You have a 1 L container of a gas at 20 C and 1 atm. Without opening the container, how could you tell whether the gas is chlorine or fluorine?a. measure the mass of the gas
b. measure the speed of the gas molecules
c. measure the volume of the container
d. measure the pressure of the gas in the container

Answers

Answer 1

Answer: Without opening the container, a. measure the mass of the gas. Once you get the mass of the gas, you can calculate its density because you already know its volume which has a value of 1 liter. To take the mass of the gas, make sure you don't include the mass of the container. It would be better to measure the container before putting the gas and after putting the gas, and then subtracting the values.

Related Questions

[AZ][B]^4=K[AB2]^2 As this reaction takes place at higher temperatures, it is observed that the equilibrium shifts toward the products. The reaction is ? 1) exothermic 2)endothermic
You heat a piece of iron from 200 to 400 K What happens to the atom's energy of random motion
When double-stranded DNA is heated at neutral pH, which change does not occur? A) The absorption of ultraviolet (260 nm) light increases. B) The covalent N-glycosidic bond between the base and the pentose breaks. C) The helical structure unwinds. D) The hydrogen bonds between A and T break. E) The viscosity of the solution decreases.
How many moles of Cr are in 156 g of the element?a. 1.0 mol b. 3.0 mol c. 6.5 mol d. 156 mol
What mass of oxygen is required to completely react with 2 moles of ch4

Can anyone please help me with this????
Please help me.

Answers

Yoooo j had this for chemistry for mr ng
The answer is 14 72 89
67 54 89 422
13 86 42
I dint have the rest
Explanation bababoey

Yes I will ok I will help you

Use electron transfer or electron shift to identify what is oxidized and what is reduced in each reaction :a) 2Na(s) + Br2(l) ----> 2NaBr(s)
b) H2(g) + Cl2(g) ----> 2HCl(g)
c) 2Li(s) + F2(g) ----> 2LiF(s)
d) S(s) + Cl2(g) ----> SCl2(g)
e)N2(g) + 2O2(g) ----> 2NO2(g)
f) Mg(s) +Cu(NO3)2(aq) = Mg(NO3)2(aq) + Cu(s)

For each reaction above, identify the reducing agent and the oxidizing agent

Answers

Answer :

Oxidation-reduction reaction : It is a type of reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases.

(a) The balanced chemical reactions is,

$2Na(s)+Br_2(l)\rightarrow 2NaBr(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Na\rightarrow Na^(1+)+1e^-$

Reduction : $Br_2+2e^-\rightarrow 2Br^(1-)$

From this we conclude that, 'Na' is oxidized and $'Br_2'$ is reduced in this reaction. The reducing agent is, 'Na' and oxidizing agent is, $'Br_2'$ .

(b) The balanced chemical reactions is,

$H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$

Half reactions of oxidation and reduction are :

Oxidation : $H_2\rightarrow H^(1+)+1e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, $'H_2'$ is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, $'H_2'$ and oxidizing agent is, $'Cl_2'$ .

(c) The balanced chemical reactions is,

$2Li(s)+F_2(g)\rightarrow 2LiF(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Li\rightarrow Li^(1+)+1e^-$

Reduction : $F_2+2e^-\rightarrow 2F^(1-)$

From this we conclude that, 'Li' is oxidized and $'F_2'$ is reduced in this reaction. The reducing agent is, 'Li' and oxidizing agent is, $'F_2'$ .

(d) The balanced chemical reactions is,

$S(s)+Cl_2(g)\rightarrow SCl_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $S\rightarrow S^(2+)+2e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, 'S' is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, 'S' and oxidizing agent is, $'Cl_2'$ .

(e) The balanced chemical reactions is,

$N_2(g)+2O_2(g)\rightarrow 2NO_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $N_2\rightarrow N^(4+)+4e^-$

Reduction : $O_2+4e^-\rightarrow 2O^(2-)$

From this we conclude that, $'N_2'$ is oxidized and $'O_2'$ is reduced in this reaction. The reducing agent is, $'N_2'$ and oxidizing agent is, $'O_2'$ .

(f) The balanced chemical reactions is,

$Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Mg\rightarrow Mg^(2+)+2e^-$

Reduction : $Cu^(2+)+2e^-\rightarrow Cu$

From this we conclude that, $'Mg'$ is oxidized and $'Cu'$ is reduced in this reaction. The reducing agent is, 'Mg' and oxidizing agent is, 'Cu'.

a) Na is oxidised Br is reduced
b) H is oxidised Cl is reduced
c) Li is oxidised F is reduced
d)S is oxidised Cl is reduced
e) N is oxidised O is reduced
f) Mg is oxidised and N is reduced

Remember: Oxidation= loss and Reduction= gains

A student tested a sample of carbon (C) by combining it with water. There was no reaction between the carbon and water. The student concluded that carbon must be a group 18 element, since it was unreactive. State whether you agree with the student's reasoning, and explain why or why not?

Answers

I disagree. Carbon is not a group 18 element. This is incorrect because elements closer to the top of the group are less reactive than those at the bottom of the group. Group 18 elements are noble gases and carbon, a group 14 element, is a non metal.

When KCl dissolves in water ________. a. the K+ ions are attracted to the partial negative charge on the oxygen atom of the water molecule b. the Cl- ions are attracted to the partial negative charge on the oxygen atom of the water molecule c. the K+ ions are attracted to Cl- ions on the KCl crystal d. the K+ ions are attracted to the partial positive charge on the hydrogen atoms of the water molecule e. the Cl- ions are attracted to dissolved K+ ions

Answers

Answer:

a. the K+ ions are attracted to the partial negative charge on the oxygen atom of the water molecule.

Explanation:

The hydrogen atoms on water are partially positive and the oxygen on water is partially negative.

Since unlike charges attract, the oxygen of the water molecules are attracted to the K+ and the hydrogens are attracted to Cl-. the water surrounds the k+ and cl- so that the unlike charges are allowed to be close together.

The proper response to KCl dissolving in water is e. the Cl- ions are attracted to dissolved K+ ions.

The ionic compound KCl separates into the ions K+ and Cl- when it is introduced to water. The partial negative charges on the oxygen atoms in the water molecules are what draw the positive K+ ions to them. At the same time, the partial positive charges on the hydrogen atoms of the water molecules draw the negative Cl- ions towards them. Ion-dipole interactions are the name for this attraction between ions and water molecules.

In the case of KCl, the dissolved K+ ions in the solution selectively attract the Cl- ions. Due to the polar nature of the individual ions, the water molecules form a hydration shell around them.

To know more about water molecules:

brainly.com/question/22298555

#SPJ6

A fruit and oatmeal bar contains 142 nutritional calories. Convert this energy to calories

Answers

Answer is: a fruit and oatmeal bar contains 142000 calories.
A nutritional calorie, or kilocalorie, is equal to 1000 calories.
E = 142 kcal · 1000 cal/kcal.
E = 142 000 cal.
Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
One small calorie is approximately 4.2 joules.
A calorie is a unit of energy.

Final answer:

142 nutritional calories (Cal) are equal to 142,000 calories (cal) since one nutritional Calorie is equivalent to 1000 scientific calories (cal).

Explanation:

To convert 142 nutritional calories to calories, you need to understand the relationship between the two units. In nutrition, when we say 'calories', we actually mean 'kilocalories' (kcal). One nutritional calorie (with an uppercase C) is equal to one kilocalorie (kcal), and one kilocalorie is equivalent to 1000 calories (with lowercase c).

Therefore, 142 nutritional calories (Cal) are equivalent to 142,000 calories (cal).

The conversion formula is as follows:
142 Cal * 1000 = 142,000 cal

How does water help cells keep an even temperature despite temperature changes inthe environment?

Answers

Water has high specific heat. So its temperature will not easy to change. Then can help cells keep an even temperature despite temperature changes in the environment.

Final answer:

Water helps in maintaining temperature in cells due to its high heat capacity. This property allows water to absorb or release a large amount of heat without significantly changing its own temperature. As such, cells can keep a stable temperature despite environmental changes.

Explanation:

Water has a high heat capacity, which is the amount of heat it takes to change its temperature. Due to this high heat capacity, it can absorb or release a large amount of heat without a significant change in its own temperature. This helps cells maintain a relatively stable temperature and protect biological processes. For instance, when the external environment is hot, cells can avoid getting overheated as the water in them absorbs and distributes the heat evenly. Similarly, if the environment is cold, the water in the cells releases heat which helps to keep them warm. Hence, regardless of the temperature changes in the environment, the high heat capacity of water aids cells in preserving a relatively even temperature.

Learn more about Water in Cells here:

brainly.com/question/32862677

#SPJ2

Other Questions

What energy resource can be used instead of fossil fuel

What describes a change in velocity?

Juliet is using a paper towel to clean up a juice spill. The liquid sticks to the paper towel because of _____.adhesion cohesion specific heat a neutral pH