Mary walked north from her home to Sheila's home, which is 4.0 kilometers away. Then she turned right and walked another 3.0 kilometers to the supermarket, which is 5.0 kilometers from her own home. She walked the total distance in 1.5 hours. What were her average speed and average velocity?

Answers

Answer 1

Answer: It would be 5.666667 km per hour.

Answer 2

Answer: well her speed and velocity are the same 8 kilometers per hour

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Suppose a spacecraft orbits the moon in a very low, circular orbit, just a few hundred meters above the lunar surface. The moon has a diameter of 3500 km, and the free-fall acceleration at the surface is 1.6m/s2. How fast is this spacecraft moving? A. 53 m/s
B. 75 m/s
C. 1700 m/s
D. 2400 m/s

Answers

Spacecraft will be moving in 1700 m/s.

Option C

Explanation:

The diameter of the moon is 3500 km and the free fall acceleration at the surface is given as $1.6\ \mathrm{m} / \mathrm{s}^2$

The radius will be half of the diameter of the moon that can be written as:

$r_{\text {moon }}=1.75 * 10^(6)$

By the application of the equation for orbit speed, we get

$\begin{aligned}&v_{\text {orbit}}=√(r * q)\n&v_{\text {orbit}}=\sqrt{\left(1.75 * 10^(6)\right) *\left(1.6\ \mathrm{m} / \mathrm{s}^(2)\right)}\n&v_{\text {orbit}}=1700\ \mathrm{m} / \mathrm{s}\end{aligned}$

Final answer:

The spacecraft is moving at approximately 1700 m/s.

Explanation:

The speed of the spacecraft can be calculated using the formula for the orbital speed of an object:

V = sqrt((G * M) / r)

Where V is the velocity, G is the gravitational constant (approximately 6.67 x 10^-11 N m²/kg²), M is the mass of the moon (approximately 7.35 x 10^22 kg), and r is the radius of the moon plus the altitude of the spacecraft.

Plugging in the known values, we have:

V = sqrt((6.67 x 10^-11 N m²/kg²) * (7.35 x 10^22 kg) / (3.5 x 10^6 m + 200 m))

Calculating the square root of this expression gives us approximately 1700 m/s.

Learn more about Orbital velocity here:

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Sally is training for the 1,000-meter running race at her school. Her goal is to place third or better. How can Sally determine if she is making progress toward her goal?

Answers

She can monitor her practice run times to see if they are decreasing.

Answer: a

Explanation:

What is this equation for?

Answers

That's the equation for the efficiency of any machine or other system that you use to change energy from one form to another. It says that the efficiency of that device is equal to the work or energy that comes out of it divided by the work or energy that you put into it.

An object traveling in a straight line accelerates. What will definitely happen due to the acceleration?The distance traveled in a certain time will increase.
The displacement covered in a certain time will decrease.
The speed of the object will stay constant.
The velocity of the object will change.

Answers

"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning. So . . .

-- The distance traveled in a certain time may increase or decrease.

-- The displacement covered in a certain time may increase or decrease.

-- The speed of the object may increase or decrease.

-- The velocity of the object (speed/direction) will change.

A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the gas is raised to 235° Kelvin what's the new pressure of the gas?

Answers

Given:

P1 = 400 kPa
T1 = 110 K

T2 = 235K

Required:

Solution:

Apply Gay-Lussac’s law where P/T = constant

P1/T1 = P2/T2

P2 = T2P1/T1

P2 = (235K)(400kPa) / (110K)

P2 = 855 kPa

What is the approximate weight of a 20-kg cannonball on earth?

Answers

The weight of an object is taken to be the force on the object due to gravity. The weight ( W ) is the product of the mass ( m ) of the object and the magnitude of the gravitational acceleration ( g ).
On Earth: g = 9.81 m/s²
m = 20 kg
W = m · g = 20 kg · 9.81 m/s² = 196.2 N

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