Adina has a rectangular garden that measures 9 m wide by 13 m long. She wants to increase the area to 192 m^2 by increasing the width and length by the same amount. What will be the width (shorter dimension) of the new garden?Question 4 options:

a) 14 m wide

b) 13 m wide

c) 12 m wide

d) 11 m wide

Answers

Answer 1
Answer: area=legnth times width
192=(9+x)(13+x)
solve
expand
192=117+22x+x^2
minus 192 both sides
0=x^2+22x-75
factor
0=(x-3)(x+25)
set to zero

x-3=0
x=3

x+25=0
x=-25
not possible since that gives negative legnths and widhs

increased by 3

shorter is 9
9+3=12

C is ansre

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Which value, when placed in the box, would result in a system of equations with infinitely many solutions?y=2x-5
2y - 4x =
10
5
10

Answers

Answer: -10

Step-by-step explanation:

(please help me) (I've been trying to figure this out for hours) (I screenshot the question and choices D: <3 )

Answers

It would be the third answer choice. m<1= 60, m<2= 30, and m<3= 60

The hexagon is split equally, making all the triangles there equilateral, and their angles equal all 60 degrees. That automatically makes angle one and three 60 degrees. For angle two, there is a line, splitting the triangle in half. There are two ways to consider this:

1. Think about the 30°, 60°, 90° special triangles.

or 

2. divide 60° by 2, and having 30° in return.

Factor 26r3s + 52r5 – 39r2s4. What is the resulting expression? 13(2r3s + 4r5 – 3r2s4)
13r2s(2r + 4r3 – 3s3)
13r2(2rs + 4r3 – 3s4)
13r2(26r3s + 52r5 – 39r2s4)

Answers

Answer:

Option 3rd is correct

13r^2(2rs+4r^3-3s^4)

Step-by-step explanation:

GCF (Greatest common factor) is the largest number that divides the two number.

Factor 26r^3s+52r^5-39r^2s^4

Find the GCF of the given expression.

GCF of 26r^3s, 52r^5 and 39r^2s^4 is, 13r^2

then;

13r^2(2rs+4r^3-3s^4)

Therefore, the  resulting expression is, 13r^2(2rs+4r^3-3s^4)

Answer:

The Given Expression is

26r^3s + 52r^5 -39r^2s^4\n13* 2* r* r^2 * s + 13* 2* 2* r^2* r^2* r- 13 * 3* r^2* s * s^3\n\n\text{Taking out common factors}\n\n13r^2(2 rs + 2* 2 r^3 -3 s^4)\n\n13r^2(2 r s+ 4 r^3 - 3 s^4)

Option  <strong>13r^2(2 rs + 4 r^3 - 3 s^4) is correct option.

Rewrite the equation 11 x - 5 x 2 + 7 = 6 in standard form and identify a, b, and c

Answers

Answer:

5x^2 - 11x = 1

This is now in standard form, where a = 5, b = -11, and c = 1.

Step-by-step explanation:

To rewrite the equation 11x - 5x^2 + 7 = 6 in standard form, we need to rearrange the terms so that the polynomial is in descending order of degree, with no missing terms. The standard form of a quadratic equation is ax^2 + bx + c = 0, where a, b, and c are constants.

So, let's start by moving the constant term to the right-hand side of the equation:

11x - 5x^2 = 6 - 7

11x - 5x^2 = -1

Next, we can multiply both sides of the equation by -1 to make the coefficient of the x^2 term positive:

5x^2 - 11x = 1

This is now in standard form, where a = 5, b = -11, and c = 1.

What's the nearest tenth of 6.40

Answers

6.4
is your answer   bhivlsFBCKJx
your answer is seven !!!!!!!!

3 is what percent of 5

Answers

Answer: 60%

Step-by-step explanation:

2.5% i’m pretty sure