Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence
here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.
Answer:
626
Step-by-step explanation:
So 62 fewer right so 688 combined- 62 cheeseburger =626 hamburger
1)a1 = -4, d= -9, n=20
2)a1 =20, d=4, n=81
3)a12 for 8,3,-2,...
Answers
A)340
B)-47
C)-175
D)94
*PLEASE EXPLAIN*
Answer: 8 11/12
Step-by-step explanation:
3 1/6+ 5 3/4
19/6+ 23/4
38/12+69/12
107/12
8 11/12
To solve this problem, you must understand what is the Common Denominator Rule:
The Common Denominator rule is when you use the common factors of the denominators to make them the same number. This will allow you to add and subtract fractions.
First, let’s put these two mixed fractions as improper fractions. Learn more about making that conversion here: brainly.com/question/35061276
Now that you have your fractions, look at the denominators: 6 and 4.
A common factor between 4 and 6 is the number 12. Multiply the denominators and numerators of each fraction by the number that will turn the denominator into 12:
=
=
Now that both factions have the same number in the denominator, you can add them together!
*be aware of the negative sign*
Your answer should be: