GEOGRAPHY COLLEGE

If all the energy from a 103 W light bulb is emitted at 590.0 nm, what is the energy of each photon in Joule? Planck’s constant is 6.6 x 10-34 J*s and the speed of light is 3.0 x 108 m/s.

Answers

Answer 1

Answer:

Answer:

Energy of each photon is given by $0.0335* 10^(-17)j$

Explanation:

We have given wavelength of light $\lambda =590nm=590* 10^(-9)m$

Speed of light $c=3* 10^8m/sec$

Plank's constant $h=6.6* 10^(-34)j-s$

We know that energy of photon is given by $E=h\nu =(hc)/(\lambda )$

So energy is given by

$E=h\nu =(hc)/(\lambda )=(6.6* 10^(-34)* 3* 10^8)/(590* 10^(-9))=0.0335* 10^(-17)j$

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Answers

Answer:

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Answers

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THERE IS MORE THAN ONE ANSWER SO PLS CHOOSE TWO ANSWERS

Answers

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