Recall that a test is statistically significant at a particular significance level if the null hypothesis is rejected when alpha is set at this value. Suppose a medical researcher conducts a statistical test of hypotheses and finds there is statistically significant evidence for the alternative hypothesis at a significance level alpha = 0.05. The researcher may conclude that...a) the test would also be statistically significant at level alpha = 0.01b) the test would also be statistically significant at level alpha = 0.10c) both of the above are trued) none of the above are true

Answer:

A

C

D

Step-by-step explanation:

Answer:

2x+2y=52

x*y=120

Step-by-step explanation:

Final answer:

The possible lengths of a side of the rectangle are 22, 21, 20, 19, 18, 17, 16 feet.

Explanation:

To find the possible lengths of a side of the rectangle, let's use the formula for the perimeter of a rectangle, which is 2(length + width). We can set up an equation using the given information:

2(length + width) = 52

Dividing both sides by 2, we get:

length + width = 26

Now, to find the possible lengths, we need to consider the area. The formula for the area of a rectangle is length x width. We are given that the area is not to exceed 120 square feet, so we can set up the inequality:

length x width <= 120

Using the relationship length + width = 26, we can substitute length = 26 - width into the inequality:

(26 - width) x width <= 120

Simplifying the inequality, we get:

-width^2 + 26width - 120 <= 0

Now, we can solve this quadratic inequality to find the range of possible widths. Once we have the widths, we can substitute them back into the equation length + width = 26 to find the corresponding lengths.

By solving the quadratic inequality, we find that the possible widths are 4 <= width <= 10. Substituting these widths back into the equation length + width = 26, we get the corresponding lengths:

If width = 4, then length = 22

If width = 5, then length = 21

If width = 6, then length = 20

If width = 7, then length = 19

If width = 8, then length = 18

If width = 9, then length = 17

If width = 10, then length = 16

The possible lengths of a side of the rectangle are {22, 21, 20, 19, 18, 17, 16} feet.

Learn more about rectangle side lengths here:

brainly.com/question/16605856

#SPJ3

Answer:

7 ; 19 ; 8% ; 28%

Step-by-step explanation:

Given the data:

791 542 671 672 555 582 616 961 639

691 648 967 959 826 573 598 790 954

711 515 649 960 949 802 507

How many of the 13-year-olds sent at least 600 but less than 700 text messages? = 7

c-2. How many sent less than 900 text messages? = (7 + 7 + 3 + 2) = 19

d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? =0.08 × 100 = 8% (from relative frequency)

d-5. What percent of the 13-year-olds sent less than 600 text messages?  0.28 × 100 = 28% (from relative frequency)

Final answer:

By sorting text messages into classes, we can get the frequency distribution. From there, we can determine the relative and cumulative frequencies. Finally, we can examine how many students sent texts within certain ranges and express these as percentages.

Explanation:

To answer this question, let's first classify the amount of text messages sent by each of the 25 13-year-olds into groups or classes of 100. Then we count the frequencies, or how many text messages fall into each class. This helps us construct the frequency distribution.

The classes are: 500-600, 600-700, 700-800, 800-900, and 900-1000.

Next, we calculate the relative frequency by dividing the frequency of each class by the total number of students. We round each relative frequency to 2 decimal places.

To calculate cumulative frequency, we keep an ongoing total of frequencies as we move up the classes. The cumulative relative frequency is computed similarly but applied to the relative frequencies.

In the last part, we determine how many 13-year-olds sent at least a certain number of texts but less than another number, and convert these to percentages.

Learn more about Frequency Distribution here:

brainly.com/question/32438359

#SPJ3

Answer with explanation:

Average Height of tallest Building in San Francisco

Average Height of tallest Building in Los Angeles

→→Difference between Height of tallest Building in Los Angeles and  Height of tallest Building in San Francisco

               =233.9-197.8

               =36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

 |260-197.8|=62.2

 |237-197.8|=39.2

 |212-197.8|=14.2

 |197 -197.8|= 0.8

 |184 -197.8|=13.8

 |183-197.8|=14.8

 |183-197.8|= 14.8

 |175-197.8|=22.8

 |174-197.8|=23.8

 |173 -197.8|=24.8

Average of these numbers

Mean absolute deviation=23.12

Answer:

1st -36.1 meters or more

2nd -23.12

Step-by-step explanation:

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

= 79

Standard deviation,

= 3.5

Now,

⇒

⇒

So,

=

=

=

Answer:

Step-by-step explanation:

a( c + b ) = d

Divide both sides by a

That's

Move b to the right side of the equation to make c stand alone

We have the final answer as

Hope this helps you

Answer:

c = - b.

Step-by-step explanation:

a(c + b) = d

(c + b) = d / a

c + b =

c = - b.

Hope this helps!