Drag each statement to the correct location on the chart. Classify the events as being a cause or an effect of pollution. urbanization oil spill smog desertification deforestation leaky landfill contaminated water

Answers

Answer 1
Answer:

Answer:

Urbanization, oil spill, leaky landfill and deforestation are causes of pollution while desertification, smog, contaminated water are the effects of pollution.

Explanation:

Urbanization is generally associated with an increase in the number of industries. The waste materials in different forms from the factories pollute air, water and soil.

The effluents from factories released into rivers cause water pollution and harm the aquatic life. Water contaminated by industrial waste becomes unsuitable for drinking. Forests play a major role in controlling the amount of carbon dioxide in the atmosphere.

Deforestation increases the amount of carbon dioxide in the atmosphere.  Oil spills usually occur in oceans and seas and it causes water pollution and threatens aquatic life.

Answer 2
Answer:

Answer:

Cause

industrial wastes dumped into rivers

oil spilled on land mixes with runoff

sewage dumped into rivers

Effect

destroyed natural habitats

fish die-off

spread of disease

Explanation:

plato


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Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods. Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane.

Answers

The moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is 0.0636 \;\rm kg-m^(2).

Given data:

The mass of each sphere is, m = 0.200 \;\rm kg.

Length of side of square is, L = 0.400 \;\rm m.

The expression for the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is,

I = 4 mR^(2)

Here,

R is the distance between center of the square and the sphere. And its value is,

R =(1)/(2)\sqrt{L^(2)+L^(2)}\nR =(1)/(2)\sqrt{0.400^(2)+0.400^(2)}\nR = 0.282 \;\rm m

Then, moment of inertia is,

I = 4 mR^(2)\nI = 4 * 0.200 * 0.282^(2)\nI = 0.0636 \;\rm kg-m^(2)

Thus, the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is 0.0636 \;\rm kg-m^(2).

Learn more about moment of inertia here:

brainly.com/question/2176093?referrer=searchResults

The moment of inertia of the system about an axis through the center of the square, perpendicular to the plane is 0.064 kg.m²

\texttt{ }

Further explanation

Let's recall Moment of Inertia formula as follows:

\boxed{ I = m R^2 }

where:

I = moment of inertia

m = mass of object

R = distance between the object and the axis of rotation.

Given:

mass of sphere = m = 0.200 kg

length of side = x = 0.400 m

Asked:

net moment of inertia = ΣI = ?

Solution:

Let's ilustrate this question as shown in the attachment.

Firstly , let's find distance between center of the square and the sphere:

R = (1)/(2) √(x^2+x^2)

R = (1)/(2) √(2x^2)

R = (1)/(2)√(2) x

R = (1)/(2) √(2) (0.400)

\boxed{R = 0.200√(2) \texttt{ m}}

\texttt{ }

Next , we could find total moment of inertia as follows:

\Sigma I = mR^2 + mR^2 + mR^2 + mR^2

\Sigma I = 4mR^2

\Sigma I = 4(0.200)(0.200√(2))^2

\boxed{\Sigma I = 0.064 \texttt{ kgm}^2}

\texttt{ }

Learn more

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Chapter: Rotational Dynamics

15 POINTS! What are some differences and similarities between Electromagnetic and Mechanical waves?

Answers

Elecromagnetic waves can travel through a vacuum, but a mechanical wave cannot.Mechanical waves can only exist in a medium, such as air or water. Electromagneticwaves behave like waves and particles, but mechanical waves only behavelike waves.

If you are driving 128.4 km/h along a straight road and you look down for 3.0s, how far do you travel during this inattentive period?

Answers

Answer:

107 m

Explanation:

Convert km/h to m/s:

128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s

Distance = rate × time

d = 35.67 m/s × 3.0 s

d = 107 m

PLEASE HELP!!!!!!suppose that mA is 8.1 kg and mBis 6.5kg. The distance between their centers is 0.5o m.Calculate the force of attraction between these two bodies?

Answers



Somewhere in your book or your notes, you must have met the formula for the
gravitational attraction between two bodies.  If you can go back and find it, you
only need to plug your numbers into that formula, and out will pop the answer.

Formula:                            Force = G (mA x mB) / (distance)²

If everything is in SI units, then        G = 6.67 x10⁻¹¹ newton-meter² / kilogram²

You said that
                         mA = 8.1 kg
                         mB = 6.5 kg
                 distance = 0.5 m .

   Force = (6.67 x 10⁻¹¹ nt-m²/kg²) (8.1kg x 6.5kg / (0.5m)² =

                (6.67 x 10⁻¹¹ nt-m²/kg²)    ( 52.65 kg² ) / (0.25 m²) =

                     1.4047 x 10⁻⁸ newtons .

That's roughly    5.052 x 10⁻⁸ ounce .  (5% of one micro-ounce)


What do you need to know to describe velocity?

Answers

Is the speed given with a direction
Velocity is referring to the speed and direction of something.

1.A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in
20 s.
a) What is the average acceleration of the car?
b) What distance does it travel in this time?

Answers

  1. The average acceleration of the car is 1.4 m / s^2.
  2. The distance travel at this time is 560 m.

Explanation:

Average acceleration is defined as the rate of change of velocity to the rate of change of period. Change of velocity refers to the difference between final velocity and initial velocity. The unit of acceleration is meter/sec/sec (or)   m s^2.

Avg Acceleration=(Final velocity - Initial velocity) /(Final time - Initial time)

a. To find the average acceleration of the car, (initial velocity and initial time   is 0, the final velocity is 28 m/s, final time = 20 s)

               Avg acceleration of the car = (28 - 0) / (20 - 0)

                                                              = 28 / 20 = 1.4 m / s^2.

b. The distance traveled is given by the product of speed and time

     Distance traveled = Speed * Time

      The Distance traveled by the car = 28 * 20 = 560 m.

Final answer:

By applying basic physics formulas, the car's average acceleration can be determined as 1.4 m/s², and the distance it travels in 20 seconds is 280 meters.

Explanation:

To answer this question, you'll need to apply basic physics formulas. Let's go step by step:

a) What is the average acceleration of the car?

Acceleration is defined as the rate of change of velocity per unit of time. The formula is Acceleration = (Final speed - Initial speed) / Time. Here, the initial speed is 0 (because the car is starting from rest), final speed is 28 m/s and time is 20 s.

So, Acceleration = (28 m/s - 0) / 20 s = 1.4 m/s². That's your answer for part a.

b) What distance does it travel in this time?

The distance traveled by the car can be found using the formula of linear motion: Distance = Initial speed x Time + 0.5 x Acceleration x Time². Since the car starts from rest, the initial speed is zero, and this component of the formula will be zero.

So, Distance = 0 + 0.5 x 1.4 m/s² x (20 s)² = 280 m. So, the car travels 280 meters in that time.

Learn more about Physics Acceleration and Distance here:

brainly.com/question/32817533

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