dissolved electrolyte separates into cations and anions, which disperse uniformly through the solvent.

Based on the definition above the key factor is the ability of the substance to separate into cations and anions.

Option A - This is correct because Some polar covalent compounds are also strong electrolytes. A typical example is HCl.

Option B - This is incorrect because nonelectrolytes end to contain covalent bonds and are typically nonpolar molecules.

Option C - Electrolytes tend to contain ionic bonds that break when the chemical interacts with water and other polar solvents. So electrolytes are typically ionic compounds. This ption is correct.

Option D - A network solid or covalent network solid is a chemical compound (or element) in which the atoms are bonded by covalent bonds in a continuous network extending throughout the material. Examples of network solids include diamond. This option is also incorrect.

Answer 2
Answer: Ionic compounds are always electrolytes because they dissociate into ions in solution

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1. Identify evidence that a chemical reaction has occurred.
2. What element is the most abundant in this chemical reaction?
3. Identify the number of protons, neutrons, and electrons found in the most
abundant element.
4. Identify where we would find the protons, neutrons, and electrons in the
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5. Identify the group and period of the element on the Periodic Table.
swer

Answers

Answer:

1. The evidence that chemical reaction has occurred can be found in the change of the reagents present after the reaction, that is formation of glucose in the area where the reaction is taking place

2. The most abundant element of the chemical reaction is oxygen which has a total quantity of 18 atoms in the reaction

3. The oxygen atom has an atomic number of 8 and therefore contains 8 protons and 8 neutrons and (therefore) 8 electrons (to be neutral, electronically)

4. The protons and the neutrons of the atom, oxygen, are located in the nucleus, while the electron are found in the different orbitals surrounding the atom

5. The element, oxygen, symbol, O, belongs to the group 16 of period 2 in the periodic table

Explanation:

What is something a scientific law and a scientific theory have in common? Responses
A Both are backed up by evidence and facts Both are backed up by evidence and facts)
B Neither can be proven correct Neither can be proven correct)
C Both make a statement about a scientific phenomenon Both make a statement about a scientific phenomenon0,
A Both answer "why")

Answers

A. Both are backed up by evidence and facts!
- scientific law is made up of evidence
and facts or not it wouldn’t be a law.
- scientific theories are also backed up!
You need to have facts in order to
make it into a theory.

- it’s important to know that scientific
theories can become scientific laws :)

Is there any difference between carbon(iv)oxide and carbon(ii)oxide

Answers

The difference is the no. of charges  present in Carbon, meaning Carbon has different charges therefore Roman numerals are used to clarify the exact number.This makes balancing equations easier.

Also their names are different.
CO4 - Carbon tetroxide
CO2 - Carbon dioxide

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions. Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) S (s) (nonspontaneous)? Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq) (nonspontaneous)? 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq) (spontaneous?) Are these correct?

Answers

A electrochemical reaction is said to be spontaneous, if E^(0) cell is positive. 

Answer 1:
Consider reactionNi^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s) 

The cell representation of above reaction is given by;
    
S^(2-)/S // Ni^(2+)/Ni

Hence, E^(0)cell = E^(0) Ni^(2+/Ni) - E^(0) S/S^(2-)
we know that, {E^(0) Ni^(2+)/Ni = -0.25 v
and {E^(0) S/ S^(2-) = -0.47 v

Therefore, E^(0) cell = - 0.25 - (-0.47) = 0.22 v

Since,  E^(0) cell is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2: 
Consider reactionPb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
    H_(2) / H^(+) // Pb^(2+) /Pb

Hence, E^(0)cell = E^(0) Pb/Pb^(2+) - E^(0) H_(2)/H^(+)
we know that, {E^(0) Pb^(2+)/Pb = -0.126 v
and {E^(0) H_(2)/ H^(+) = -0 v

Therefore, E^(0) cell = - 0.126 - 0 = -0.126 v

Since,  E^(0) cell is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3
Consider reaction2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
    Cr/Cr^(2+) // Ag^(+)/Ag

Hence, E^(0)cell = E^(0) Ag^(+)/Ag - E^(0) Cr/Cr^(2+)
we know that, {E^(0) Ag^(+)/Ag = -0.22 v
and {E^(0) Cr/ Cr^(2+) = -0.913 v

Therefore, E^(0) cell = - 0.22 - (-0.913) = 0.693 v

Since,  E^(0) cell is positive, hence cell reaction is spontaneous

Answer: Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)  : non spontaneous

Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)  : non spontaneous

2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)  : spontaneous

Explanation:

a) Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)

Here S undergoes oxidation by loss of electrons, thus act as anode. Ni undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Ni^(2+)/Ni])=-0.25V

E^0_([S^(2-)/S])=0.407VV

E^0=E^0_([Ni^(2+)/Ni])- E^0_([S^(2-)/S])

E^0=-0.25-(0.407V)-0.657V

As value of E^0 is negative, the reaction is non spontaneous.

b)Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)

Here Hydrogen undergoes oxidation by loss of electrons, thus act as anode. Pb undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Pb^(2+)/Pb])=-0.13

E^0_([H^(+)/H_2])=0V

E^0=E^0_([Pb^(2+)/Pb])- E^0_([H^(+)/H_2])

E^0=-0.13-(0V)=-0.13V

As value of E^0 is negative, the reaction is non spontaneous.

c) 2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)

Here Cr undergoes oxidation by loss of electrons, thus act as anode. Ag undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Ag^(+)/Ag])=+0.80V

E^0_([Cr^(2+)/Cr])=-0.913V

E^0=E^0_([Ag^(+)/Ag])- E^0_([Cr^(2+)/Cr])

E^0=+0.80-(-0.913V)=1.713V

As value of E^0 is positive, the reaction is spontaneous.

Name the compound of AuO

Answers

If it existed it would be gold(II) oxide. The stable gold oxide is gold(III) oxide Au2O3

What type of Bond exist in a molecule of hydrogen Iodide

Answers

Is it polar covalent?